Binding energy, Fission, Fusion: Nuclear Radiation: Edexcel A-level Physics
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- Опубликовано: 25 авг 2024
- Explaining the concept of binding energy along with details of the binding energy per nucleon curve, and how that relates to nuclear stability, nuclear fission and nuclear fusion.
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Fusion projects/info:
world-nuclear....
www.iter.org/
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www.neimagazin...
Quantum tunnelling:
en.wikipedia.o...
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One of the best explanations on RUclips.
ur acc a g for this 4:17
This question I don't understand - what are you asking?
@@nutshellphy no question, in other words ur a king for that in 4:17
How does the number of neutrons lead to less binding energy per nucleon if they have a higher mass?
Shouldn't that be the opposite - since Neutrons have a higher mass they will tend to contribute more to binding energy?
its bcz of the strong nucleur force of attraction between two quarks i.e neutrons and protons u have to know that this force of attraction is at a very short range compared to electrostatic force of repulsion between protons which acts at a longer range and spreads out so if an element for eg U-235 has a high nucleon number then it means tht the strong attraction force which acts at a short range would be low and the electrostatic force of repulsion between protons will dominate therefore the element with high nucleon number will try to break apart into two lighter ones to increase the strong force of attraction and making the two lighter nuclie more stable therefore more B.E per nucleon
Why do neutrons contribute less to binding energy if they have more mass? 8:04
That's a discussion beyond the scope of this channel but... think of it like this...the strong nuclear force is very short in range but electrostatic is not. So as nuclei get bigger, nucleons added to a nucleus will be too far from some others to feel their nuclear attraction. Added protons, however, feel the repulsion of all other protons, since the Coulomb force is longer in range. Coulomb repulsion grows for progressively heavier nuclei, but nuclear attraction remains about the same, and so BE/A becomes smaller. In other words, it becomes easier to remove protons and about the same difficulty to remove neutrons.
How do you find the true mass of the helium nucleus at 5:07 ?
I think to find the true mass you need to know the mass deficit and the calculated mass,
So by subtracting the calculated mass from the mass deficit, you'll get the actual mass.
I don't think there's any other way but if you find one, please let me know.
Hi
do we need to know how to use Ek = Ee? I didn't come across it in the Specification...
Conservation on energy is on there (Mechanics) so that would include Ee which is covered in the Materials section.