52:00 Here's the easier method... Take ratio of T=√(2H/g) and T - 0.5 = √(2×81/g) We know value of H and so we can find T.. by putting T in any of the equation, we can get g...
Isse easy ye h ki do equation bnao s=ut+1/2at² vali, ek full 100m ke liye aur ek 81m ke liye. Dono ko divide krke t ki value a jayegi. Usko simple s=1/2at² me dalo a 8 aa jayegi
16:40 relation writting btw H and u 23:00 relative position ke graphs 47:00 diff planet ki gravity 1:15:00 perpendicular kb hogi velocity 1:23:00 relative velocity 1:26:00 horizontal landing on an inclined plank
11:45 ithink there is a smart way also from given graph dv/dx is -ve and x and v is +ve as they r in 1st quad So a=vdv/dx Hence a is -ve and x is +ve from given graph D is correct 💯
at the question which was discussing at 52:52 if we make equation of s from 100 and s from 81 m and then individullly divide them then we can get the value of t easily and then we have to put it in any one of 2 equations and it would give 8 without approximation as the correct answer
@@AyanAttar-uh8bc100=1/2gt^2 81=1/2g(t-0.5)^2 Take ratio 1/2 g will cut And take root on both sides 10/9 = t/t-0.5 Solve we get t = 5 s Put t = 5 in 100 = 1/2gt^2 You get g = 8
Sir I would suggest you ki aap iss batch me sabse pehle 12th ke chapters kra dijiye...kyunki wo lectures hme boards me bhi kaam aajayenge...Nhi to abhi 11th ke chapters pe dhyan dene me problem aayegi..kyunki boards aachuke hai....please sir help in this
1:09:00 Here We Can Use Simple Method:- initial velocity=u Distance=R t1.t2=? Sol= t1=√2h/√g=√2R/√g Same as t2=√2R/√g Product of t1.t2= 2R/g Ans. Is This Right😊
36:33 THIS POINT SIR DIDN'T TAKE T¹=180/50 HE TOOK 120/50 CAN ANYONE CAN EXPLAIN ME 👀👀 I THINK 💬 HE MADE MISTAKE. HE SHOULD ALSO TAKE DISTENCE 180m IN FIRT CASE👎👎
At 41:06 the qn can be solved very easily by doing differentiation. V=a+ 2bt-3t^2c a=2b-6t=0. 2b=6t. t=b/3 V=a+2bt-3t^2 Bu putting t=b/3c we get V=a+2b×b/3c-3×(b/3c)^2 V=a+(2b^2)/3c- (3b^2)/9c V=(9ac+6b^2-3b^2)/9c V=(9ac+3b^2)/9c V=a+b^2/3c and
Sir Gravity near planet vale ques me 2 eq bna skte the one for complete motion and second for t-0.5 seconds as displacement was known and uske bad divide kr dete toh very easy Calc se solve ho jaata
Sir agar 11+12 ke mix chapters ke saath karate to hum boards ke sath 12 ke kuch ache jee mains ke liye lga lete aur jab boards khatam hota to phir 11 wale chapters ke sawalo ko laga lete kyuki abhi main focus toh boards pe hi ha..............BTW thankyou for thi agar possible nhi hai to koe baat nhi yeh bhi thik hai thankyou again🤍🙏🙏
Sir ball dropped from top of 100m tower vale question me [√200-√162]2=√g tha tab √200-√162=10√2-9√2 lekar √2 comman nikale to 2√2 bachega aur uska squre complete g= 8 m/s milega😊
Sir in question at 45:43 kya apan area nikalne ke liye aise nhi kr skte ki .. Positive me jo trapezium ban rha hai usko todle te h do traingles and ek rectangle type mein then Us Pehle triangle ka Area nikale {1/2(b)(h)} se then aise hi beech ke rectangle h uska area nikale {length x breadth} Krkr then agle traingle ka wapis se {1/2(b)(h)} karkar then neeche Wale triangle ko Jo negative mein hai use bhi solve kroge .. to ajyega na ? Lekin mera ans nhi aa rha me kya glt kr rha hu😢 12.99 aa rha mera to 😅
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Sir it showing wrong batch
Last question answer is, c =15m 1:36:16
52:00 Here's the easier method...
Take ratio of T=√(2H/g) and T - 0.5 = √(2×81/g)
We know value of H and so we can find T.. by putting T in any of the equation, we can get g...
