Sir when sigma 1 less than sigma y then how sigma 2 exceed sigma y because sigma 2 is minor principal stress .. When sigma 1 i.e major principal stress less than sigma y
You prolly dont care at all but does anybody know a way to log back into an Instagram account..? I stupidly lost my password. I appreciate any tricks you can give me!
@Daxton Elliot i really appreciate your reply. I found the site thru google and I'm in the hacking process atm. Seems to take quite some time so I will get back to you later with my results.
A machine element is subjected to the following bi axial sate of stress sigma x=80 Mpa sigma y =20 Mpa Tau xy=40 Mpa Share strength of materials is 100 Mpa. find the factors of safety as per Trecsca Maximum share stress theory. a) 1 b 2 c) 3 can you tell me the correct ans please sir. The correct Ans is 2. but while i solve get 1. can you confirm it please?
Thank you so much sir for giving such a wonderful concepts 👌
Accha phdate ho sir aap ❤❤
You don't have any idea that what kind of noble work you are doing ..... Such a sweet person you are..... ❤️
😂
Very very easy to understand when we are taught by someone like you.. Amazing sir
Crystal clear ho gya sir 🙏
Your explanation is very mive sir🙏🙏🙏🙏. Thanku sir for such great explanation.
Today was my university because of your clear explanation I was able to attend 13-marks.Thank you so much sir
Good luck dear
Very very easy way to understand sir 🙏
Mind blowing lecture👌👌👌
Superb lecture sir.. explanation is crystal clear...
Superb sir ji.
Upload next video.
Bahut achaa lecture sir ....thank you sir
Very clear understanding
Great sir 🙏🏼🙏🏼👍
Thanks you sir...lot of thanks...very nice session for me...I hope this session help for all mechanical Compitater. waiting for next session sir...🙏
Nice video and good explanation with easy way 😊😊
Very very thans for the this video
U r best teacher ever...sir
Good lecture sir and I'm waiting next lecture
Thank you so much sir for this videk
bhtreeéeeeeeeeeen hogya Sir gi
Thank u sir ....realy really thank u sir.....
Great lecture sir 👍🙏🏼
This was amazing lecture sir
Aj exam hain sir abhi dekh raha hu exam 11:30 se hain ...abhi samajlia sir aapki wajeshe sir thank you so much sir ☺️🙏🏻
Thanku sir ❤️
excellent lecture
Thank you so very much sir
dedication sir
Sir 2 part vi upload kare very easy way to understand thanks sir 🙏 upload second and other lecture
I am waiting for next lecture of theories of failure..
Nice lecture sir
Thanks sir
Sir remaining hydraulic machines ke lectr pr ek video bna do like Hydraluic press , hydraulic ram ,hydraulic intensifier etc
Sir bohut achha hua
Kal kab hoga is lecture ki remaining part
Thanks Sir ji
Keep it free lecture further 🙏
I hope u upload next lect ASAP
I am eagerly waiting
It would be grat help sir 🙏🏼🙏🏼
I appreciate ur work ty so much sir
We owe u lot
Good lecture sir, will the next lecture on further theories of failure will be available on playlist or will it be for paid students only?
Sir when sigma 1 less than sigma y then how sigma 2 exceed sigma y because sigma 2 is minor principal stress .. When sigma 1 i.e major principal stress less than sigma y
Very nice session sir....Enjoyed a lot,,,, thank you so much sir🙏.....Eagerly waiting for the next lecture😊
You prolly dont care at all but does anybody know a way to log back into an Instagram account..?
I stupidly lost my password. I appreciate any tricks you can give me!
@Juelz Tadeo instablaster ;)
@Daxton Elliot i really appreciate your reply. I found the site thru google and I'm in the hacking process atm.
Seems to take quite some time so I will get back to you later with my results.
@Daxton Elliot It did the trick and I finally got access to my account again. I'm so happy!
Thanks so much you really help me out!
@Juelz Tadeo No problem =)
Thanks sir . You should upload next lecture.
Thanks so much sir.sir spring ke lecture bhi upload kar digiye.
Thanks you sir
Sir real gas equation ko bhi samjhana
Clearly understand
Nice sir
Thank u sir
Sir iska 2nd lecture kha hai
👑
Right 👍
💯💯💯
A machine element is subjected to the following bi axial sate of stress
sigma x=80 Mpa
sigma y =20 Mpa
Tau xy=40 Mpa
Share strength of materials is 100 Mpa.
find the factors of safety as per Trecsca Maximum share stress theory.
a) 1
b 2
c) 3
can you tell me the correct ans please sir.
The correct Ans is 2.
but while i solve get 1.
can you confirm it please?
fatigue Failure theories bhi same hain kya?
Maximum
38:33 sir maximum books me rectangular bola hai
🙏🙏
Keep the lectures free please🙏🙏🏼🙏
🙏🙏🙏🙏🙏
Sir safest condition less than k liye hogi na if equal ho jayega then most chances for failure for design purpose
FOS bhi tho rahega
itna boring ki neend aagyi