3^(3x)-3^x=24 3^(3x)-3^x=27-3 3^(3x)-3^x=3^3-3^1 3x-x=3-1 2x=2 x=1it will be easier, if something is not clear, or not correct, throw the question in the comments
Again a bunch of math for nothing. Use some deductive reasoning. 3^3X has to be greater than 24. Powers of 3: 1, 3, 9, 27, etc. 27 > 24. 27 =3^3. 27-24 =3 Therefore: X=1
@@dolfindino7430 The best solution is the one that takes the least amount of work. Knowing the powers of numbers is not trial and error. Then again everyone is entitled to their opinion.
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3^(3x)-3^x=24
3^(3x)-3^x=27-3
3^(3x)-3^x=3^3-3^1
3x-x=3-1
2x=2
x=1it will be easier, if something is not clear, or not correct, throw the question in the comments
1
Unity
Easy
3³x = (3^x)³
(3^x)³ - 3^x = 24
Let 3^x = d
d³ - d = 24
d³ - d - 24 = 0
(d²+3d+8)(d-3)=0
d=3
3^x = 3¹
X=1
Or
d²+3d+8=0
[Using the quadratic formula]
d. = 0.5 x [-3 + i(sq.rt 23)]
3^x = 0.5[-3 + i(sq.rt 23)]
x log 3 = log 0.5[-3 + i(sq.rt 23)]
x = log 0.5[-3 + i(sq.rt 23)]/log 3
&
d.. = 0.5[-3 - i(sq.rt 23)]
3^x = 0.5[-3 - i(sq.rt 23)]
x log 3 = log 0.5[-3 - i(sq. rt 23)]
x = log 0.5[-3 - i(sq.rt 23)]/log 3
Answers:
▪︎ x=1
▪︎x=log 0.5[-3+i(sq.rt 23)]/log 3
▪︎x=log 0.5[-3-i(sq.rt 23)]/log 3
👍👍👍
Again a bunch of math for nothing. Use some deductive reasoning. 3^3X has to be greater than 24. Powers of 3: 1, 3, 9, 27, etc. 27 > 24. 27 =3^3. 27-24 =3 Therefore: X=1
This is trial and error method
It is not best solution and we use this only when proper method is not present🦎
@@dolfindino7430 The best solution is the one that takes the least amount of work. Knowing the powers of numbers is not trial and error. Then again everyone is entitled to their opinion.