Cockroft walton voltage multiplier

[@vinodkumarmourya1485]

You explain very well ....thanks

[@techbuzzguru4534]

Thanks

[@pemakuenchap3082]

Thank you. Indeed good explanation!!!!

[@techbuzzguru4534]

Thanks

[@bunny_editz132]

Sir my doubt is that in summary u mentioned low value of capacitance is used to minimize ripple
But from the total ripple expression you presented earlier, shouldn't it be high capacitance

[@techbuzzguru4534]

Thanks for referring back with doubt, the voltage ripple is inversely proportional to the product of frequency and value of capacitance. We can reduce the ripple by either using large capacitance and keep frequency constant, or increase frequency and keep capacitance constant. The cost of circuit can be minimized by using lower value of capacitance and keeping frequency higher while reducing ripple. Refer voltage ripple or voltage drop equations for clarity. I hope the answer helps you.

[@mabhishekofficial9590]

nice explanation ,
thank you sir.

[@techbuzzguru4534]

🙏🏻

[@udayabhanup5376]

Very nice explanation sir, useful information

[@techbuzzguru4534]

Thanks Sir

[@melplishka5978]

Awesome ty. Very well explained.

[@techbuzzguru4534]

Thanks🙂

[@bgmworld4500]

I have a doubt for problems.... will we need to mutlipy stages by 2 for calculate ripple voltage

[@techbuzzguru4534]

Hello, the ripple voltage formula depends on number of stages and other factors. Visit this website link for clarity vlabs.iitkgp.ac.in/vhvlab/html/pages/Multiplier/Theory_multiplier.html

[@bgmworld4500]

@@techbuzzguru4534 sorry i could not understand....
Please explain i have exam tomorrow..
Will i need to multiply by 2 or not?
Please help me

[@vinodkumarmourya1485]

Make videos on impulse voltage generator

[@narendravarmavarma1140]

Nice sir

[@techbuzzguru4534]

Thanks

[@amandeepkumar7855]

Why means voltage less than peak inverse voltage . First you say capacitor charge by 2 vmax ???????????

[@techbuzzguru4534]

Hi Amandeep,
The total output voltage is less than sum of peak voltages since they depend on several factors like capacitance, supply frequency, load current and number of stages. The optimum number of stages decides remaining three parameters. Higher the value of capacitances, higher will ripple. Hence high frequency and low stage capacitances are preferred. As the load current increases, the output voltage will decrease slightly.
Hope you understand this.
Thanks

[@amandeepkumar7855]

@@techbuzzguru4534 no I say when capacitor charge by 2 vmax then discharge 2 vmax and 2 vmax greater than vmax then how output voltage less than peak inverse voltage

[@rajamalik7536]

Thanks sir 🙏

[@tapasdas7847]

Can u explained in hindi