@@jacobnussbaum2309 it comes from a Tumblr post comparing eldritch madness with being an ant that briefly understands the workings of a circuit board and then, after a moment, returns to being a normal ant
This is why I love watching NL: keeping the spade joker all game while changing all the cards to hearts, only to replace it at the very last hand of the game just to get it right back. 😂
13:02 - Regarding NL's reasoning, I decided to go full Type A viewer, and posted this in a response to another comment as well. Let's try to solve this quantitatively. Double check me to make sure I don't make any mistakes. The multiplier value from copying Gros Michel is (30 • X) + (Y • X), where X is the multiplier from obelisk and Y is whatever multiplier value you get from the hand (hand type, mult cards, suit triggers, etc) prior to moving on to triggering the jokers. The multiplier value of copying Obelisk on the left is (Y • X²) + (15 • X). You're copying Gros Michel one less time, and it only receives the multiplier value from your Obelisk Copy, not the original. On the other hand, your mult prior to jokers triggering is now multiplied by both, so you get an X² multiplier on Y. To find the break even point, we set these equal to one another and solve for Y. This will tell us at what value our mult prior to joker triggers has to be for it to equal the value of copying Gros Michel. YX + 30X = YX² + 15X Y + 30 = YX + 15 YX - Y = 15 Because the square of X is involved here, it means the breakeven value is going to change depending on the value of X. Setting X equal to a series of values provides a series of "isomult" curves which should give the breakeven value for a given Obelisk magnitude. If Obelisk's multiplier was a continuous variable, these would describe a smooth surface of point payouts for any given Obelisk value, but the payout is actually a discrete variable so it's a discontinuous series of "ridges." If you were to plot these, you would find a progressively lower Y breakeven as the value of X goes up and the square of X has a larger impact on the initial Y multiplier. Let's look at this for the first hand played at 14:54 . The Obelisk multiplier is at 3.2 here so we have: 3.2Y - Y = 15 2.2Y = 15 Y = 6.81818181 (repeating, of course :P) So, your initial mult only has to be roughly 7 for copying Obelisk to be a better idea than Gros Michel. On that hand of two jacks, one of which was a mult card club suit, the initial multiplier from the hand prior to jokers is 9. So in that instance, NL would have been better copying Obelisk over Gros Michel. That's not an especially strong hand, so I would imagine in most instances, except maybe playing a single pair with only 1 or 0 clubs and no other effects, it is probably preferable to copy Obelisk. Any hand with at least a couple clubs in the score is going to outperform with Obelisk. It's even easier to see if we set the Obelisk value to, say, 4. You only need a Y of 5 to break even. At an X of 5, you only need a Y of 4. Given the low margin that NL lost that run by at the end, I suspect copying Obelisk would have saved that run for him. But this is part of why Balatro is such a fun game!
As an addendum, this works out even more lopsidedly when he starts copying Gluttonous Jokers instead. In that instance it's X(8C + Y) vs X²(4C +Y) Where X is Obelisk, C is the number of scored clubs, and Y is all other sources of mult. Just glancing at it, the right expression is definitely greater than the left expression for all X>2 at any given number of clubs. I think it's probably a bit lower if you factor in Y depending on how big it is, but this is a 3 variable equation so it now describes a 3D space and I'm too lazy to work out something more comprehensive. 😂
@@whatsguccivespucci4379 Geez, why is everyone being so rude?! I'm sick today, and I thought it was fun to work out a little math problem while I'm stuck inside. Sue me I guess.
@@nathanhopkins7976it is! This is sick to read, and a good proof! I think some people (me included) just have short attention spans and are coping through seething.
@@nathanhopkins7976 honestly man 99% of people who comment on youtube are not looking for a full breakdown of the math problem and thus find you more annoying than helpful, also like me i have absolutely no clue what your saying because i dont understand math like you do so again your comment is more annoying than helpful. not trying to be rude just letting you know why people dont care for your comment. its too much for a youtube comment especially on a NL balatro video.
13:31 But imagine if you had 10, the you multiplied it by 2... Then you multiplied it by 2 AGAIN! It's better than adding first then multiplying if your adder is less than even the early multiplication. That's what you're missing out on not copying obelisk on the left.
