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I added the displace node, the node setup looks identical from what I can see, but the displace doesnt seem to have the desired effect whatsoever?

Select your flower, go to the materials panel, scroll down to settings, and change the displacement setting from bump only to displacement and bump.

Type log for base ten or ln for base e. So, for example, typing ln(x) would graph the natural log of x.

Go for it!

Add a torus and scale it down in the z direction.

@@3E8mps no, i mean the ring effect.

@@BlueTheCubeLegacy Use the node setup shown in the video. The trick is to plug a gradient texture into the vector input of a noise texture. I also included another noise texture added to the gradient texture to provide a bit of randomness. This setup can be seen at 3:30.

@@3E8mps but how did you make it at 1:59

@@BlueTheCubeLegacy The ring on the surface at 1:59 is just the shadow of the other ring.

The link still works - in the description there is a link to a ZIP file, you can download that.

Exactly! I simple clicked this link throw VPN to place me "from America" - and it downloaded! Thanks! I see that it is not exactly that I will do, but very interesting. I surprised how did you paint even rests and other complete signs by simple drawing lines, without images...

I'm not sure what you mean by black edges. Could you be more specific? Edit: wait, are you referring to the difference between the live preview and the actual render? The additional levels of subdivision in the adaptive subsurf modifier are present in the render and not in the live preview. Because of this, there are more polygons during the render, which makes the edges of the petals smoother.

@@3E8mps oh i see i didnt tick adaptive on my modifier. such a cool tutorial and method. thanks genius

In this version of Blender, after viewing from the camera, I pressed SHIFT+F and then used the W A S D keys to move the camera around before pressing ENTER to accept. In the current version of Blender, it is SHIFT + ~ (the little key above the TAB key).

Well, I've never used the wisp shader, but if you want to see the node setup that I used, there's a link to a video of it in the description of this video. It works with Blender 2.83, as I just now tested it. It doesn't use the principled volume but it gets the job done.

@@3E8mps thank you :)

I can't find it anywhere

Select your smoke domain. In the physics properties editor, the top section is called "Smoke." There is a number input called "Time" in that section. The word "Scale" is in the box itself. You just need to keyframe that property up or down to adjust the speed of time in the smoke simulation. If you want your simulation to always be in slow motion, then don't bother with keyframes and just keep the time setting permanently adjusted. Edit: These are instructions for Blender 2.7x. I don't know how different things are in 2.8.

@@3E8mps its now under "dissolve" in Blender 2.8. I love you so much, you gained yourself a new subscriber

Can you link me a video with good looking fire in blender?

Glad you liked it! I uploaded a time lapse as you requested, it's up on my channel now.

I'm not exactly sure what you're asking, but this is an old program, and I have a much newer one that is easier to use. You can find it here: vbgadgets.weebly.com/photon.html

thank you sir for your replay ,I write a program in vb6 that performs mathematical operations on mathematical functions , I have a problem ,which is the code needed to convert the input to mathematical texts,

Ah, I understand. You're wondering how to take something like "1+2" as a string and evaluating it to be 3. You'll need to do some research on using the MSScriptControl or "programming in .net on the fly." I used a script control, and article can be found here: docs.microsoft.com/en-us/previous-versions/visualstudio/visual-studio-6.0/aa227633(v%3dvs.60) To add the script control to your project, you'll need to add a reference to it first. In Visual Studio, click "Project", then "Add Reference", be sure to select the COM tab on the left, then scroll down to find "Microsoft Script Control 1.0" and check that box. Click OK and you're set to go. From there, you'll want read up on how to use a script control to evaluate expressions.

thank you sir for your answer, if the user want yo find the root of function ( say>>>> sin(x) ) , first i ask the user to input the function he want to find the root of it , he will write ( sin(x) ) in the ( input msgbox ) the problem i faced i cant write the suitable code in my program to make the program know which the function input and us it as y=sin(x), and recognize it as mathematical input not just a script ,i have a code that can find (( all )) the root of any function in any interval for 15 digit for example if the function is ( sin(x) )and for interval [0,20] the result is [3.14159265358979 6.28318530717958 9.42477796076937 12.56637061435920 15.70796326794890 18.84955592153870]

ahmed samawe Yes, to do that you'll need the script control. You will be using the Eval method from a script control to evaluate a string as a mathematical expression. To find the roots, you'll want to look up Newton's method or another algorithm to solve for the roots. In the script control's code, create a variable called x and then you will be able to feed "sin(x)" into the script control's Eval method.

You're welcome to download the source code provided on my website!

+Biken Kurmanova I just used a for loop to draw a few lines inside a picturebox. You should check out my new version of the program, though, on my channel. This one is quite old.

When fraction mode is enabled, Photon does its best to locate a fraction, irrational, or factor of pi that is equal to your calculated answer. And yes, it does this for any answer, not just the "famous" trig values.

3E8mps So basically, your telling me that it will have a for loop from 1 to ..... , take the square root one by one and try to divide the answer to see if the answer is rational ?

Hồ Ngọc Quang It's a bit more complicated than that, since it will also simplify something like "sqrt(9/5)" into "3*sqrt(5)/5" (basically it rationalizes the denominator). And I don't use a For loop, I use a While loop. Also, to speed up calculations, I only check for factors of perfect squares up to the square root of the given number, because numbers higher than that are redundant. This results in very fast code.