🎉v nice bro
yeah same I did bro
Who's gonna learn so much formulas for this silly que.
yeah but that's concept not formula
@@Chuslimkadada69
me too @@dogeman0719
at 36:07 the ratio of t2 will be 180/110
yess, i was searching for this comment...😅😅
Ha
Yess
Bhai maine 7 baar repeat karke dekha mujhe laga mujhe samajh nhi ayaa😂
@@ShaanYadav09 lol🤣🤣🤣
50:42 Write √200 = 10√2 & √162 = 9√2 for easier calculation
Isse easy ye h ki do equation bnao s=ut+1/2at² vali, ek full 100m ke liye aur ek 81m ke liye. Dono ko divide krke t ki value a jayegi. Usko simple s=1/2at² me dalo a 8 aa jayegi
@@mr-lacker😮
thank you, calc was easier with this.
source : marks app 😅
@@mr-lacker
@@mr-lacker same !
at 51:26 we can make calculation easy
2[/200 - /162]
2[10*/2 -9*/2]
2*/2[10-9]
2*/2 = /g
squaring both side
4*2=g
g=8
/ represents underroot
Correct bro.. 👍👍
( √- available hai na😅 )
16:40 relation writting btw H and u
23:00 relative position ke graphs
47:00 diff planet ki gravity
1:15:00 perpendicular kb hogi velocity
1:23:00 relative velocity
1:26:00 horizontal landing on an inclined plank
Thanks bro
Yeah TQ uuu bhai
🎉
21:03 21:09 21:10 21:10 21:10 21:10 21:10 21:11 21:11 21:11 21:11 21:11 21:11 21:12 21:13 21:13 21:14 21:14 21:14 21:14 21:14 21:14 21:15 21:15 21:15 21:15 21:16 21:16 21:16 21:16 21:16 21:16 21:17
thankyou bro very much
Imp ques
11:46
16:19
21:57
31:02
43:59
46:44
52:28
1:17:40
1:22:40
1:26:20
1:34:33
Bhai 44:05 me to ans 11m ana chhaiye na
Sir at 36:23 you put the value wrong T1= 180/50 not 120/50 please check
Exactly 💯
4:24 faster way to crack question is by using v2-u2=2as(as acceleration is constant) by selecting any two points on the graph.
Hmm i also solve in this way
Please tell me how to solve using v2-u2 formula
Consider AB | v2 is 60 then u2 is 40 s is 10 | so use the formula to get a as 1@@Rosiejane918
Rj sir on 2021 and Rj sir on 2023 is like a day and night difference, from funny and smart to mature and intellectual 💟..... love u sir 💟
Happy with the change...
But also misses the old one...
He is still funny in 2024 btw.
Not that nuch he used to be@@APSingh-ce2fg
Question 1) 4:31
Question)2) 8:54
Question 3) 11:46
Question 4) 16:20
Question 5) 21:57
Question 6) 31:02
Question 7) 36:43
Question 8) 41:17
Question 9) 44:04
Question 10) 46:06
11:45 ithink there is a smart way also
from given graph
dv/dx is -ve
and x and v is +ve as they r in 1st quad
So a=vdv/dx
Hence a is -ve and x is +ve from given graph
D is correct 💯
the how could you tell the diff btw option c and d
at the question which was discussing at 52:52 if we make equation of s from 100 and s from 81 m and then individullly divide them then we can get the value of t easily and then we have to put it in any one of 2 equations and it would give 8 without approximation as the correct answer
please bro can you write the answer in comment
@@AyanAttar-uh8bc100=1/2gt^2
81=1/2g(t-0.5)^2
Take ratio 1/2 g will cut
And take root on both sides
10/9 = t/t-0.5
Solve we get t = 5 s
Put t = 5 in
100 = 1/2gt^2
You get g = 8
Let's rock pwians 🫡
Most awaited series has been started 💥🫶
Last question ans is 15 ?
Yessss🎉
@@aaliyasiddiquewe must join in same IIT
😅
@@krishnateja3419
@@krishnateja3419 💀
Sir I would suggest you ki aap iss batch me sabse pehle 12th ke chapters kra dijiye...kyunki wo lectures hme boards me bhi kaam aajayenge...Nhi to abhi 11th ke chapters pe dhyan dene me problem aayegi..kyunki boards aachuke hai....please sir help in this
Pehle modern aur ray/wave optics .... karani thi boards +dropper +mains +advance sab cover ho jati🤔
Yrr tum log sab bigad gaye ho !! Itna bhi kya, ab boards pe hi dhyaan dena hai, usi ka krlo, 75% se ooper aane chahiye
No need
@@princeclassen bhai agr fir nta ne nayi guideline bna di ki 80 percentage chaiye fir ??? Fir kya kroge
BOARDS KE LIYE ITNI JEE KE QUESTIONS KARKE KOI FAAYDA NAHI, BOARDS MEIN ONLY DERIVATION AND DIRECT FORMULA BASED QUESTIONS AAYGA
Questions starts 4:21
Hmm
But those 4 minutes are also imp
@@panditG0078 exactly
Kitne questions krwwye gye hai
@@anjaliordinary1232 19/20
This question 1:21:21 can also be done by using the concept of (-b/2a,-D/4a) to find H max.
