Itna drama nhi krna tha. We can first calculate the occurrence of 5 from 1 to 100 . So, the occurrences of 5 from 1 to 100= 20 times. Similarly, occurance of 5 from 1 to 1000 = 20×10 = 200 times . But, occurance of 5 at hundredth place from 500 to 600 = 100 times, So, total number of times 5 digit would appear= 200+100= 300 which is the answer. ALSO AS A TEACHER YOU SHOULD BE ABLE TO MAKE THE SUM EASY FOR THE STUDENTS TO UNDERSTAND INSTEAD YOU MADE IT MORE COMPLEX AND HARD
Itna drama nhi krna tha.
We can first calculate the occurrence of 5 from 1 to 100 . So, the occurrences of 5 from 1 to 100= 20 times.
Similarly, occurance of 5 from 1 to 1000 = 20×10 = 200 times .
But, occurance of 5 at hundredth place from 500 to 600 = 100 times,
So, total number of times 5 digit would appear= 200+100= 300 which is the answer.
ALSO AS A TEACHER YOU SHOULD BE ABLE TO MAKE THE SUM EASY FOR THE STUDENTS TO UNDERSTAND INSTEAD YOU MADE IT MORE COMPLEX AND HARD
Sir isn't there any one solution to count every number listing ?
300 times
Thank you
You're welcome
3 times 5 digit ke 3 cases kaise?
555 ek hi to case hai?
Why 3c1 . Why 3 !?
I also have the same doubt. Factorial could have also done the same...
Arrangement?
No need
190 numbers hun gy
302 is right galat h yeh
Nahi 300hai
N*10 n to power N kro .where N is no. Of zeros
1000 Lisining me 1 ka udhan mana jata hai ti kya hoga
First comment
300 time
190 numbers hu gy
302 is right galat h yeh
How?
No this is right, you are wrong
Yes 302 will be the right answer