Im not sure NL reads these comments anymore, but regarding brainstorm with obelisk, yes you want the multiplier at the end, but brainstorm would work as obelisk, thus you would still multiply it at the end, but you would multiply the multiple. Not trying to be a type B chatter, just hoping to clarify something you might have missed!
13:40 I think this is actually a misplay in this situation. Because he has the club joker which adds mult as the cards are scored which means he'll usually have enough initial mult for a 3x on the left to be worth more than a +15
Ideally you would actually switch them back and forth depending on what hand you're about to play, but I know better than to expect that level of min maxing from NL
Say you're in a pretty good scenario playing a default Flush with the Obelisk at 4*. If you're copying Obelisk, the copy has you going from a +4 mult from the Flush to a +16 mult, which is only adding 12. Copying banana gives you +15. In both cases you're then multiplying by the same number at the end, so copying banana ends up being more. I guess optimal play is to rearrange the order mid fight depending on what the math says, but that's beyond what I (and the egg) can compute. The math also probably changes when the mult from the Obelisk gets higher and it gets better to copy Obelisk.
@@masterplusmargarita You get two times with copy on the far right and obelisk on the left: obelisk triggers first, without any additive mult bonus at this point, then your other jokers go, then your copy on the end triggers. It's better to have the obelisk at the left and copy at the right, you're essentially squaring it plus a bit more.
@@rjlarson6744Exactly. Unless your first joker adds more than obelisk would multiply, it's almost always going to be better to do multiple multiplications anywhere in the lineup as long as you have as many as possible on the right. You're doing exponentiation at that point, which is even better than multiplication. He's too caught up on the "multiplication last is best!" idea to realize he could be a level above that.
Let me see if I can solve this quantitatively. Double check me to make sure I don't make any mistakes. The multiplier value from copying Gros Michel is (30 • X) + (Y • X), where X the multiplier from obelisk and Y is whatever multiplier value you get from the hand (hand type, mult cards, suit triggers, etc) prior to moving on to triggering the jokers. The multiplier value of copying Obelisk on the left is (Y • X²) + (15 • X). You're copying Gros Michel one less time, and it only receives the multiplier value from your Obelisk Copy, not the original. On the other hand, your mult prior to jokers triggering is now multiplied by both, so you get an X² multiplier on Y. To find the break even point, we set these equal to one another and solve for Y. This will tell us at what value our mult prior to joker triggers has to be for it to equal the value of copying Gros Michel. YX + 30X = YX² + 15X Y + 30 = YX + 15 YX - Y = 15 Because the square of X is involved here, it means the breakeven value is going to change depending on the value of X. Setting X equal to a series of values provides a series of "isomult" curves which should give the breakeven value for a given Obelisk magnitude. If Obelisk's multiplier was a continuous variable, these would describe a smooth surface of point payouts for any given Obelisk value, but the payout is actually a discrete variable so it's a discontinuous series of "ridges." If you were to plot these, you would find a progressively lower Y breakeven as the value of X goes up and the square of X has a larger impact on the initial Y multiplier. Let's look at this for the first hand played at 14:54 . The Obelisk multiplier is at 3.2 here so we have: 3.2Y - Y = 15 2.2Y = 15 Y = 6.81818181 (repeating, of course :P) So, your initial mult only has to be roughly 7 for copying Obelisk to be a better idea than Gros Michel. On that hand of two jacks, one of which was a mult card club suit, the initial multiplier from the hand prior to jokers is 9. So in that instance, NL would have been better copying Obelisk over Gros Michel. That's not an especially strong hand, so I would imagine in most instances, except maybe playing a single pair with only 1 or 0 clubs and no other effects, it is probably preferable to copy Obelisk. Any hand with at least a couple clubs in the score is going to outperform with Obelisk. It's even easier to see if we set the Obelisk value to, say, 4. You only need a Y of 5 to break even. At an X of 5, you only need a Y of 4. Given the low margin that NL lost that run by at the end, I suspect copying Obelisk would have saved that run for him. But this is part of why Balatro is such a fun game!
Brainstorm would go last and it should be higher since you're multiplying at the beginning and end. Works best with glass cards and planet cards adding mult before the jokers hit
After playing a few rounds, the full game seems a lot more harder and the Jokers are very very varied, getting big boy mults early is getting hard for my bland flush playstyle.
