the proof is flawless but for any triangle one should prove that the perpendicular bisector and angular bisector meet at a common single point ,and even if they meet they should meet inside the triangle (O) ,one has to prove that point O will be internal point always as it does not happen always ,even if it meets the foot of perpendiculars i.e D and E points should be internal to the sides of a triangle ,the whole proof will change accordingly and please note that for a equilateral triangle the perpendicular bisector and angle bisector and the altitude will be the same ,so there are infinite points according to you
Keep it high!!
Well done Bharat Teja the jack of maths
the proof is flawless but for any triangle one should prove that the perpendicular bisector and angular bisector meet at a common single point ,and even if they meet they should meet inside the triangle (O) ,one has to prove that point O will be internal point always as it does not happen always ,even if it meets the foot of perpendiculars i.e D and E points should be internal to the sides of a triangle ,the whole proof will change accordingly and please note that
for a equilateral triangle the perpendicular bisector and angle bisector and the altitude will be the same ,so there are infinite points according to you
Sir the last caption is truly awesome "where fixing flaws is a routine" I think your idea came when varun said that 0/0 = 1
i am an iitian and this proof looks convincing............. awed.......#bharathtejathegod
dear sir sorry i dont think it is SAS Congruence it is RHS congrunce