Видео

g.co/kgs/W1cFrnM

I would propose to modify this sheet to include b^2-4ac after you find c in the first iteration. Since it will be less than 0, take the square root of its absolute value and call it D. Now x3 can be shown in this sheet consisting of two parts. x3_real=x2-(b/2a) and x3_imaginary= -D/2a. In the second iteration x0 will be x1 from the first iteration, x1 will be x2 from the first iteration and x2 will be x3 which was just calculated. The function evaluation for f(x2) will involve complex numbers so the calculations would become a bit complicated. The same process would be repeated.

It might be a slip of the tongue. In the first iteration x0=0, x1=1, x2=4, we got x3=1.5055. In the second iteration, we will go in order as we have 0, 1, 1.5055, and 4 as values of the function. We must choose three values to find the better estimate in this iteration. We discard the first value (0). We choose x0=1, x1=1.5055, and x2=4 for the calculations in the second iteration. Alternatively, if we choose x0=1, x1=4, and x2=1.5055 according to what I have spoken then it would also not cause an error in the answer. We would get the same x3 value in this iteration. I hope it explains.

According to the statement of problem, expenses are only in the first 10 years and then in year 15 and 20 only.

@@arialcad matlab says it can't read Gaussnaive as a function because that's a local function. And even they say the function has same name with script. Nevertheless different name. Plz help me

You can try this script in your MATLAB. It should work. function x = GaussNaive(A,b) [m,n] = size(A); if m~=n, error('Matrix A must be square'); end nb = n+1; Aug = [A b]; for k = 1:n-1 for i = k+1:n factor = Aug(i,k)/Aug(k,k); Aug(i,k:nb) = Aug(i,k:nb)-factor*Aug(k,k:nb); end end x = zeros(n,1); x(n) = Aug(n,nb)/Aug(n,n); for i = n-1:-1:1 x(i) = (Aug(i,nb)-Aug(i,i+1:n)*x(i+1:n))/Aug(i,i); end

@@AbidNadeem thank you so much i will use that code after coming back home

No, sorry

You are welcome

ruclips.net/video/OS55WfbAli8/видео.html

Sorry. I don't have it.

it is by back-substitution. you can write a series of commands in Mathematica.

Actually, there is no need to put row reference in the base (subscript). A normal typing of A[[2]] for example without a subscript use for [[2]] will also work. However, you can show subscript in Mathematica by pressing Ctrl plus the underscore key.

@@AbidNadeem sir its not working with A[[2]]

I have tried a lot times please help sir

@@AbidNadeem when I using subscript in mathematica by pressing cntrl plus the undercase key.

only change the size of word

This figure is from the Book by Callister. You can get it from there.

I did not have proper mic that time as we have to transform to online teaching mode due to Covid19.

I have no idea without knowing any more details.

Kindly specify where in the clip?

There are four sigma terms as there are four terms in the DE. (1-x^2)y'' are two terms.

For c1 and c2 we have two equations. You can use any method you know to find the answer. I skipped it as I wanted to finish this clip early.

No. it is -0.5.

@@AbidNadeem ok sir thanku

4 is written as 36/9 to calculate the fractions with a common denominator.

@@AbidNadeem thanks sir

Thanks and welcome

Thanks for sharing your experience.

I am sorry. I have no idea about that.

There may be a typo. Thanks for notifying me.

yes