Pumping Lemma for Regular & Non-Regular Languages with Examples in Urdu/Hindi

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Deserve more than 5M subscriber and 10M views on one vedio

[@azcomputing]

thanks, Your appreciation means a lot to me

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Deserves more views that of you have

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Thanku so much sir jii kl mera paper hai apki videos sy mjhy bht mili Allah pk apko is ka ajar dain 🥰

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Mera to abhi he 2 ghante bad😂

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Mera bi kal h😂😂😂😂​@@abujar.786

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Thank you sir , college me khuch smj me hi nhi aya tha ab smja

[@umarafzal8009]

Sir kmall method❤❤❤

[@mohilkumar1602]

😀nice explanation sir best for pumping lemma

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What an explanation ❤

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Excellent bhai very helpful video

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Wonderful Explanation❤❤❤

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Thank you sir! excellent work

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Thanks sir this video is very helpful and good

[@azcomputing]

Welcome

[@tech4inspiration619]

@@azcomputing sir ma nay pumping lemma for non language wali example may X=3, Y=4, Z=3 put kiya ha or jab Y ko pump kia ha to wo a^n and b^n equal aa gya ha, please guide me

[@nawabzadi678]

​@@tech4inspiration619the ending string will be aaaaabbaabbbbb which is not in the language as their is a sequence required in the question that number of b's must be followed by equal number of a's so it's non regular language

[@maazali9672]

such a great explanation😍😍

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thank you sir

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Mza agya

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Thank you sir its really help me

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I like your efforts ❤❤❤

[@azkaaziz6666]

Very nice explanation

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Zabardast bro

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Thanks sir

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Good sir

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Nice sir 🥰

[@arehman3304]

Dear Sir, Thank you for the explanation. I am watching your videos from Italy and My exam is on 26th January 2022. My professor taught this topic in a very different method. I just need to ask that how do we prove it in a mathematical fashion.

[@azcomputing]

First of all thanks for watching.
Yes, there are different and multiple methods to cover a single topic. Similarly we can prove it in mathematical fashiin in different ways.
Basically, pumping lemma is used as a proof for irregularity of a language. If a language is regular, it always satisfies pumping lemma.

[@BollywoodUniversity786]

Jazakallah sir.
You're method is great
Sir agr a ki power 834
Or b ki power 733
Ya kasy slove krny gy
Kindly tell me

[@MadGenious]

What if we divide S in such a way that X Y and Z still follow the Description even after Pumping Y?
For example, instead of considering Y as 4 b's after the 1st b.. We consider Y as the middle, 3 a's and 3 b's? So when we pump, it will still satisfy the RE..
The point is, whaat is the criteria of division of S between X Y and Z?

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❤❤❤❤❤❤

[@UsmanGenius]

What in the case if starting condition is ab and ending is bab, in that case I found pumping lemma is giving false result, is it?

[@ahmedraza6101]

Very nice explanation sir🤌👌

[@fairystar4869]

Sir plzz myhill nerode theorm ka bta dain..,possible ho tu kal tak ...perso sham ma paper h

[@arehman3304]

I would love to hear from You if you could provide these mathematical proofs using pumping lemma:
L1 = {a^p b a^q b a^q b a^r | p, q, r >= 1}
L2 = {a^p b a^q b a^q b a^q+r | p, q, r >= 1}
L3 = {a^p+q b a^q+r | p, q, r >= 1}
State whether L1, L2, and L3 are regular languages, and provide mathematical proof.

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very good explanation

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