PW TEAM PLEASE MAKE A PLAYLIST FOR THIS BATCH ❤️ SO THAT LECTURES ARE ARRANGED
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chutye ghla ghlaya chahiye sb
This is the Last chance to crack JEE mains 2023 🔥 otherwise you have to wait for JEE 2024 😶
😮
Jee nikla ya nahi aapka
@@SYCHIC96 mains nikal gya but disqualified in advance by just 3 marks 🥺💔😭
@@Krishna.Kumar.1 It's okay bro pehla attempt tha ya dusra
@@SYCHIC96Dropper the 💔
How easy life becomes when there is no choice left 💔
Very true 💕🚩
Very true 🇮🇳
👁️👄👁️
7:20 Method 2 (Imp Pt)
9:20
11:50
16:30
22:10
47:50
56:30
1:1:40
1:7:00 Imp Concept
1:10:00
1:17:50
1:26:20
at 36:34 the ratio of t2 is 180/110
Exactly
Yeah, and the t1 = equal to 180/50, sir wrote it 120/50 which is wrong ××
Ans will be same😮
How?@@GarenaFrEeFiRe-ke7qb
1:09:00 Here We Can Use Simple Method:-
initial velocity=u
Distance=R
t1.t2=?
Sol= t1=√2h/√g=√2R/√g
Same as t2=√2R/√g
Product of t1.t2= 2R/g Ans.
Is This Right😊
36:33 THIS POINT SIR DIDN'T TAKE T¹=180/50 HE TOOK 120/50 CAN ANYONE CAN EXPLAIN ME 👀👀
I THINK 💬 HE MADE MISTAKE. HE SHOULD ALSO TAKE DISTENCE 180m IN FIRT CASE👎👎
Bro sir forgot to add 60 but still answer is same after adding 60 because train have to cross 180 metres ultimately
1:01:20 eqn of trajectory question
1:13:28 imp question
1:17:51 again trajectory question
36:18 sir t1 180/50 tha? Pls check
If I am wrong any pls correct me
Aa ji sunte ho yaha koi 2025 me jee dene vala hai kya😂
Ha bhaiya
Haanzi 😢❤
Ass...pirand
@@NOTHINGvy 😭
36:17 sir T1 is 180/50 not 120/50
but your ans is correct
8:34 : if V² vs x graph is St.line then acc=m/2 ( m=slope=tan theta)
Sir water drop question can be solved by Law of Odd ratio...12:37
1:31:58 15 degree pr bhi wo 10 m pahle girta
Aur 45 pe max range pe 10 m zyada
To ans 45 aur 15 ke beech me hi hona chahiye so 30 degree should be ans
LAST QUES OPTION C) 15 m
#99%tile IN 2nd ATTEMPT 🎯
Can u send solution pls
48:16 , use v2=2 as, s=(v+u)t/2, minimal calculation was applied
Thanks for new course BOOSTER💗💗.
thanks PW team !!
Ans of last qsn is 15m
Thank you sir ❤️☺️ I was to do majority of them very easily confidence pump hogya 🔥
haann
RDJ❌ ONLY RJ ✅
Anyone from ARJUNA 1.0 2025
me
Sir at 35:58 the length will be 180 as the previous case, you have said it but wrote it wrong,please correct it
Yes 👍 bro
At 36:07 distance will be 180 instead of 120
120 hi hoga max hi to hota hai❤❤
Thanks sir itna badia padhane ke liye ❤️❤️❤️❤️
11:53 here in the water drop's question, it can also be solved using Galileo's law of odd numbers
Bhai itna dimaag kyu lagana jab direct solve ho gya 1 min Mai hi
@@Coconuttree156 are Jo Mai keh raha hu usse zada jaldi solve ho jaega... Mushkil se 30 sec...
