Alright. Not bad. I did follow but with 5V on the Vcc, and got Vc around 2.5V …. Now idea is to apply 0-3.3V via capacitor to base so it be -1.65 to 1.65V audio wave from DAC., boost it to 5V (can do 9V if necessary), then drive 1W 8ohm speaker. I’m assuming this stage boosts voltage, then will need current boosting stage.
yes, this type of circuit boost the voltage. think of it as a pre-amplifier. To drive a speaker, you need to boost the current, not really the voltage. Commonly referred as power amplifiers. If you do audio, you may want to look at op amps for boosting the voltage to proper level before your power amplifier.
Sorry i went a bit fast there. You have two equations for two unknowns. Using first eqn, you can express one of the two unknowns as a fumction of the other and you plug that expression into the second equation. It was not done in my head but on paper. Hope that helps
Can you please explain a bit more as I am struggling to see this. Also if I take R1 // R2 = 10k using your values I get 9200 is this correct. @@electronicsainteasy5253
It doesn t have to be 1 volt, really. What s important is that the 3 resistors, that is, the two in the voltage divider and the one in the emitter leg make the setup stable wr to beta, that is, changes to beta don t affect the bias voltages. I think i will makd a video of why it is so.
Love it... great talent explaining the subject at hand
Thank you so much for the comment.
Excellent explanation! Very helpful.
Thank you for your comment. Well appreciated.
Alright. Not bad. I did follow but with 5V on the Vcc, and got Vc around 2.5V …. Now idea is to apply 0-3.3V via capacitor to base so it be -1.65 to 1.65V audio wave from DAC., boost it to 5V (can do 9V if necessary), then drive 1W 8ohm speaker. I’m assuming this stage boosts voltage, then will need current boosting stage.
yes, this type of circuit boost the voltage. think of it as a pre-amplifier. To drive a speaker, you need to boost the current, not really the voltage. Commonly referred as power amplifiers. If you do audio, you may want to look at op amps for boosting the voltage to proper level before your power amplifier.
I can't see the jump to the value of R2 at 30.48 time mark. What did you compute in your head to get that?
Everything else flowed well.
Sorry i went a bit fast there. You have two equations for two unknowns. Using first eqn, you can express one of the two unknowns as a fumction of the other and you plug that expression into the second equation. It was not done in my head but on paper. Hope that helps
Can you please explain a bit more as I am struggling to see this. Also if I take R1 // R2 = 10k using your values I get 9200 is this correct. @@electronicsainteasy5253
Hi, what's the reason for assuming Ve = 1V for temperature stability?
Good question. I don t know
I have never seen it explained.
It doesn t have to be 1 volt, really. What s important is that the 3 resistors, that is, the two in the voltage divider and the one in the emitter leg make the setup stable wr to beta, that is, changes to beta don t affect the bias voltages. I think i will makd a video of why it is so.
Good explanation
Great work
Thanks a lot for the comment!
Should get larger white board.