Small mistake @1:33 you go from 8x^4-8x^2-x+1=0 to (8x^4-8x^2)-(x+1)=0. @2:15 you say "I factor out negative 1" but what you are actually doing is "factoring out". This is nonsense, of course, but by doing this you change (x+1) to (x-1), thus compensating your mistake @1:33 by a second mistake. The rest is OK.
I actually appreciate your contribution.But what happened was to group and then factoring out negative 1 was to make the factorization process easy.Otherwise, if 1 is factored out and the parenthesis is (x+1), the process will halt..So nothing was wrong but i appreciate your input.Thanks!!!
@@Christopherbigfish No. The last equation on the board @1:33 is wrong. Let x=1, which is a solution of the original equation 8x**4-8x^2-x+1=0. But x=1 is NOT a solution of (8x**4-8x^2)-(x-1)=0. Try it out: Substitute 1 for x into the last equation @1:33: 8 times 1^4 is 8, -8 times 1^2 is -8, x+1 is 2, 8 minus 8 minus 2 is -2, 2 is NOT 0. Do you see that the last two equations @2:15 are NOT equivalent?
Sir, like I said, I appreciate your contribution... Testing for the roots of an equation is not done that way... Factorization is to make two parentheses the same so that the process can flow.. Grouping it has altered the equation, the end product is the material objective.
My point, simply put, is that your derivation contains an error. The intermediate equation @1:13 is not equivalent to the original equation. This is because grouping an expression like a-b-x+1 as (a-b)-(x+1) is incorrect. Correct would be (a-b)-(x-1).
Sir, again with all due respect, factorization by grouping should give the same original expression when you distribute the parentheses or brackets after factoring.This question is an internal Olympics of Saginaw valley State University Olympics.It is correct nothing is wrong.This problem is actually a sub-part of a problem Sin π/10... The factorization is very correct.So you can fact check as well.If -(x-1) is used for someone who's not a math major the other term would be misunderstood.So long the factors when multiplied gives the original expression, it's unequivocally correct without any Again thanks for your insight, I appreciate you.
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Pls sir. Help me solve this
3^x + 4^x = 5^x
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Small mistake @1:33 you go from 8x^4-8x^2-x+1=0 to (8x^4-8x^2)-(x+1)=0. @2:15 you say "I factor out negative 1" but what you are actually doing is "factoring out". This is nonsense, of course, but by doing this you change (x+1) to (x-1), thus compensating your mistake @1:33 by a second mistake. The rest is OK.
I actually appreciate your contribution.But what happened was to group and then factoring out negative 1 was to make the factorization process easy.Otherwise, if 1 is factored out and the parenthesis is (x+1), the process will halt..So nothing was wrong but i appreciate your input.Thanks!!!
@@Christopherbigfish No. The last equation on the board @1:33 is wrong. Let x=1, which is a solution of the original equation 8x**4-8x^2-x+1=0. But x=1 is NOT a solution of (8x**4-8x^2)-(x-1)=0. Try it out: Substitute 1 for x into the last equation @1:33: 8 times 1^4 is 8, -8 times 1^2 is -8, x+1 is 2, 8 minus 8 minus 2 is -2, 2 is NOT 0.
Do you see that the last two equations @2:15 are NOT equivalent?
Sir, like I said, I appreciate your contribution... Testing for the roots of an equation is not done that way... Factorization is to make two parentheses the same so that the process can flow.. Grouping it has altered the equation, the end product is the material objective.
My point, simply put, is that your derivation contains an error. The intermediate equation @1:13 is not equivalent to the original equation. This is because grouping an expression like a-b-x+1 as (a-b)-(x+1) is incorrect. Correct would be (a-b)-(x-1).
Sir, again with all due respect, factorization by grouping should give the same original expression when you distribute the parentheses or brackets after factoring.This question is an internal Olympics of Saginaw valley State University Olympics.It is correct nothing is wrong.This problem is actually a sub-part of a problem Sin π/10... The factorization is very correct.So you can fact check as well.If -(x-1) is used for someone who's not a math major the other term would be misunderstood.So long the factors when multiplied gives the original expression, it's unequivocally correct without any Again thanks for your insight, I appreciate you.
Good job and presentation
Glad you liked it