love the way you explain, I'm uni student in uk. I'm following your method and showed few questions to my professor ( integration) and he was shocked as I solved the question in 20 seconds which rest of the students took around 7 to 10 minutes.
This beautiful trick, like your various other tricks saves so much of calculation time, now I can't stop using them to solve lengthy questions in fraction of time!!! Mind blown!!! Thanks a million for your efforts!!!
Realy it goes magical trick... Waoooo😃... So DIY ans is.... y(x/(x²-1)+5/(3x+7)-4x/(3x²+9)).. Hope it will be right one.. Tysm for this wonder full trick mam... ❤❤
I really took 6-7 second to solve this. You are a very good teacher. Maths will become a very interesting and beautiful because of teachers like you. Thanks a lot for explaining tricks and concepts in maths so enthusiastically.
Thankyou mam this is so easyt o learn and the techniques are very good and i m preparing for nda through ur videos and yes i feel myself confident that i can clear nda in 1st attempt..🙏🙏
It literally took 5 seconds to solve the ans Y{(x/x^2-1)+(5/3x+7)-(4x/3(x^2+3)) Mam by watching your videos i think that i didnt want any professor or teacher to learn this much about maths No one in this world can beat your short tricks And i am sure that i will be pass any exam in my life especially maths by using your short tricks Thank you mam so much for supporting us You are really a GOD WOMAN THANK YOU MAM WE ARE ALWAYS THERE TO SUPPORT YOU
For those who want to know how dis method works..write 'y' in exponential form and differentiate..i always used to solve dis way.. Btw thank u mam fr the video..
Thank very much ma'am for creating such a fabulous content. Its 5 years since you posted this but still it's such a novel solution that it's being required by many of us JEE aspirants now. Solving the last qn took me 30 seconds... I need to improve my time by a lot but still you videos have helped me so many ways that i can't even explain... Again , Thank you.
Really maam your video is too gud... It got relief from too long way of solving..... From past 3 years to now 2021-22 boards... Really vry healpful.. Becoz only 90 min r given to us and lots of question r given .... Your short tricks vry vry awesome.... And you also the awesome maam.... .. God always bless u.. 😇😇😍😍lots of happiness in your life 🥳🥳
Hello Neha Mam answer to the DIY question is y'=y(2x÷2(x^2-1) + 15÷2(3x+7) -4x÷3(x^2+3) A good teacher is a master of simplification and an enemy of simplism.
I am a neet student, but iam preparing for KEAM . Since maths is compulsory for engineering stream, I am familiar with the basics of calculus in physics.When I refered to past papers, such calculus problems are seen and these seems to be a boon for us . AND NOW ITS SUPER EASY .THANK YOU MAM.
GREAT VIDEOS!! However, please omit using the symbol "x" as a multiplier. Again thanks, and I have been looking far and wide for Nth derivative techniques.
y1/2*2x/x^2-1-5/3*3/3x+7/2/3*2x/x^2+3....................that's it ma'am.....that was amazing ma'am....you make me so easy to do this ... thankyou so much ma'am....bye bye ma'am...........it took 7 seconds...
Its done by taking the logarithm Since we know that logarithms separate the multiplicative functions into addition And divisions into negative Then she took the derivative of ln(fx) Which will be simply writing 1/f(x)*derovative of fx
love the way you explain, I'm uni student in uk. I'm following your method and showed few questions to my professor ( integration) and he was shocked as I solved the question in 20 seconds which rest of the students took around 7 to 10 minutes.
Jk
Wow
Wow
Joke...🤣🤣
Wow
Y' = y(x/x^2 -1 + 5/3x+7 - 4x/3x^2+9)
And I took me 4-5 seconds to get the answer.... loved this trick
Yes bro
A good teacher is a master of simplification and an enemy of simplism.
Well said
This beautiful trick, like your various other tricks saves so much of calculation time, now I can't stop using them to solve lengthy questions in fraction of time!!!
Mind blown!!!
Thanks a million for your efforts!!!
Realy it goes magical trick... Waoooo😃... So DIY ans is.... y(x/(x²-1)+5/(3x+7)-4x/(3x²+9)).. Hope it will be right one.. Tysm for this wonder full trick mam... ❤❤
Hii
answer to boht sahi hai
Nice trick
THIS TRICK IS JUST BEAUTIFUL LIKE YOU ANGEL ❤️❤️❤️♥️♥️
Hey.🥰
WOW!!! You can write with both Hands that also with good handwriting 👌
My Expessions before seeing this video 🤔😕😭😵🤢🤕🤒. But my Expessions after seeing this video 😱😳😝😂😆😚🤗😇. Got MATHEMATICALLY INCLINED!!!.
This is my first video of this channel and it is really helpful....i'm so greatful of you..✨️❣️....
U r first maths teacher in my life to speak English so fluently
I really took 6-7 second to solve this. You are a very good teacher.
