Watching the physics playlist for the MCAT and i cannot stress how great of a teacher you are!!! Thank you for uploading your videos on RUclips, they’re so SO helpful!
You know how I know Chad is a generous, talented educator? Because these videos were used religiously for test prep on a paid platform, Coursesaver, for years. Chad's made this available for free as part of his new test prep program.
Thank you for these videos!! Videos with simple explanations of algebra-based physics have been super hard for me to find. So glad I found your channel
You should check out the website! It’s these exact videos however each section includes a worksheet/“cheat-sheet” to follow along and is followed by practice problems + solutions :) I should note that it’s like $9 or something a month but honestly it’s worth it
Ok I don't know if you'll see this or even reply to this, but I have a dumb question... Can we just always think of the vector as a hypotenuse?? That's a lot easier for me to remember conceptually than just thinking "it has magnitude and direction" lol
Hello Meredith! My best answer to this is "sort of." If a vector lies directly on the x- or y-axis then breaking it into components will not be necessary as it would have one component that is zero and the other that is the full magnitude of the vector. However, if the vector does not lie directly on the x- or y-axis then the magnitude of the vector will always be the hypotenuse of a right triangle so this is when you could think of the vector (or specifically the magnitude of the vector) as a hypotenuse. Keep in mind that this wouldn't get you direction of the vector and that you'd typically be using the tangent function to determine the angle. Hope this helps!
You know what I hate the most? Teachers who teach a subject that really do not care about that subject at all. My physics 101 teacher is the worst, literally. Just hands you the book and expects you to know by test. I hope these vids can help
Watching the physics playlist for the MCAT and i cannot stress how great of a teacher you are!!! Thank you for uploading your videos on RUclips, they’re so SO helpful!
Excellent, Kristina - glad they are helping!
You know how I know Chad is a generous, talented educator? Because these videos were used religiously for test prep on a paid platform, Coursesaver, for years. Chad's made this available for free as part of his new test prep program.
Glad you find them helpful, JT!
this is probably the most beginner friendly general phys videos I've ever watched!! Thank you SO much for sharing.
You are most welcome.
Thank you for these videos!! Videos with simple explanations of algebra-based physics have been super hard for me to find. So glad I found your channel
Glad you're finding them helpful Britt!🙂
You should check out the website! It’s these exact videos however each section includes a worksheet/“cheat-sheet” to follow along and is followed by practice problems + solutions :)
I should note that it’s like $9 or something a month but honestly it’s worth it
Just by listening to you, Chad sir...gives a beginner with zero knowledge, the motivation to learn...tq
Thanks for saying so!
'Abreadcrumb and fish' shirt love it haha
A great shirt indeed! 😇
Thank you chad, you helped me so much in chemistry and I look forward to using this playlist for physics
Glad to hear it - I'm also currently publishing an updated General Physics playlist. I hope you find either/both helpful.
Great video and explanations, to the point and engaging.
Much appreciated!
The final answer of the magnitude of the vectors A+B wouldn't be 13.3? ( 18.56 ' of the video)
will this physics be calc based or algebra based?
Ok I don't know if you'll see this or even reply to this, but I have a dumb question... Can we just always think of the vector as a hypotenuse?? That's a lot easier for me to remember conceptually than just thinking "it has magnitude and direction" lol
Hello Meredith! My best answer to this is "sort of." If a vector lies directly on the x- or y-axis then breaking it into components will not be necessary as it would have one component that is zero and the other that is the full magnitude of the vector. However, if the vector does not lie directly on the x- or y-axis then the magnitude of the vector will always be the hypotenuse of a right triangle so this is when you could think of the vector (or specifically the magnitude of the vector) as a hypotenuse. Keep in mind that this wouldn't get you direction of the vector and that you'd typically be using the tangent function to determine the angle. Hope this helps!
You know what I hate the most? Teachers who teach a subject that really do not care about that subject at all. My physics 101 teacher is the worst, literally. Just hands you the book and expects you to know by test. I hope these vids can help
We hope the vids help, Acolyte - good luck on your studies!