Module 17: Homodyne Receiver

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  • Опубликовано: 18 сен 2024

Комментарии • 14

  • @MrHeatification
    @MrHeatification 2 месяца назад

    wow this course is soo well made. Splendid. Thank you very much Sir!

  • @dhavalvaidya5153
    @dhavalvaidya5153 5 лет назад +23

    On slide number 4, at time 0:22, x(t) X s(t) should have one term cos(win+wL0). Please correct the error

    • @jan861
      @jan861 4 года назад +2

      Very obvious, yes. :D
      @Professor Ricketts: You can simply add an annotation in the RUclips editor.

    • @mamo6727
      @mamo6727 Год назад +3

      this type of mistakes makes learners confused, so I had to double check on other sources to get the correct formula. Which add more doubts in the correctness of the learning material. Professor, please make a correction in order to watchers relay on information

  • @richardamullens
    @richardamullens 4 года назад

    It would be great to see a practical Homodyne receiver like the one described in the September 1973 issue of Wireless World, Page 416 but using components that are easily obtainable (perhaps an NE602)

    • @professorricketts
      @professorricketts  4 года назад

      Send me a link to that article. I couldn't find it. Or the name of the article that is on p. 416

    • @richardamullens
      @richardamullens 4 года назад

      @@professorricketts Please see rhodamine.eu/~richard/Homodyne/Homodyne.html which contains links to the extracted article as well as the entire September 1973 issue.
      I built it many years ago though I substituted two mechanically ganged variable capacitors in place of the ganged inductors.

    • @badreddinegacem
      @badreddinegacem 2 месяца назад

      1:42 Dude, can you help here? in this timestamp?

    • @badreddinegacem
      @badreddinegacem 2 месяца назад

      The spectrum figure, it is not clear to me, what is w0 at right? What does it signify?

    • @richardamullens
      @richardamullens 2 месяца назад +1

      ​@@badreddinegacem Do you mean w=0 ?
      w which is read as omega is the angular frequency [ w = 2 π f ] and w = 0 signifies DC.
      when the signal is mixed with its carrier you get the sum and the difference frequencies. The difference frequency is zero. On either side of w = 0 you have the lower and upper sidebands
      See the maths at t=22s (it has a typo mentioned in the comments) - this is just the identity
      Cos(x).Cos(y) = 0.5 [ Cos (x-y) + Cos(x+y)] which is derived from
      Cos (x+y) = Cos (x) Cos(y) - Sin(x)Sin(y)
      Cos (x-y) = Cos (x) Cos(y) + Sin(x)Sin(y) Leading to
      Cos(x+y) + Cos (x-y) = 2 Cos(x).Cos(y)
      I hope that helps and answers the question you had in mind.

  • @abdelkaderalicherif6439
    @abdelkaderalicherif6439 3 года назад

    than you