Ozonolysis
HTML-код
- Опубликовано: 26 авг 2024
- Ozonolysis? Ozone is in the sky, right? That thing that shields us from UV light? That's right friend, but ozone is also used in the lab to cleave carbon-carbon double bonds. Check it out if you don't believe me.
Watch the whole Organic Chemistry playlist: bit.ly/ProfDave...
General Chemistry Tutorials: bit.ly/ProfDave...
Biochemistry Tutorials: bit.ly/ProfDave...
Biology Tutorials: bit.ly/ProfDaveBio
Classical Physics Tutorials: bit.ly/ProfDave...
Modern Physics Tutorials: bit.ly/ProfDave...
Mathematics Tutorials: bit.ly/ProfDave...
EMAIL► ProfessorDaveExplains@gmail.com
PATREON► / professordaveexplains
Check out "Is This Wi-Fi Organic?", my book on disarming pseudoscience!
Amazon: amzn.to/2HtNpVH
Bookshop: bit.ly/39cKADM
Barnes and Noble: bit.ly/3pUjmrn
Book Depository: bit.ly/3aOVDlT
I'm shocked. After hours of trying to understand it, I get it only in few minutes! Thanks professor Dave! You are amazing
so under-appreciated...
+RadicalWizard i know, right?!? spread the word my friend!
Amazing explanation, I was able to wrap my head around this in only 3 minutes! Your videos are the reason I have an A in orgo! I can't thank you enough!!!!
you're the best tutor in the world.......!
his videos are very short such that they save time and easily understandable
How many peoples like the intro😀
I really love your channel… NO ONE can explain like you do!
God I love that Professor Dave chest hair...
That’s gay
WTF!!!
@@sebastianbancroft7184 That's stupid.
Wonderful Great !!!!!!
You saved my CAT,you didn't name them
Your teaching is as good as your hair..... Awesome man.....
i love your way of explanation
This was so simple and useful! Thanks Prof!
thanks professor dave ! your videos are awesome !! props from germany
you are saving me dude, thanks a lot
very helpful as usual :)
thank you chemistry jesus
By ozonolysis of C10H16, gives 2 diketones C4H6O2 and C6H10O2. What is the compound C10H16? and what are the 2 diketones that are formed?
Good
hahahahaha, my chinese prof spent 30 minutes teaching ozonolysis, i gat the concept in 1 minute, thanks prof
honestly same lol, we live in a crazy world bro...
Thank you so much :D
damn, that last ex. about the cyclic structure, mic drop right there. way to end the video. LOL
Guys, guys! It's Professor Dave! He wants to tell us some things about ozonolysis ...
Professor...could you please tell how the ozonolysis of bicyclo alkenes would be carried..
You are amazing
How did you numbered the carbon atoms in that compound?
I don't know that rule.
And thank U so much for these awesome videos❤️
There is no rule. He's arbitarily assigning a number to each carbon to keep track of which carbons are involved in the double bond. Granted, he does start with the non-ring carbon and continues in one direction, but really there is no rule here. It's not IUPAC naming, so you don't need to worry about misnumbering a carbon.
The numbering is done wrong at 2:20
That's not IUPAC numbering, it's just bookkeeping for mechanistic purposes.
How do I determine the reactant for oxidative cleavage if my product is only one ketone?
Hi Dave, just wondering what the function is of the workup with CH2Cl2 and Zn, HOAc? I am also a little confused about which workups/solvents will or will not contribute to the atoms of the final molecule.
very good question! i don't totally recall, and i've actually never done the reaction in the lab. i believe zinc acts as a reducing agent somehow. DCM is just solvent though. i think after ozonolysis the substrate is still one molecule all connected, an "ozonide", and a reducing agent cleaves it to give two separate carbonyls.
Ok thanks. It becomes difficult to predict the end product for me when there are all these different solvents and workups that sometimes change the effect of the "root" reaction. I am writing the DAT on the Sept. 20th so I'm trying to gather any tricks or quick ways to differentiate these details.
Life saver
are you the reincarnation of Markovinkov??!!
bless your soul
respect from india
thanks for the help , its really precious to me ! Any ideas about the products of this ozonolysis : CH2=CH-CH2-CH2-CH=CH2 ?
just split apart any double bond and tack on carbonyls! so starting from the left you would get formaldehyde, the four-carbon dialdehyde, and another formaldehyde.
thanks a lot :)
i think u did something wrong while counting the Moleculs,because we start counting when the double bond begins and in the second Molecul the Aldehyd has the priority as a functional Group morethan the Keton Group so we count from right to left,isn´t that true?
+ons laabidi oh those numbers are not IUPAC labeling numbers, they are just bookkeeping numbers to make sure everyone understands which carbon on the starting material corresponds to which carbon on the product. no correlation with nomenclature at all.
you're genious
Thanks sir. May GOD bless u .Thanks once again 😊😊.
Awesome👌
Is there a reaction that allows the formation of ozone, besides occurring naturally and with ozonizer devices?
If there is, can I get your explanation or get a link for the explanation.
was this an assignment lol?
he knows a lot about science stuff... professor dave explains.... poooiii 😊😘😘
thanks you man... i studying through your videos nowadays...
Can you count into a ring struture?
like number your carbons or something? sure!
how does ozonoloysis of o-xylene take place
hmm, same as any other ozonolysis i think!
you didn't explain the mechanism involved
it's a tricky one!
please add example reaction for your explain.
what do you mean? there's like ten in there.
❤️❤️❤️
can u plz help me with cyclic compound having two double bond plz plz
it's not different! pull apart the pi bonds and replace those carbons with carbonyls.
i love youuuuuuuu
👏🏻👏🏻👏🏻👏🏻