Sir please dont stop uploading, your videos are very helpful and we are vey grateful to have a wonderful teacher like you whose concepts are crisp clear sharing his knowledge with us
i dont mean to be offtopic but does any of you know of a method to get back into an Instagram account..? I was dumb lost the password. I would appreciate any tricks you can give me!
I don't understand this concept so sir you explain very simple i am also learning about this topic so let me full ip ADDRESSING concept clear upload more video in this topic
your explanation of fragmentation is confusing, as you divide by 8 each time , however you should divide the length by 8 only if it was provided to bit, since all we're doing here is converting to bytes it would be better to divide the whole length by 8 once and then use that to offset regularly (the offset would be where the last fragment was cut) and if the length was given in bytes then don't divide by 8 You present it as just the method to do offsets otherwise, great video, really helpful, thanks a lot
There are two parts I do not understand well so can someone please explain in more detail: 1) At 2:25 the lecturer said if "the value in the header length field is 5, it refers that the length of IPv4 header is 5 words. One word in IPv4 is 4-byte in length. Therefore the total length of the IPv4 header will be 5 x 4 = 20-bytes." I'm not sure what is meant by "word" and how he came up with the length of 5 words to begin with, instead of say, 2 words or 3 words. 2) At 4:38 the lecturer calculated the theoretical length of IP datagram using datagram length of 16-bit: 2^16-1=65535 bytes. How come this calculation is different from calculating the total length of IPv4 datagram header using header length of 4-bit from earlier in the video (where the maximum header length was 2^4 -1=15, then 15 x 4 = 60 bytes max)? Doesn't the IP datagram length calculation need to take that 65535 and multiply by 4 as well? I feel like I am misunderstanding something along the way.
1) A 'word' is fancy way say (32 bits or 4bytes) , this is row length => 1) row 4+15+8+16 = 32bit 2) row 16+3+13 = 32bit 3) row 8+8+16 = 32 bit 4) row source IP = 32 bit 5) row destination IP = 32bit Above 4 row is mandatory field for IP4 header , every packet should have those field minimum. So total bits = 5 × 32 = 160bits =20 bytes Minimum, If we add options so the total length go up maximum 60 bytes by using *header length* . 2) we are not using *header length* to calculate packet length, instead we are using *datagram length* field to calculate total packet length it is 16 bits , therefore 2^16 = 65535 bytes.
@@salehakhaton6027 you mention 65,535 as bytes. But is it not instead the decimal equivalent able to be created using 16 bits? Because when someone says 32 bit that implies that they are also saying 4 bytes. I thought the largest decimal number able to be represented by 16 bits was 65,535. Pls correct me if I’m wrong.
Sir please dont stop uploading, your videos are very helpful and we are vey grateful to have a wonderful teacher like you whose concepts are crisp clear sharing his knowledge with us
Learnt something ? ...Very less people are born with such talent sir . You way of explaining should take you to next level .
Amazing content! Worth 5 years of Engineering
at the end, "if u learnt something from this..." oh man, we learnt a lot. Thanku for this effort
i dont mean to be offtopic but does any of you know of a method to get back into an Instagram account..?
I was dumb lost the password. I would appreciate any tricks you can give me!
@@majorkai4960 well the basic should be using your own mail address that should be enough if you lost your IG acc
I don't understand this concept so sir you explain very simple i am also learning about this topic so let me full ip ADDRESSING concept clear upload more video in this topic
I just don't have words for your crystal clear explanation, you have done a fantastic job.
your explanation of fragmentation is confusing, as you divide by 8 each time , however you should divide the length by 8 only if it was provided to bit, since all we're doing here is converting to bytes
it would be better to divide the whole length by 8 once and then use that to offset regularly (the offset would be where the last fragment was cut)
and if the length was given in bytes then don't divide by 8
You present it as just the method to do offsets
otherwise, great video, really helpful, thanks a lot
Sir ..You are taking huge time to upload
You're the best. I was looking for your video to understand IP Header. Thanks for teaching us and lots of respects.
i couldn't be happier, best explanation i have ever met
very good content sir. learnt a lot. please do videos on TCP, UDP and MAC header structure and its explanation sir.
