Razavi Electronics 1, Lec 30, MOS Characteristics I

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  • Опубликовано: 30 ноя 2024

Комментарии • 82

  • @Theincredibleteaching
    @Theincredibleteaching 6 лет назад +87

    U CHANGED MY THINKING ABOUT ELECTRONICS...... U MADE IT LIKE A CAKE WALK. THANK U SO MUCH SIR! SERIOUSLY U R THE LEGEND OF ELECTRONICS.

  • @mr.ANIMAT0N
    @mr.ANIMAT0N 2 года назад +26

    You are one of a kind.
    You must lecture our instructors and professors that makes us hate electronics

  • @d4rcym
    @d4rcym Год назад +16

    Talented, brilliant, incredible, amazing, show stopping, spectacular, never the same, totally unique

  • @veys7035
    @veys7035 3 года назад +9

    These lectures are just amazing. You are the teacher I have been looking for. Thank you very much, for humanity sake.

  • @HanumanthRao-je8ds
    @HanumanthRao-je8ds Год назад +2

    i never saw such a legend professor. Such a Good explanation.

  • @Tarunkumar-mc9of
    @Tarunkumar-mc9of 5 лет назад +3

    today I meet the legend of electronics
    such a great teaching of elecronics I never learn thank you so much sir

  • @borncreative671
    @borncreative671 5 лет назад +2

    I want to thank you sir...I was sacred of electronics but u explained it so nicely....respect

  • @rohitverma4252
    @rohitverma4252 2 года назад +2

    Only one thing to say --
    You are a legend !! 🙌🙌🙌🙌

  • @ateeq444
    @ateeq444 5 лет назад +7

    Thank you soo much!!! You've made my life a whole lot easier!

  • @sragvimohapatra13
    @sragvimohapatra13 9 месяцев назад

    marvel of a explanation ,sir.......clarifying everything

  • @pathikritsyam3687
    @pathikritsyam3687 2 года назад

    THE GOD OF TEACHING , PERIOD. I'm glued to your lectures like web series!!

  • @husamsaid3611
    @husamsaid3611 9 лет назад +62

    woooooow ; U deserve to be called " the father of Electronics CourseWare " :D
    Great thanks Prof. Razavi

    • @EslamMohamedX
      @EslamMohamedX 9 лет назад +3

      Husam Said so FAKE :D

    • @husamsaid3611
      @husamsaid3611 9 лет назад +14

      Eslam Mohamed sorry Eslam But , Do HECK U know me to judge on my feedback to prof. razavi < please keep in your SAT and don`t disturb me :D

    • @wantedq8332
      @wantedq8332 3 года назад +3

      He is the God of electronics because he knows what most of don't.

  • @mauricio533
    @mauricio533 2 года назад

    He is a really good teacher. Thank you so much.

  • @syedmuhammadmusab554
    @syedmuhammadmusab554 8 лет назад +2

    YOU ARE GREAT..
    I'VE LEARNED SO MUCH THROUGH YOUR LECTURES.
    THANKYOU SOO MUCH!!

  • @abdoulayeidrissabakar2118
    @abdoulayeidrissabakar2118 2 года назад +2

    Many thanks sir, it is really helpful

  • @muhammadabdelmoneim9917
    @muhammadabdelmoneim9917 7 лет назад +2

    you are just awesome..................

  • @thanoskaraiskos
    @thanoskaraiskos 4 года назад +10

    At the top right sketch at the start of the video, shouldn't D(rain) and G(ate) symbols be reversed? I think prof. misplaced them.

  • @BasavarajMHubli
    @BasavarajMHubli 5 лет назад +5

    Why didn't I find out about these videos sooner ?

  • @YusufBalaban
    @YusufBalaban Год назад

    You are the father of us!

  • @arpitsharma3071
    @arpitsharma3071 2 года назад +4

    7:10 Anyone noticed Drain & Gate are terminals are marked incorrectly ?

  • @lokeshsutar3476
    @lokeshsutar3476 3 года назад +2

    Please answer this...!!!!
    When writing the drain cent for the distance 'v'.....ie. v*Qch(dense).....how you substituted v(the random length) as u(dV/dx) (charge velocity)...????????

    • @rasheedadxb4835
      @rasheedadxb4835 3 года назад

      did you get its answer?.i have same doubt

    • @sauravkumar7672
      @sauravkumar7672 3 года назад +1

      he mention that in unit time it moves v mtrs.

