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Log Equation but with Different Bases
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- Опубликовано: 28 июн 2024
- Solving log equations with different bases can be tricky.
In this video, one can learn how to change the base of one log so that it matches the base of the other log expression.
Did not know this property of logs. Makes perfect sense, given some thought. Thank you!
Wow. I'm always learning new logarithm properties. I wonder how many logarithm properties exist in math. Is it infinite? 🤔
They are NOT infinite but we've quite a bunch of them. According to my experience logaithm properties are better studied by practising.
This is just a result of other laws i.e. logₐx=ln x/ln a=bln x/(bln a)=ln xᵇ/ln aᵇ=log_{aᵇ} (xᵇ).
log16(x) + log4(x) + log2(x) = 7
log2⁴(x) + log2²(x) + log2(x) = 7
1/4 (log2(x)) + 1/2 (log2(x)) + log2(x) = 7
log2(x)¼ + log2(x)½ + log2(x) = 7
log2(x¼.x½.x) = 7
(x¼)⁷ = 2⁷
x¼ = 2
x = 2⁴
x = 16
Nice
How come
Hail from Brazil! Nice solution
Very good thanks for sharing
It was awesome.
can you teach me on about integretion and limitations.
This is such a save when you have a math test on log tomorrow 😭❤️🌟
Thank you so much!
Thanks teacher
Thank you soo much sir ❤️🙏🏻
Nice
base=2, we have (1/4)log2(x)+(1/2)log2(x)+log2(x)=7,so log2(x)=4, x=2^4=16
That was impressive.
That's a good one. Thank you.
Thank you for your teaching 🌹
I like your teaching 🌹
You are very kind teacher ❤
thank you sir 🙏
Genius guy
I will teach this rule next year to my students. Thanks.
All the best~
Am from Uganda en i love the way you calculate math problems. Am requesting u to use us differential equations thank u very much ❤❤❤❤❤❤❤❤❤❤0:00
You can't just say that because the powers are the same, x = 16. For example, x²=2² has two solutions, x = ±2. In this case there are actually seven solutions, the other 6 being complex numbers. So x = 16e^(2kπi/7) ∀k∈ℤ∩[0,6].
Very good
Thanks
interesting, I didnt know this was a property of logs. very useful though, thank you.
You're welcome!
Sir, please upload some videos on integration.
🤗
log16(x)+log4(x)+log2(x)=7
log2(4x)+log2(2x)+log2(1x)=7
log2(4•2,52)+log2(2•2,52)+log2(1•2,52)
log2(10,08)+log2(5,04)+log2(2,52)=
3,33'+2,33'+1,33'=7
x=2,52
Our math teacher never taught us such details of logs
@@sajidrafique375
Yeah you are right although where are you from ?
@@user-km2fh5zi7p Santa Barbara city college , caifornia but i was a foreign student there from pakistan ..
Maybe at the end just 7logx = 7
How many people accidentally square or power to 4 the 7 on the other side.
he x should be 2 also if u just write power before log and put it on x head it be 2 powe 7 is x pow3er 7 so x is 7
Sure….it’s easy for a math genius…..
Very helpful.
If only you don't use writing in colours other than white and yellow. Both colours are perfect and visible
Ok next time