Lec 39 - Graphs of Polynomials: Behavior at X-intercepts

[@sayantaniray2213]

U made this difficult concept pretty easy sir

[@gowthamkarthi9836]

Really?he is the worst teacher I ever seen

[@jishubharadwaj3817]

@@gowthamkarthi9836 beauty is in the eyes of the beholder

[@maythegodguideyou]

@@jishubharadwaj3817 koi andha hua toh

[@aashishsinghnagvanshi4155]

thanks for iit madras that can provided these kinds of amazing content for free

[@KDANAND-mr2jn]

I apologise Sir but you are teaching or study for yourself.

[@Devarathareddy]

Ya you are right😢

[@theius7781]

i am studying these concepts on youtube and they are pretty easy, but this prof. made them difficult.

[@damemer8724]

*Sir big fan of your work*

[@ADARSHCHATURVEDI-gm7nd]

sir how did you conclude that 4 cant be the multiplicity in last example?

[@priyanshusharmaprsh6629]

Pretty easy

[@varun3447]

you literally gave no explanation for the example two and how you excluded degree from 4 from the polynomial

[@smokyvibes]

bro he did you are brain dead or what? how the f did u even pass class 12 if you dont know graph of x^2 and x^4

[@1970uma]

14:08 How did sir arrive at x^2+1 as a factor? can someone please enlighten..

[@hmmm2617]

He did not arrive at that factor, he just knew it because he probably plotted it from the expression using some software like desmos.
That example was shown to us to illustrate the fact that some polynomials have zeros that cannot be obtained using the methods we learnt so far. Here the two zeros of (x^2 + 1) are outside the real domain and therefore we cannot find them or their corresponding multiplicities.

[@ajojose1077]

Nahh bro we know that the other roots must be complex so take it as (x²+a)
Now the function is f(x)=k(x²+a)(x-2) since we know the graph check for 2 points and find k and a.
Please note that I just made this up so there maybe better ways ig 😅

[@safeerkilinadan7366]

Nicely explained.

[@rakshit_arora1]

Sir aapka reaction at 1:44 😆