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THANK YOU. Best video ever to understand this topic, I am shocked by how good you are

helpful! thanks !

thank god you are here !!!

put some captions pls, hard to understand anything with this audio

In This video....❌ In This Tutorial.....❌ In This lecture.....❌ In This Video Tutorial Lecture ✅ 👍🏻

Drho/Ds=DR and Drho/Ds=Drho how

Very compact and precise. Thank you for the clear explanation of the topic.

EXCELLENT!

WTF, you are the best person I have seen who talks about the difference between these two shits. Thank you so much.

Thank-you sir

Length of the sequence is N=3

So amplitude vs time, to amplitude vs frequency where it is easier to understand. 👍

To the point and detailed video. Thanks alot I was searching for this for a long time!

What is 'w' equal to in DTFT sir? Is it w=2π/N or w=2π/T?? In DFT it is w=2πkn/N......

Amazing

the way you are explaining the topic is superb sir

very good

well done..many thx

Super sir

🖤🖤

Hello could you please give us the pdf or ppt file in the description box

clc; clear; clear var; %% N=3e5; alpha16qam=[-3 -1 1 3]; Es_N0_dB =[0:20]; ipHat=zeros(1,N); %% for ii=1:length(Es_N0_dB) ip=randsrc(1,N,alpha16qam)+j*randsrc(1,N,alpha16qam); s=(1/sqrt(10))*ip; n=1/sqrt(2)*[randn(1,N)+j*randn(1,N)]; y=s+10^(-Es_N0_dB(ii)/20)*n; y_re=real(y); y_im=imag(y); ipHat_re(find(y_re< -2/sqrt(10)))=-3; ipHat_re(find(y_re> 2/sqrt(10)))=3; ipHat_re(find(y_re>-2/sqrt(10) & y_re<=0))=-1; ipHat_re(find(y_re>0 & y_re<=2/sqrt(10)))=1; ipHat_im(find(y_im< -2/sqrt(10)))=-3; ipHat_im(find(y_im> 2/sqrt(10)))=3; ipHat_im(find(y_im> -2/sqrt(10) & y_im<=0))=-1; ipHat_im(find(y_im> 0 & y_im<=2/sqrt(10)))=1; ipHat = ipHat_re + j*ipHat_im; nErr(ii)=size(find([ip- ipHat]),2); end %% simBer=nErr/N; theoryBer=3/2*erfc(sqrt(0.1*(10.^(Es_N0_dB/10)))); figure semilogy(Es_N0_dB,theoryBer,'b.-','LineWidth',1); hold on semilogy(Es_N0_dB,simBer,'mx-','LineWidth',1); axis([0 20 1e-5 1]) grid on

Thanks

Well, the calculation is wrong

*PLZ HELP*. Given a pressure of 2kpa, nominal resistance of 120 ohm, diameter of strain gauge 0.1mm, a GF of 2. What will be the change in resistance value of the strain gauge?....in short I wanta formula to calculate the change in resistance of strain gauge for a given INPUT PRESSURE

could you attach link of the code and experiment

thankuu sir

Thank you. You made the difficult topic so easy to understand!

can you provide the code in a pdf form

Thanks alot for this presentation, but there is a small mistake done. X(0)=Sum(from 0 to 3) of (1/3)= 4*(1/3)= 4/3, cz the number of terms is 4. Thank you!!!

Great informational video . Sir audio level is low. One more point i have to add is that digital processor works on discrete values .Thus we convert dtft to dft.

Thank you for sharing !!

well done

not audible.

Sir voice is not audible

thank you sir

Thanks for good explanation

very good explanation keep it up i am feeling lucky