in grad school where you're expected to learn pretty much everything yourself regardless of how good of a professor you have...this video has put together so many major concepts for IR in a concise and effective manner. thank you for this video. please continue making a difference for students like me.
I'm an undergrad,, yet I understand nothing in class its super fast. I'm always lost. This is where I learn. I'm so grateful. The system they use in school is just not fair.
sorry to be so offtopic but does any of you know of a tool to log back into an Instagram account?? I was stupid forgot my account password. I would love any assistance you can give me
These videos are a great summary of the basic principles of this analysis technique and have helped massively with my understanding of the topic. However, I'm explaining how this technique is used in a piece of university work and so am in need of academic references on the subject. I don't suppose anyone could suggest any of the original publications which describes this technique in detail? Thank you in advance and thanks again for the videos!
It is obvious the 'bond' does not absorb the photon, but the electrons in them, and electrons absorb photons according to their orbital state(s). Could you go into exactly why the stretching/wagging freq matches the photon absorption, eg: spectral lines, or do they? They seem like different things that may affect each other, but are distinct.
I like ur every vedio bro Pleaseeeeeee add more contents like this and please add more information in every vedio because u make it understand properly with examples and diagrams
Thank you so much for your kind words. However, I no longer make any new videos. I'm working in a completely different industry now. So, what you see is what you get.
You mentioned lighter tha mass of atoms greater is the wavenumber but C=O has 1700-1800 but C=C has 1680-1600 why so? C has less mass than O so shouldn't C=C have higher wavenumber than C=O
oxygen is more electronegative compared to carbon. therefore the electronegativity difference in C=O is more compared to the C=C bond. if the electronegativity difference is more, stronger the bond. so C=O bond is stronger than a C=C bond, and if the bond is strong, requires more energy for its vibration. therefore C=O bond showing a higher wave number than C=C.
in grad school where you're expected to learn pretty much everything yourself regardless of how good of a professor you have...this video has put together so many major concepts for IR in a concise and effective manner. thank you for this video. please continue making a difference for students like me.
I'm an undergrad,, yet I understand nothing in class its super fast. I'm always lost. This is where I learn. I'm so grateful. The system they use in school is just not fair.
sorry to be so offtopic but does any of you know of a tool to log back into an Instagram account??
I was stupid forgot my account password. I would love any assistance you can give me
@Blaze Timothy Instablaster :)
THANKS FOR SAVING MY LIFE SIR YOU ARE SAVING STUDENTS 1 VIDEO AT A TIME EVEN 9 YEARS AFTER U UPLODADED THIS VIDEO
The best content I found for this topic.
The best channel I have found on chemistry
Yep, I'm going to keep watching until I get bored....so far, it's awesome
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Amazing Stuff. It would be really helpful if you had a similar video for XRD as well!
These videos are a great summary of the basic principles of this analysis technique and have helped massively with my understanding of the topic. However, I'm explaining how this technique is used in a piece of university work and so am in need of academic references on the subject. I don't suppose anyone could suggest any of the original publications which describes this technique in detail?
Thank you in advance and thanks again for the videos!
Very clear and helpful, thanks a lot
It is a great lecture ! Thank you.
It is obvious the 'bond' does not absorb the photon, but the electrons in them, and electrons absorb photons according to their orbital state(s). Could you go into exactly why the stretching/wagging freq matches the photon absorption, eg: spectral lines, or do they? They seem like different things that may affect each other, but are distinct.
this tutorial is awesome ! thank you !!!
Is the answer going to be the same if the question wasn't specific like due to carbonyl group in the first question?
13:09
More single bond character = higher wavenumber due to C-O on the molecule on the right
sir please explain how can we know particular i.r frequencies of a molecule in i.r spectroscopic problems
these are really good videos.
Love your videos
I like ur every vedio bro
Pleaseeeeeee add more contents like this and please add more information in every vedio because u make it understand properly with examples and diagrams
Thank you so much for your kind words. However, I no longer make any new videos. I'm working in a completely different industry now. So, what you see is what you get.
@@Knowbee i'm so sorry to hear that it's a shame
Great explanation
In sample problem 2 why are we not considering the masses of O and N?
Perfect. Thank you.
Very useful video
wonderful
You mentioned lighter tha mass of atoms greater is the wavenumber but C=O has 1700-1800 but C=C has 1680-1600 why so? C has less mass than O so shouldn't C=C have higher wavenumber than C=O
C-C is a single bond. Single bond has less energy.
cause yolo swaggg
oxygen is more electronegative compared to carbon. therefore the electronegativity difference in C=O is more compared to the C=C bond. if the electronegativity difference is more, stronger the bond. so C=O bond is stronger than a C=C bond, and if the bond is strong, requires more energy for its vibration. therefore C=O bond showing a higher wave number than C=C.
the C=O bond is stronger and shorter than the C=C bond. Oxygen is more electronegative than Carbon. Therefore, the C=O bond has a higher wave number.
Good
electron withdrawing and donating group point is not discussed in the video.
Great!
5:52 Hehehe... He wrote heaver :P
I'm only teasing. I enjoyed the video tons. Very helpful.
Applause 👏
Nice one
'we're just gonna accept this equation as true' haha.
Wisozk Dale
probably a good video but i stopped at 50 seconds when i heard you say aa-ffect 😭