  • @chandrimakachhwah8866
    @chandrimakachhwah8866 9 месяцев назад +1

    simplified and easy to understand

  • @garnikpepelyan8760
    @garnikpepelyan8760 3 года назад +1

    An engineer is a man or women who isn't getting tired to draw the MOSFET structure!

  • @kazishihabulislam8659
    @kazishihabulislam8659 6 месяцев назад +1

    LEGEND

  • @BhimUpadhaya-c3w
    @BhimUpadhaya-c3w 7 месяцев назад

    Love from 🇳🇵🇳🇵

  • @Peter_1986
    @Peter_1986 4 года назад +1

    Is it correct to say that the Gate voltage increases the ABILITY for the transistor to create a current, whereas the Drain and Source voltages control the actual current flow?

    • @santom13
      @santom13 4 года назад +3

      Gate voltage increases the ability for the transistor to create a channel, whereas the Drain and Source terminal voltages regulates the actual current flow
      along the channel.

  • @darshanbb6656
    @darshanbb6656 6 лет назад +3

    @40:43 v is considered as length . But @44:30 same v is substituted as velocity . Can someone explain this !!?

    • @yasirpunathil7143
      @yasirpunathil7143 6 лет назад +2

      he said v is length when takes a snapshot ,it means at a moment, but its is still velocity

    • @NaaJeevitham500
      @NaaJeevitham500 5 лет назад +4

      velocity=length/time.Current I=q/t. He said t=unit time=say 1 sec. so velocity is equal to length

    • @victrixmortalis7823
      @victrixmortalis7823 4 года назад

      bro that is current density na so with respect a particular dl element at that point current is dq/dt so in 1 second how much charge is flowing so that length got converted to Velocity!!

  • @nidigondaramesh7683
    @nidigondaramesh7683 4 года назад

    If I meet you I will just simply touch your foot and say a very big thank you sir

  • @williamsimpson-k2d
    @williamsimpson-k2d Год назад

    Correction: 10:04 It would be better to write $Q = CV_G$ or $Q = CV_{GS}$ using the actual value of V in this case.

  • @ALIN28able
    @ALIN28able 4 года назад

    Sir can you make a video on cascode Loads and start up circuit with Mos technology I'm following your Book

  • @esadakcam
    @esadakcam 3 года назад +1

    My college professor read the slide without showing how to derive it: Well this is the drain current formula...

  • @victrixmortalis7823
    @victrixmortalis7823 4 года назад

    LEGEND!!

  • @shuyuwang4867
    @shuyuwang4867 6 лет назад +1

    Too good to be true

  • @surooshali8452
    @surooshali8452 7 лет назад +4

    thank you so much sir!

  • @Sourav_Soumyajit
    @Sourav_Soumyajit 3 года назад

    Awesome :)

  • @tanmoydutta5846
    @tanmoydutta5846 3 года назад +1

    Does Prof. Behzad Razavi teach Digital Electronics Courses also? If yes, where can I get them?

  • @A_Dark_Knight
    @A_Dark_Knight 3 года назад

    What a man 🙆🔥

  • @madhurib317
    @madhurib317 7 лет назад +4

    v =uE; where v is velocity; But while deriving Id ,v is considered as small length of channel.how velocity equation is substituted in the place of length?

    • @samanzarbakhsh7923
      @samanzarbakhsh7923 7 лет назад +6

      This v is not as velocity, this distance is velocity times to 1 second (we can call it v meter). Always in this kind of problems, they consider this distant to study the what happens to the charge inside of this volume in the frame of one second. what volume? The volume with the size of v meter (v times one second) times W times in the thickness of the channel. Then he explains more, in one second later all of the charges inside of this volume (=Qden*(v meter)) is passing through the rectangular interface with the width of W and length equal to the thickness of the channel. Because we know that all of the electrons in the frame of one second they shift v meter to the right. so all of the charges inside of that volume one second before they are passing from that interface in this time of one second.

    • @rupalakshmiprasanna2418
      @rupalakshmiprasanna2418 2 года назад

      @@samanzarbakhsh7923 Thankyou so much for ur explanation

  • @sandeepgouni2871
    @sandeepgouni2871 Год назад

    why c0x is not considered as a function v(x) when there is drain voltage ? I guess it must vary with x

    • @rahulbelani1612
      @rahulbelani1612 Год назад

      Cox can't be function of V(x) as Cox is constant. It doesn't change with x

  • @AnimationsJungle
    @AnimationsJungle 4 года назад

    sir what do you mean when you say the mosfet device is ON with Vg less than Vth ? what significance does it have if there is no current ?