Yeah, I figured that full house is a way more versatile to invest into with só many possible jokers, I still go for a flush build if the right joker presents itself though
Hey NL, any plans to re-release merch anytime soon? Loving that hoodie and would love one of my own 🥹 (You may not read this, but asking none the less.)
Going back to the demo after witnessing the full launch is like being the ant that witnessed the circuit board.
That's a great line did you come up with it? An all time literary analogy
@@jacobnussbaum2309 it comes from a Tumblr post comparing eldritch madness with being an ant that briefly understands the workings of a circuit board and then, after a moment, returns to being a normal ant
me who uses the balatro vids like a podcast
@@nmyhv1 that's what librarian is for
@@jacobnussbaum2309 pam from the office saying it's the same picture.jpg
Releasing a video on the demo after the full release video, what a mad lad!
never forget what they took from us (dean norris deck)
he probably has PTSD from slay the spire where he didnt release the full version just kept posting old one untill it became 70% dislikes LULE
When did that happen?@@Ryan38475
Mad at a man for building a responsible and hefty backlog smh
Pog the camera is in the demo ie correct place
“This is one of the greatest hands I’ve ever had”
- Things said days before getting a million point hand in the full Balatro game
Watching the demo after playing and seeing the full game is really an allegory of the cave moment for how crazy Balatro can be.
Editor's note: nobody calls him Mister Glass
My man is Jokaire-pilled today and I am pegged up for it.
Jokace
a demo video after the full release?!?! he's fully balatro mode
Got them out of order like his glass cards
@@pretentiousname01
+2
@@pretentiousname01 +2
This is why I love watching NL: keeping the spade joker all game while changing all the cards to hearts, only to replace it at the very last hand of the game just to get it right back. 😂
Demo ah ah video
13:02 - Regarding NL's reasoning, I decided to go full Type A viewer, and posted this in a response to another comment as well.
Let's try to solve this quantitatively. Double check me to make sure I don't make any mistakes.
The multiplier value from copying Gros Michel is (30 • X) + (Y • X), where X is the multiplier from obelisk and Y is whatever multiplier value you get from the hand (hand type, mult cards, suit triggers, etc) prior to moving on to triggering the jokers.
The multiplier value of copying Obelisk on the left is (Y • X²) + (15 • X). You're copying Gros Michel one less time, and it only receives the multiplier value from your Obelisk Copy, not the original. On the other hand, your mult prior to jokers triggering is now multiplied by both, so you get an X² multiplier on Y.
To find the break even point, we set these equal to one another and solve for Y. This will tell us at what value our mult prior to joker triggers has to be for it to equal the value of copying Gros Michel.
YX + 30X = YX² + 15X
Y + 30 = YX + 15
YX - Y = 15
Because the square of X is involved here, it means the breakeven value is going to change depending on the value of X. Setting X equal to a series of values provides a series of "isomult" curves which should give the breakeven value for a given Obelisk magnitude. If Obelisk's multiplier was a continuous variable, these would describe a smooth surface of point payouts for any given Obelisk value, but the payout is actually a discrete variable so it's a discontinuous series of "ridges." If you were to plot these, you would find a progressively lower Y breakeven as the value of X goes up and the square of X has a larger impact on the initial Y multiplier.
Let's look at this for the first hand played at 14:54 . The Obelisk multiplier is at 3.2 here so we have:
3.2Y - Y = 15
2.2Y = 15
Y = 6.81818181 (repeating, of course :P)
So, your initial mult only has to be roughly 7 for copying Obelisk to be a better idea than Gros Michel. On that hand of two jacks, one of which was a mult card club suit, the initial multiplier from the hand prior to jokers is 9. So in that instance, NL would have been better copying Obelisk over Gros Michel. That's not an especially strong hand, so I would imagine in most instances, except maybe playing a single pair with only 1 or 0 clubs and no other effects, it is probably preferable to copy Obelisk. Any hand with at least a couple clubs in the score is going to outperform with Obelisk.