Maths will become a very interesting and beautiful because of teachers like you. Thanks a lot for explaining tricks and concepts in maths so enthusiastically.
Wow mam u r writing with both hands....
It is a part of logarithmic differentiation. And you make this more simpler great 👍
Let the magic begain is CLASSICALLY neha mam goated
mam answer for diy is y[1/2*2x/x square-1+5/3*3/3x+7-2/3*2x/x square +3
You are the awesome menter I ever saw for teaching tips 😍👌👌🌹🌹🌹🌹🌷🌷💐💐..... I am a big fan of your voice mam..........
I love your tips a lot mam..... ❤❤
Mam this technique is very nice and you are genius so mam I request you made a more and more videos for us
Y{2x/2(xsquire-1)+15/3(3x+7)-4x/3(xsquire+3)}❤
Ans is ...
Y(1/2(x^2-1)×2x+5/2×3/(3x+7)-2/3×2x/x^2+3
Magicalll....
Time taken only 8.33sec
Mam...it is a super duber trick...really....so helpful specially with the new pattern of cbse...🥰🥰🥰🥰🥰🤩🤩
Mam please make vedios on straight lines and circles
MAM IT TOOK JUST 5 SEC AND U R VERRY INTELLIGENT,,, SO PLEASE CONTINUE ADDING MORE VIDEOSSSSS...... AND STAY BLESSED..
Within 10 secs mam ans is
Y'=y[x/x2-1+5/(3x+7)-2/3(2x/x2+3)]
Excellent trick mam ur amazing!!!
1/2 2x/(x^2-1) + 5/3 (3/ 3x+7) - 2/3 2x /(x2+3)
Thankyou mam this is so easyt o learn and the techniques are very good and i m preparing for nda through ur videos and yes i feel myself confident that i can clear nda in 1st attempt..🙏🙏
It literally took 5 seconds to solve the ans
Y{(x/x^2-1)+(5/3x+7)-(4x/3(x^2+3))
Mam by watching your videos i think that i didnt want any professor or teacher to learn this much about maths
No one in this world can beat your short tricks
And i am sure that i will be pass any exam in my life especially maths by using your short tricks
Thank you mam so much for supporting us
You are really a GOD WOMAN
THANK YOU MAM
WE ARE ALWAYS THERE TO SUPPORT YOU
Ya it literally took 5 seconds
I am weak for English but your sound and teaching style is too good
Weak in english **
This shows that u aren't lying😂
Ekk hii toh dil hh❤️
Kitne baar jeetenge mam🙌🏻
For those who want to know how dis method works..write 'y' in exponential form and differentiate..i always used to solve dis way.. Btw thank u mam fr the video..
Y(1/2 × 2 by x square - 1 + 5 by 3 × 3 by 3x + 7 - 2 by 3 × 2 by 3 × 2x by x square plus 3 )
Ur way of teaching is fab . It helps me understand x10 time faster . Thanks maam for it .☜☆☞
Y{1/2*1/x2-1*2x+5/3*1/3x+7*3 -2/3*1/x2+3*2x}
Jus 8 secs..Thankuu so much Mam..❤
Mam great trick!!!!just keep on inventing such super tricks to help us...😀😃
Mam you are the best math teacher👍👍♥️♥️...I hope that everyone gets such talented teachers🥺🥺♥️♥️
Well u r one of my favorite guide for rising guys... 🎉🎉💐
Thank very much ma'am for creating such a fabulous content. Its 5 years since you posted this but still it's such a novel solution that it's being required by many of us JEE aspirants now. Solving the last qn took me 30 seconds... I need to improve my time by a lot but still you videos have helped me so many ways that i can't even explain... Again , Thank you.
Mind-blowing tricks simply WOW 👍
Mam you are genius.I do not have a word for your talent
my respect for you is increasing day by day ma'am ❤
Wow u can write with both hands amazing. Nice trick for differentiation. I wish i could have watched this video before my exam which was yesterday
Ans is y(1/2×2x/x^2-1+5/3×3/3x+7-2/3×2x/x^2+3) Thank you😊
Really maam your video is too gud... It got relief from too long way of solving..... From past 3 years to now 2021-22 boards... Really vry healpful.. Becoz only 90 min r given to us and lots of question r given .... Your short tricks vry vry awesome.... And you also the awesome maam.... .. God always bless u.. 😇😇😍😍lots of happiness in your life 🥳🥳
By the time you were introducing the question I solved it .
It was super quick.
Thank you ma'am.
Your teaching skills are magical
Wish I had seen this before completing derivatives chapter but thanks mam it will help me a lot... You are great
Neha you are the great Teacher
Very useful and really magical formula
I always see your all shortcut tricks
Thank u mam.
