Thank you so much for this clear in plain english explanation, it is simple , concise and direct, just one´s need to set hands on job!, congratulations and greetings from Mexico!
Hi Hemanth sir, this Santhosh.Can you remember me, i am the person who messaged you via LinkedIn earlier.Today luckily i studied about hazard function.Even you thought the same with more clear understanding.
Hello sir, Nicely presented. As i have never dealt with weibull distribution, I want to know that how shape parameter and scale parameter are determined?
R(400) is actually 0.94 (Time 6:20 in video). As you note, 30 bulbs out of 500 have failed by 400 hours . This means 470 survived. Thus reliability is 470/500=0.94. Hope this is clear.
Hi Hemant Sir, This is prakash Pawar from Ashok Leyland, Sir I have a data for last one year which shows the scoring defects in panel at certain cumulative number. Weather weibull analysis will help me to predict the exact cycle of defect (scoring)occurenece, which will help mw to take action before it reoccure next time.
Sir, This id the data of failure of perticular tool for the defect Scoring Scoring data collected for one year with no of strokes produced cumulative. Also frequency of failure on that day also captured. How i can predict that whwn next failure is going to happen by using weig bull. Data sheet for your reference sent on e mail
Hi! Thanks for your keen interest. The hazard rate for the next TWO months is to be calculated. h(t) is per unit time per unit. So the demoninator will be (2x1196) and not (5x1196). Hope this is clear.
Sir actually in weibull plotting we will take characteristic life at 63.2% , why do we have to consider at that point.I know if lambda =t then e power -1 gives you 0.362 and 1- of this is 0.632 but is there anything to consider at 63.2%>>>>?
Good question. At chracteristic life, reliability is 0.362 as mentioned by you. This is purely a mathematical number and does not signify anything else in my opinion.
![ROSÉ (로제) - number one girl [더 시즌즈-이영지의 레인보우] | KBS 241129 방송](http://i.ytimg.com/vi/A9oByH9Ci24/mqdefault.jpg)
Excellent explanation Sir! This is really helpful to understand the concept, thank you!
Welcome! Appreciate your feedback!
Thank you so much for this clear in plain english explanation, it is simple , concise and direct, just one´s need to set hands on job!, congratulations and greetings from Mexico!
I am glad it was helpful! Appreciate your feedback from Mexico! Take care!
Thank you so much for this lucid exposition of the topic.
Welcome Nintishia! Thanks for your encouraging feedback.
Nice Explanation, Sir Thank You
My pleasure! Glad you liked it!
This was fantastic. Really helpful!
I am glad to know!
Very well explained, thank you so much!
Thank you Jennifer!
Great job done Sir. It was very useful for me. Thanks
Glad to hear that. Appreciate your feedback!
Thx for excellent presentation!
Glad it was helpful!
Do you have develop RBD method for SIL calculation?
Hi Hemanth sir, this Santhosh.Can you remember me, i am the person who messaged you via LinkedIn earlier.Today luckily i studied about hazard function.Even you thought the same with more clear understanding.
Good to know Santhosh!
THANK YOU THANK YOU THANK YOU THANK YOU THANK YOU THANK YOU THANK YOU THANK YOU!
You are so welcome!
I love your videos!
I am glad to know!
Hello sir,
Nicely presented.
As i have never dealt with weibull distribution, I want to know that how shape parameter and scale parameter are determined?
Thank you. Please watch our other videos on Weibull distribution. Link is here to one video:
ruclips.net/video/dsuLVS2yQ4U/видео.html
What about the ROCOF? how does it compare to the hazard rate?
Thanks! Please watch my videos on HPP and NHPP, AMSAA model for this.
Nice video. Thnk you. Can you guide us how R(400)=095 has been arrived? I am struggling. kindly help
R(400) is actually 0.94 (Time 6:20 in video). As you note, 30 bulbs out of 500 have failed by 400 hours . This means 470 survived. Thus reliability is 470/500=0.94. Hope this is clear.
Hi Hemant Sir, This is prakash Pawar from Ashok Leyland, Sir I have a data for last one year which shows the scoring defects in panel at certain cumulative number. Weather weibull analysis will help me to predict the exact cycle of defect (scoring)occurenece, which will help mw to take action before it reoccure next time.
I need to understand more before I make my recommendation.
Sir, This id the data of failure of perticular tool for the defect Scoring
Scoring data collected for one year with no of strokes produced cumulative.
Also frequency of failure on that day also captured.
How i can predict that whwn next failure is going to happen by using weig bull.
Data sheet for your reference sent on e mail
@1:55 mark, why is the h(t) not over the five months, as opposed to the 2 shown? 6/(5*1196)?
Hi! Thanks for your keen interest. The hazard rate for the next TWO months is to be calculated. h(t) is per unit time per unit. So the demoninator will be (2x1196) and not (5x1196). Hope this is clear.
Instantaneous Hazard rate at 450 hrs is only 0.00017. In your question you have mentioned hazard rate at 400 hrs 0.00017 which is wrong..
Let me check. I am under Covid isolation. Will respond as soon as possible!
Yes! I have the same question regarding this
3:03 we have two hazard rates at 400, 0.00015 & 0.00017? Any logic to choose one of the two?
There is only one hazard rate. 4/(50x470)=0.00017. Please do not divide by 500 as at 400, only 470 bulbs have survived.
Add more videos sirrr... related to reliability...if I have mttb in hours obtained from datasheet then how to calculate reliability using mttb
I believe you are talking about MTBF. Else clarify.
Sir actually in weibull plotting we will take characteristic life at 63.2% , why do we have to consider at that point.I know if lambda =t then e power -1 gives you 0.362 and 1- of this is 0.632 but is there anything to consider at 63.2%>>>>?
Good question. At chracteristic life, reliability is 0.362 as mentioned by you. This is purely a mathematical number and does not signify anything else in my opinion.
weather this can be used to predict the failure based on past failure data - as a predictive maintenace of press shop dies.(tools)
You need to use Life Data Analysis. Hazard rate is a foundation concept.