@@chintapakdamdum koi nhi bhai method koi bhi ho question solve hone de matlab hai , bss agle mains mai 99+ percentile lana hai kaise bhi 😤😤
@@Coconuttree156 kushwaha jinka surname hota hai unka josh jldi khatam ho jaata hai
@@tus237 faaltu baat Matt kar bhai yahan par 2nd attempt ke baad dekhte hai kisme kitna Josh hai
At 41:06 the qn can be solved very easily by doing differentiation. V=a+ 2bt-3t^2c
a=2b-6t=0. 2b=6t. t=b/3
V=a+2bt-3t^2
Bu putting t=b/3c we get V=a+2b×b/3c-3×(b/3c)^2
V=a+(2b^2)/3c- (3b^2)/9c
V=(9ac+6b^2-3b^2)/9c
V=(9ac+3b^2)/9c
V=a+b^2/3c and
99%ile + Fixed👍❤❤🤟🤟
aagai ky😂
22:11
53:06
31:56 isme opp me velo. lga kr kisi ik body ko rest pe le aao
1:00:00
1:07:57
Amazing lecture👌👌
Considering u=0 if we find acceleration then putting value in v=u+at .....we can get the answer 43:00
36:25 par sir aapne 180 ki jagah 120 kyu likha hai?
Yes
For revision:- 16:25
41:13
1:13:36
1:26:05
52:30 par calculation easy bhi ho sakti thi sir agar ham √2 common le le.
Thanks for concept ...
Sir Gravity near planet vale ques me 2 eq bna skte the one for complete motion and second for t-0.5 seconds as displacement was known and uske bad divide kr dete toh very easy Calc se solve ho jaata
Uska answer 800/81 ≈ 9.8 aa raha haina ??
No 8 aa rha h bhai
10/9=t/t-0.5
@@deepanshudahiya8966 ya ya my mistake 0.5 ko 10/9 se multiply karna bhul Gaya tha 😅
ThankQ so much sir, 💓
sir on question 6 their is just a slight mistake answer is correct but by mistake you wrote 120 instead of 180 we will correct it Thankyou sir🙏🙏🙏🙏
Yes
Bohot yaad aa rhi h aapki, lakshya batch mein zaroor aana 🤩🤩
Arjuna's Mark attendence here😄.
Arjuna1.0❤
2.O
But i am in class 9th
Telegram 😂
No
Need more like this same for mathematics. Currently I am in 11th
Sir aap 52:30 pe aap 10√2 -9√2 se kar skte the to make calculations easy
As we know that we are droppers 🥺 so we have tu prove our potential ❤️
My 83 percentile can I scroed 98 percentile in 2nd attempt class 12 students
@@AshishSingh-bf1ux NO
@@AshishSingh-bf1ux yes
@@AshishSingh-bf1ux no
@@AshishSingh-bf1ux nope
1:17:35 sir small mistake velocity puchi thi . So D is correct
Time pucha h dhyaan se pdo
sir i got 98.4 %ile from prayas 3.0 thank u to whole team of pw
i also got 98.42 what should we do now i am confused?
Do for advance
@@sujalmadaan2389itna %ile laane waala person kabhi confused ni ho skta usko uska path clear cut dikhai dera h
Means u r lying
@@Shilpy-hc5ly i'm literally a iitd student now
❤
I got 82 percentile
Nd I will try my best to hit 97+ percentile
I'm not getting pdf of this if somebody got then please tell where is it? In app this series is not there rank booster
Manzil legend or manzil 2.0 + this batch = 97+% and I follow it blindly sir ,promise 🙏🏻🙏🏻🙏🏻🙏🏻🥰🥰🥰
Teri aagyi bro 😂
@@nishamanral9658 aagyi mam ,
98.08 percentile 31 Jan shift 2
Sir agar 11+12 ke mix chapters ke saath karate to hum boards ke sath 12 ke kuch ache jee mains ke liye lga lete aur jab boards khatam hota to phir 11 wale chapters ke sawalo ko laga lete kyuki abhi main focus toh boards pe hi ha..............BTW thankyou for thi agar possible nhi hai to koe baat nhi yeh bhi thik hai thankyou again🤍🙏🙏
Sir please upload schedule in which chapters name are mention so we can prepare for their theory
@@thestranger7820 Schedule mai chapter ka name nhi likhte ye
nhi to lecture se pehle uss chapter ko revise kr le
@@thestranger7820 thanks
Sir 36:30 par 60 add nahi kiye?
