5^3 = x^3 => x=5 full stop if we are looking for complex roots also, they are on the circumference of r=5 on the vertices of an equilateral triangle at an angle of 2 pi/3 and -2 pi/3 i.e. x = 5 (cos (2 pi/3) + i sin (2 pi/3)) and x = 5 (cos (-2 pi/3) + i sin (-2 pi/3))
Why do you make this so complicated? Given 5/x * 5/x = x/5: Multiply the terms on the LHS to get 25 / x^2 = x / 5 cross multiply to get x^3 = 125 bring 125 to the LHS to get x^3 - 125 =0 Now we have the difference of two cubes => (x - 5)(x^2 + 5x + 25) Easy and direct solution, no messing about with substitutions, and leading to the same solutions for x.
Перемножаем пропорцию:
(5/х)*(5/х)=х/5
5*5*5=х*х*х
125 = х^3
х = 5.
Yes why so complicated when the answer is obviously simple.
Because intuition is not a rational method.
5^3 = x^3 => x=5 full stop
if we are looking for complex roots also, they are on the circumference of r=5 on the vertices of an equilateral triangle at an angle of 2 pi/3 and -2 pi/3 i.e. x = 5 (cos (2 pi/3) + i sin (2 pi/3)) and x = 5 (cos (-2 pi/3) + i sin (-2 pi/3))
(5/x)*(5/x)=x/5
25/x^2=x/5
125=x^3
x=5
Answer is 5. I did it in my head😅
This guy knows how to BS folks.
x=5
You got only one of three solutions. 33% = F
Why do you make this so complicated?
Given 5/x * 5/x = x/5:
Multiply the terms on the LHS to get 25 / x^2 = x / 5
cross multiply to get x^3 = 125
bring 125 to the LHS to get x^3 - 125 =0
Now we have the difference of two cubes => (x - 5)(x^2 + 5x + 25)
Easy and direct solution, no messing about with substitutions, and leading to the same solutions for x.
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