Thnx ma'am you will clear my iit Jee in these tricks
Ans: y{x/(x^2-1) + 5/(3x+7) - 4x/3(x^2+3)}
Ans is change the +5 to +15 becaz u forget to differentiate (3x+7) it give 3 and multiple by 5. And u get 15
Now I apply this in ncert question and get answer same .really it is very good. Wow
We can't spell awesome without u mam😊 super trick.it took me 2seconds to do. Thx mam🤗🤗
Thank you ma'am 🙏🏽
Thank you so much mam for your super.....magic tricks ❣️❣️😍🙏🙏
Better tricks... Mam... By the way... Today is happy mother's Day.... Wish u... With all the hearty blessings
Iam very excited to apply your tricks ma'am.Thank u.......😊😊😊😊😊
very very nice trick mam l love you so much.Thank you.
I took only 7 seconds to solve this DIY.
y' = y ( x/x^2-1 + 5/3x+7 - 4x/3x^2+9 ) - it hardly took 3-4 sec. !! super trick thank you soo much maam !!
Y'=y{1/2 2x/x²-1+5/3*3/3x+7-2/3*2x/x²+3}
Mera exam clear hua because of you mam u r such an amazing teacher
It took very less time to solve by using ur trick than normal method hats off to u mam... No words to speak about u...🤩🤩🤩🤩🤩
You are an amazing mathematics teacher?
Thank you neha...for wonderful tricks u have shown to us...for learning the maths in easier way
Hello Neha Mam answer to the DIY question is
y'=y(2x÷2(x^2-1) + 15÷2(3x+7) -4x÷3(x^2+3) A good teacher is a master of simplification and an enemy of simplism.
Mam literally no words... You are God gift to us...❤️❤️❤️ Thank you so much mam...🥰❤️❤️❤️
Im really spellbound by your works .im so blessed to see your videos .thankyou for all ur efforts mam.pretty damn good
Mam answer to the DIY question is
y'= y{1/2 *1/(x^2 -1) *2x +5/3 *1/(3x+7) *3 -2/3 *1/(x^2+3) *2x
Mam one video more with more difficult problem on partial fraction
it can be done by log method easily ,but this method is a great method
1/2*2x/x²-1+5/3*3/3x+7-2/3*2x/x²+3
I am a neet student, but iam preparing for KEAM . Since maths is compulsory for engineering stream, I am familiar with the basics of calculus in physics.When I refered to past papers, such calculus problems are seen and these seems to be a boon for us . AND NOW ITS SUPER EASY .THANK YOU MAM.
GREAT VIDEOS!! However, please omit using the symbol "x" as a multiplier.
Again thanks, and I have been looking far and wide for Nth derivative techniques.
thnx mam very much for making one of the most complex part of maths so easy and super fun to do.thnx mam very much again
Y{(1/2)(2x/(x^2-1)+(5/3x+7)-(2/3)(2x/x^2+3)}
Awesome ! Very thankful 😊
Y(1/2*2x/x^2-1+5/3*3/3x+7-2/3*2x/x^2+3)
I would always be bothering about the differentiation.but after seeing ur tricks it made me learn easier, thank u mam.
It take 6sec. only in differentiation and ans. is=y[{x/x²-1}+{5/3x+7}-{4x/3(x²+3)}]
y1/2*2x/x^2-1-5/3*3/3x+7/2/3*2x/x^2+3....................that's it ma'am.....that was amazing ma'am....you make me so easy to do this ... thankyou so much ma'am....bye bye ma'am...........it took 7 seconds...
Only 3 sec thanks for your tricks
Wow mam superb video etni acchi s tu hmare coaching m bhi nhi pdate
its just basically taking logarithm and solving in your head.....
Its done by taking the logarithm
Since we know that logarithms separate the multiplicative functions into addition
And divisions into negative
Then she took the derivative of ln(fx)
Which will be simply writing 1/f(x)*derovative of fx
Love♥️ from a neet aspirant
You are also good in vedantu but your channel is at other level
y{(x/x^2+1)+(5/3x+7)-(4x/3x^2+9)}
Diy y'=y(x/x^2-1+5/3x+7-4/3x^2+3)
Thanks a lot for making such amazing vedios
Really.....iam big fan of ur teaching
Thanku mam for this type of video which is much helpful for me
U always say the best tricks ma'am
I always look forward for more of your videos
I loved the video mam
Ur tricks are fabulous
Ans is y'=y {1/2 (2x/x2-1)+5/3 (3/3x+7)-2/3 (2x/x2+3)}
Solved in 7sc
Had solved in 7 sec
One of the best vedio you are just awesome and thank you so much for making such a useful vedio keep it up
Thank you maam nice trick.more use full for IIT JEE mains exam and other competitive exam
Thank u mam for this trick I had solved it in 5 sec
Wow mam it is very helpful for competition.
Ans for DIY is y{x/(x^2-1) + 5/(3x+7) - 4x/3(x^2+3) 👍
Mam,how did you practice to write in both hands it was awesome