Ha krna tha
Sir ball dropped from top of 100m tower vale question me [√200-√162]2=√g tha tab √200-√162=10√2-9√2 lekar √2 comman nikale to 2√2 bachega aur uska squre complete g= 8 m/s milega😊
NEET Student attendance here 😊🙋🏻♀️
thankyou sir this is really help for the question practice in the jee journey
RJ sir is the JAM of PW
abe anpadh jem hota hai
@@sandarbhpandey5160 gawar gem hota h jem nhi😂🤦♂️ dusro ko bolne se pehle khud ko dekh😂😂
@@aadityagaming2704 😂😂😂😂😂
@@aadityagaming2704 💀🤣
@@aadityagaming2704 tit for tat for him
50:00 sir waha pas.. seedha √162= 9√2 ayga or 10√2-9√2 = √2 ho jayga..😊
Is me hai 19m covered to 81m hoga ground se. But sir ne 19m likha hai.
36:15 sir here you have done a blunder....
21:09 n²u²g-2nu-2hg² hoga agr mai sahi to like ❤and support guys😅
Is there any mistake at 36:24?
Yes
𝐏𝐇𝐘𝐒𝐈𝐂𝐒 𝐖𝐀𝐋𝐋𝐀𝐇 𝐎𝐓𝐇𝐄𝐑 𝐘𝐎𝐔𝐓𝐔𝐁𝐄 𝐂𝐇𝐀𝐍𝐍𝐄𝐋𝐒 :
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1:02:05... बहुत अच्छे से समझ आया ... 🙃🙃
Thank you so much sir ☺️
Sir in question at 45:43 kya apan area nikalne ke liye aise nhi kr skte ki .. Positive me jo trapezium ban rha hai usko todle te h do traingles and ek rectangle type mein then Us Pehle triangle ka Area nikale {1/2(b)(h)} se then aise hi beech ke rectangle h uska area nikale {length x breadth} Krkr then agle traingle ka wapis se {1/2(b)(h)} karkar then neeche Wale triangle ko Jo negative mein hai use bhi solve kroge .. to ajyega na ? Lekin mera ans nhi aa rha me kya glt kr rha hu😢 12.99 aa rha mera to 😅
4:52 graph problem
9:18 graph problem
11:59 good question
23:33 best questions
Sir i got 98 percentile in jee mains 1 st attempt promising to get 99.5+ in 2 nd
Need your blessings 😊🙏
Bro you have gone for selected chapters or for whole syllabus, as you have got nice percentile
ho gya bhai apka selection to agle saal muje bhi dena hai abhi 11th mei hon🙏
Bhaiya kitne percentile Bane aapke 2nd attempt me ?
2nd attempt me kitne aye apke?
51:43 we can take 1.41 as
Square root if 2 for easy solving
Sir I promise you that I will score 99% in 2nd attempt guaranteed 🔥🔥🔥❤️❤️
1st attempt mein kitna aaya tha
Aur Arjuna jee se kiya tha kya 11th
Hi bro fir Kitna score kiya in 2nd attempt??
ktine bane bhaiya?
pehele ling chus ( bhai tu choti jat sc/st hai na tabhi bol raha hai gamdu)0
Mr ⭐ jordar rj sir ♥️♥️♥️
Mein neet mein hu lekin jee ke questions sirf 1min mein kar dikhaya
Mr⭐ rj sir♥️😘
Crct brdr.....2nd question me ratio se question 10 sec me ho gya....think without ink
Finally..😃😃
Thank you so much
Jindal JEE 😃
Love you sir
Thanks for this series 😍
4:21 Questions start from here
25:23 57:04 1:11:46 1:15:01 1:25:20 1:20:22
52:00 Wale question ka ek easy method bas A TO B point may v = u + at lga do
I am a Neet aspirant but I am solving all q of this series to clear my concept
💩
@@karn755🤪
Last question 1:36:15 answer is B(15m)
Thanks sir ji ❤️🔥❤️🔥
at 30:56 quadratic me a ki value negative hai is karan downward parabola banega aisa bhi kah sakte hai
Missing you sir
From Arjuna jee 1.0 ❤️🔥❤️🔥❤️🔥
Will meet you again in lakshya sir ❤️😌
Last ans option c 15m
Thank u sir I am from lakshya batch but I follow percentile booster❤️❤️❤️❤️❤️
46:55 starting point for second day.
sir you are a legend , i understood everything because of you !
No sir theory ham batch ke note se kr lenge aap acha acha question krye 👍❤️
Sir 36:37 ye wrong hai maine kitni baar try kiya but kya bole to bole kya😂😂😂
I am a neet aspirant but answered every question with ease
To jee do
So?
1:36:14 Ans (c) 15m
Thank you very much sir...all concepts are cleared ♥️♥️♥️