Thank you for the video, Kindly share the link for the notes, need to expand brain further
Awesome explanation.. please do video for ipv6 also
very nice explanation sir
excellent explanation keep it up (high thumb)
Congratulations for 100k subs buddy and upload tcp and udp Asap 😃
REALLY NICE EXPLANATION
Awesome..With animated..looking moreee from u💯💯💯💯
Presentation was super
Orr videos kro upload. That's helpful man....
Very useful sir, Thank you
Osama explanation sir
its amazing explaination bro
Very Well Explained
Excellent Explain
still a legend
There are two parts I do not understand well so can someone please explain in more detail:
1) At 2:25 the lecturer said if "the value in the header length field is 5, it refers that the length of IPv4 header is 5 words. One word in IPv4 is 4-byte in length. Therefore the total length of the IPv4 header will be 5 x 4 = 20-bytes." I'm not sure what is meant by "word" and how he came up with the length of 5 words to begin with, instead of say, 2 words or 3 words.
2) At 4:38 the lecturer calculated the theoretical length of IP datagram using datagram length of 16-bit: 2^16-1=65535 bytes. How come this calculation is different from calculating the total length of IPv4 datagram header using header length of 4-bit from earlier in the video (where the maximum header length was 2^4 -1=15, then 15 x 4 = 60 bytes max)? Doesn't the IP datagram length calculation need to take that 65535 and multiply by 4 as well? I feel like I am misunderstanding something along the way.
U got it???
1) A 'word' is fancy way say (32 bits or 4bytes) , this is row length =>
1) row 4+15+8+16 = 32bit
2) row 16+3+13 = 32bit
3) row 8+8+16 = 32 bit
4) row source IP = 32 bit
5) row destination IP = 32bit
Above 4 row is mandatory field for IP4 header , every packet should have those field minimum. So total bits = 5 × 32 = 160bits =20 bytes Minimum,
If we add options so the total length go up maximum 60 bytes by using *header length* .
2) we are not using *header length* to calculate packet length, instead we are using *datagram length* field to calculate total packet length it is 16 bits , therefore 2^16 = 65535 bytes.
@@salehakhaton6027 you mention 65,535 as bytes. But is it not instead the decimal equivalent able to be created using 16 bits? Because when someone says 32 bit that implies that they are also saying 4 bytes. I thought the largest decimal number able to be represented by 16 bits was 65,535. Pls correct me if I’m wrong.
Thank you
Amazing !!!!you just explained everything
@ 6:37 Shouldn't the do not fragment IP datagram D:1 always set M bit to 0 ?
Excellent 🥰
I am really interested on your tutor !
Well explained!!!
plz create a video about fiber
Superb
Nice video
Bro please do more videos💞
Excellent Job
@5:33 Why not use maximum Ethernet frame 1,500 byte, meaning IP1 1500, IP2 1500, IP3 980 ?
That’s my question too
I think in addition of 1400 + 1400 + 1180 = 3980 meaning 4000 - 20 of IHL, note each frame allows up to 1500 i think
Excellent ! Loved it ❤️
Awesome! Video
can anyone explain the 2^16 -1 concept?? and the 13 bit fragmentation offset?
Thank You Very Much!!
Could you please talk about kernel, jump host..
bhai Presentation ke leye kon sa software use krte hoe
GG zaim
Please upload Vlan Tutorial videos
We need Ipv6 also
2:30 Isn't a word 16 bits?? A word is 2 bytes, not 4
Notes
Too advanced for me 😞
please make video on TCP/IP Model
How can i change my ip adress on pc and mobile to any country's ip without any vpn application?
Its impossible
hello! hello can you hear me as i scream your name ,tt make video on subnet mask and how to distinguished it 😮😮😮
Poor pronounication, plz try to improve. Class was good
I just can’t pass your accent…
Thank You
@5:33 Why not use maximum Ethernet frame 1,500 byte, meaning IP1 1500, IP2 1500, IP3 980 ?