It's even easier to see if we set the Obelisk value to, say, 4. You only need a Y of 5 to break even. At an X of 5, you only need a Y of 4. Given the low margin that NL lost that run by at the end, I suspect copying Obelisk would have saved that run for him. But this is part of why Balatro is such a fun game!
As an addendum, this works out even more lopsidedly when he starts copying Gluttonous Jokers instead. In that instance it's
X(8C + Y) vs X²(4C +Y)
Where X is Obelisk, C is the number of scored clubs, and Y is all other sources of mult.
Just glancing at it, the right expression is definitely greater than the left expression for all X>2 at any given number of clubs. I think it's probably a bit lower if you factor in Y depending on how big it is, but this is a 3 variable equation so it now describes a 3D space and I'm too lazy to work out something more comprehensive. 😂
Touch grass
@@whatsguccivespucci4379 Geez, why is everyone being so rude?! I'm sick today, and I thought it was fun to work out a little math problem while I'm stuck inside. Sue me I guess.
@@nathanhopkins7976it is! This is sick to read, and a good proof! I think some people (me included) just have short attention spans and are coping through seething.
@@nathanhopkins7976 honestly man 99% of people who comment on youtube are not looking for a full breakdown of the math problem and thus find you more annoying than helpful, also like me i have absolutely no clue what your saying because i dont understand math like you do so again your comment is more annoying than helpful. not trying to be rude just letting you know why people dont care for your comment. its too much for a youtube comment especially on a NL balatro video.
13:31 But imagine if you had 10, the you multiplied it by 2... Then you multiplied it by 2 AGAIN! It's better than adding first then multiplying if your adder is less than even the early multiplication. That's what you're missing out on not copying obelisk on the left.
+2 type a
the math knower
Finish one Balatro video just for another to be there for me let's go
KEEP EM COMING BROTHER KEEP EM COMING
Im not sure NL reads these comments anymore, but regarding brainstorm with obelisk, yes you want the multiplier at the end, but brainstorm would work as obelisk, thus you would still multiply it at the end, but you would multiply the multiple. Not trying to be a type B chatter, just hoping to clarify something you might have missed!
41:21 clean outro my streamer is NOT washed
getting the largest pogging gourd at the county fair today lads
If he had just made that flush with 5 cards instead of 4 in the first run...😢
13:40 I think this is actually a misplay in this situation. Because he has the club joker which adds mult as the cards are scored which means he'll usually have enough initial mult for a 3x on the left to be worth more than a +15
Ideally you would actually switch them back and forth depending on what hand you're about to play, but I know better than to expect that level of min maxing from NL
type a chatter spotted
At 13:00 you could have just put the copy joker on the far right and obelisk on far left wouldn't that have been more than copying banana?
Say you're in a pretty good scenario playing a default Flush with the Obelisk at 4*. If you're copying Obelisk, the copy has you going from a +4 mult from the Flush to a +16 mult, which is only adding 12. Copying banana gives you +15. In both cases you're then multiplying by the same number at the end, so copying banana ends up being more. I guess optimal play is to rearrange the order mid fight depending on what the math says, but that's beyond what I (and the egg) can compute. The math also probably changes when the mult from the Obelisk gets higher and it gets better to copy Obelisk.
@@masterplusmargarita You get two times with copy on the far right and obelisk on the left: obelisk triggers first, without any additive mult bonus at this point, then your other jokers go, then your copy on the end triggers. It's better to have the obelisk at the left and copy at the right, you're essentially squaring it plus a bit more.
@@rjlarson6744Exactly. Unless your first joker adds more than obelisk would multiply, it's almost always going to be better to do multiple multiplications anywhere in the lineup as long as you have as many as possible on the right.
You're doing exponentiation at that point, which is even better than multiplication. He's too caught up on the "multiplication last is best!" idea to realize he could be a level above that.
Let me see if I can solve this quantitatively. Double check me to make sure I don't make any mistakes.
The multiplier value from copying Gros Michel is (30 • X) + (Y • X), where X the multiplier from obelisk and Y is whatever multiplier value you get from the hand (hand type, mult cards, suit triggers, etc) prior to moving on to triggering the jokers.
The multiplier value of copying Obelisk on the left is (Y • X²) + (15 • X). You're copying Gros Michel one less time, and it only receives the multiplier value from your Obelisk Copy, not the original. On the other hand, your mult prior to jokers triggering is now multiplied by both, so you get an X² multiplier on Y.