    • @shaikhsafura3032
      @shaikhsafura3032 3 года назад

      No, sir has said MOSFET device is ON when Vg is greater than vth not less than. And he said it happens in MOSFET only not in BJT.

    • @shaikhsafura3032
      @shaikhsafura3032 3 года назад

      And there is no current bcoz vd is zero so no current is there

  • @N.AJAYKUMAR
    @N.AJAYKUMAR 7 лет назад

    when Vgs > Vth, Vs=Vd=0 won't flow current(it's nothing but capacitor)
    how the current flows in capacitor when we apply positive voltage??? 10:00

    • @Rish569
      @Rish569 7 лет назад

      Here in this case, gate - poly - substrate form the capacitor, the current flow is considered across the the drain - substrate - source.

  • @andrejosue98
    @andrejosue98 5 лет назад

    at 48:45 you derivate V(x) ... as if it were a lineal function as V... but you said that we don´t know what form V(x) has... so v(x) is a linear expression ?

    • @이상혁-b1w
      @이상혁-b1w 4 года назад

      Hi. I don't understand the meaning of your question.
      First, prof. didn't derivate it, he integrated it. Also, when you integrate terms, being lineal or not don't matter.
      To avoid integrating V with respect of x, he just multiplied dx (I_D * dx = u_n * w * C_ox * (V_gs-V_th-v(x)) * dv )

  • @vyshnavikonka9440
    @vyshnavikonka9440 2 года назад

    at 45:00 why for distance (v) substituted the velocity equation? Can anyone help me, please

    • @nomqn1861
      @nomqn1861 2 года назад

      because at the same time both sides are divided by a unit time, making the Q become I and the distance (v) become velocity (v)

    • @vyshnavikonka9440
      @vyshnavikonka9440 2 года назад

      @@nomqn1861 thank you

  • @lachulucky4080
    @lachulucky4080 6 лет назад

    can anyone explain why we are choosing n+ (heavily doped )....i m not clear at that point so if anyone had clear about that point pls explain

    • @jiteshprasad3534
      @jiteshprasad3534 6 лет назад +2

      just bcaz to make a grt bond between p type substrate and n type material for easily current conduction

    • @kavyapandey6682
      @kavyapandey6682 6 лет назад +2

      So as to avoid the construction of any kind of diode or rectifier we usually use n type heavily doped//// And also because we want to have a good contact with the source wire and the part of silion substrate. Happy to help.

  • @bubunmazumder
    @bubunmazumder 5 лет назад

    In the graph of Id vs Vds, what maximum value of Vgs can one use?

    • @Krishanvant
      @Krishanvant 4 года назад

      the maximum value of Vgs can not exceed your supply voltage that is Vdd . obviously you can give give the input that is more than the supply voltage

    • @victrixmortalis7823
      @victrixmortalis7823 4 года назад

      VGS is a constant value through out the experiment assumed to be greater than the VTH so yeah it can be any value greater than VTH.....

  • @reemalshanbari
    @reemalshanbari 4 года назад

    Please, Does anyone know this in which chapter?

  • @UdayKumar-bm1el
    @UdayKumar-bm1el 4 года назад

    Why I_D is integrated when it is constant ?

    • @poly3902
      @poly3902 4 года назад

      Actually he didn't integrate the current, he took it out of the integration because it is constant.

  • @shikharsrivastava8346
    @shikharsrivastava8346 5 лет назад

    limit of integration should be vg to vg-vd na?

    • @이상혁-b1w
      @이상혁-b1w 4 года назад +1

      No, since V(x) is a voltage difference across source and drain, integration at the right hand should be from 0 to V_DS.

  • @williamsimpson-k2d
    @williamsimpson-k2d Год назад

    10:04 It would be better to write $Q = V_G$ or $Q = V_{GS}$ using the actual value of V in this case.

  • @mrpossible5696
    @mrpossible5696 6 лет назад

    55:44

  • @賴君皓
    @賴君皓 5 лет назад

    59:51 No

  • @mytech3833
    @mytech3833 3 года назад

    56:49
    ohh this is way before covid 19. No problem!