Mechanical Engineering: Ch 11: Friction (16 of 47) Ladder: Example 1 of 4

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  • Опубликовано: 12 дек 2024

Комментарии • 11

  • @juanlabuschagne8845
    @juanlabuschagne8845 7 лет назад +5

    Sir you are the best thing that happened since Oreos

  • @psychoshowboat
    @psychoshowboat 6 лет назад +2

    Awesome little video, made solving my own personal mechanics problem very simple and I had watched quite a selection of other videos trying to find some guidance. Nice job 🤘

  • @hassanalbuainain7635
    @hassanalbuainain7635 7 лет назад +1

    Thank you Mr. you make the things looks too easy ,keep going

  • @munirahamin9310
    @munirahamin9310 6 лет назад +2

    I'm a bit confused. Why don't we multiply Nb by 9.6/2 when calculating the moment at point A? I thought that to find a moment, we need to multiply a force by its perpendicular distance divided by 2 (as taught in other videos)..? Someone please help

  • @leonjensenn8253
    @leonjensenn8253 2 года назад +1

    2:56 should it be 9.6 or 4?

    • @MichelvanBiezen
      @MichelvanBiezen  2 года назад +2

      9.6 is the perpendicular distance from the point of rotation (A) to the line of action of the force (Nb)

  • @rapfarsinews1394
    @rapfarsinews1394 Год назад +1

    پشمام عین مال درس ماس تو فصل دو دوازدهم

  • @FindingHeaven173
    @FindingHeaven173 10 месяцев назад +1

    I have a question sir,,
    For ladders math, when I took (mg) for ladder, at an inclined plane.. then why we didn't take it's component like mgcos@ and mgsin@ ?

    • @MichelvanBiezen
      @MichelvanBiezen  10 месяцев назад +1

      Without seeing a picture, we cannot really answer the question satisfactorily. But for a force pushing against a sloped plane, you would want to calculate the two components (perpendicular and parallel to the slope). But for a ladder pushing against a vertical wall, there will only be a perpendicuar component when there is no friction and both horizontal and vertical components when there is friction.