To find the break even point, we set these equal to one another and solve for Y. This will tell us at what value our mult prior to joker triggers has to be for it to equal the value of copying Gros Michel.
YX + 30X = YX² + 15X
Y + 30 = YX + 15
YX - Y = 15
Because the square of X is involved here, it means the breakeven value is going to change depending on the value of X. Setting X equal to a series of values provides a series of "isomult" curves which should give the breakeven value for a given Obelisk magnitude. If Obelisk's multiplier was a continuous variable, these would describe a smooth surface of point payouts for any given Obelisk value, but the payout is actually a discrete variable so it's a discontinuous series of "ridges." If you were to plot these, you would find a progressively lower Y breakeven as the value of X goes up and the square of X has a larger impact on the initial Y multiplier.
Let's look at this for the first hand played at 14:54 . The Obelisk multiplier is at 3.2 here so we have:
3.2Y - Y = 15
2.2Y = 15
Y = 6.81818181 (repeating, of course :P)
So, your initial mult only has to be roughly 7 for copying Obelisk to be a better idea than Gros Michel. On that hand of two jacks, one of which was a mult card club suit, the initial multiplier from the hand prior to jokers is 9. So in that instance, NL would have been better copying Obelisk over Gros Michel. That's not an especially strong hand, so I would imagine in most instances, except maybe playing a single pair with only 1 or 0 clubs and no other effects, it is probably preferable to copy Obelisk. Any hand with at least a couple clubs in the score is going to outperform with Obelisk.
It's even easier to see if we set the Obelisk value to, say, 4. You only need a Y of 5 to break even. At an X of 5, you only need a Y of 4. Given the low margin that NL lost that run by at the end, I suspect copying Obelisk would have saved that run for him. But this is part of why Balatro is such a fun game!
@@nathanhopkins7976 I ain't reading all that. I'm happy for u tho. Or sorry that happened.
The rocket joker is Economy +++. It equals a Squirrel on speed.
crazy? I was crazy once
+2 mult
Egg is so bad at econ that even when he says he's econ pilled he's spending to 0 every shop
Brainstorm would go last and it should be higher since you're multiplying at the beginning and end. Works best with glass cards and planet cards adding mult before the jokers hit
The true becoming a joker arc begins
The outro on fast forward goes crazy
After playing a few rounds, the full game seems a lot more harder and the Jokers are very very varied, getting big boy mults early is getting hard for my bland flush playstyle.
gotta diversify the portfolio
Yeah, I figured that full house is a way more versatile to invest into with só many possible jokers, I still go for a flush build if the right joker presents itself though
So far I've thought both were incredibly easy but I haven't done stakes
Pogged up for some Balatro
only NL posts a demo video after the full release one
22:13 that is, in fact, how it is pronounced
What about the copy joker all the way right and the obelisk all the way left, you get obelisk ×mult at the beginning and end
I was like oh cool another full...oh its the demo lmao
He was cooking with that obelisk I won’t lie, he might not be fucking suck today…
edit: nvm he cooked too hard he burnt it
Unbreakable reference noted
Hey NL, any plans to re-release merch anytime soon? Loving that hoodie and would love one of my own 🥹 (You may not read this, but asking none the less.)
they dont call you that
leave it to egg to decide X.5+15=Xi Xi.5=Xt is better than (X+15+15).5=Xt in most cases
Anyone know if unlocks are counted from Endless Mode?
If he copied Obelisk, would it have gotten +0.4 better on every hand instead of 0.2?
Through the wire ass title
2:40 - Since when selling The Fool and buying the Joker is better play than buying a Credit Card then the Joker? :V
Wouldn't be easier to just slowly rotate your most played hand?
Helldivers
OH MY GAWD THE DAYCARE IS UPON US
NL try not to flush challenge
POGGGGGGG!!!!
Lets gooooo
this gave me fuckin wiplash xd
Man overthinking obelisk so hard
Not copying the obelisk with blueprint almost made me unsubscribe
Watching NL for optimal plays is cringe
@@jokojabowatching NL for optimal plays is suboptimal