A wonderful exponential equation || An international Mathematics !
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- Опубликовано: 3 окт 2024
- Let's solve this nice #exponentialequation 7^x+3 +7^x+5=50
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Thanks for the nice solution 👍
Welcome
I would start withh rewritung 7^(x+5) to 7^(2+(x+3)):
7^(x+3)+7^(x+5)=50
7^(x+3)+7^(2+(x+3))=50
7^(x+3)+7^2*7^(x+3)=50
7^(x+3)*(1+7^2)=50
7^(x+3)*(49+1)=50
7^/x+3)*50=50
7^(x+3)=1
7^(x+3)=7^0
x+3=0
x=--3
Very good 👍