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Nice chemistry sir

Thank you!! you’re videos are great for people like me who don’t study chem in college but love it! Keep up the amazing work!!

Do you make these videos because for the sole purpose of education?

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Am not seeing the nomenclature at 14:07. How do we know (from the name) the heptane is not attached to N at C-4? It could still be (R)-N-ethyl-6-methylheptanamine...? Thanks!

Do more about group theory.

thanks man helped a bunch!

Very educative video. Good job

Hello good sir ❤ please don't stop enlightening us we do really need the way u explain ❤ keep it going 🎉

Nice vidio❤.

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is 4 carbon ring compound is stable?

I really enjoy these videos but it’s really disappointing if one can’t get to the right solution because the starting material was drawn incorrectly. The double bond was missing in the first figure. Are the double bonds correct in the product of the new exercise? If I draw the mechanism with a ring opening of the formed [2.2.0]-bicyclohexanone I get the double bonds in different positions

Great video! I've seen multiple of your videos, frankly and respectfully you need to work on your drawings because after a few steps it becomes so crowded and I can't tell what's going on by then.

Yeaaah mechanism monday 🕺

Your clip is pretty interesting. Because of busy schedule, i could not watch fully but i still liked. Hope you successfull

First a claisen condensation reaction takes place which forms a bicyclic intermediate and the loss of ethanol. Then the acidic alpha hydrogen, in the middle of the two carbonyls, is deprotonated forming a new alkene that breaks the C-C bridge. The electrons from the broken bond moves towards the carbonyl that was once an ethyl ester. This creates the six membered ring and the alkoxide giving the final product.

in the last step when we have the ring with oh group we can do an elimination reaction if we consider it to be done in acidic conditions

thank you for helping me in becoming less of a noob in chemistry :)

I have my first chemistry exam in med school tomorrow and this helped a lot! Thank you

Thank you for the video. Can the alkoxide also react as an electrophile at the carbon which is attached to oxygen?

I was thinking that once one of the amines was protonated, a sn2 attack of water would happen, and then a proton transfer, then the lone pairs from oxygen would kick off the C-N sigma bond. This would then repeat for the adjacent nitrogen obtaining formaldehyde. But it would make sense that the neighboring nitrogen would kick the ammonium off first since it's intramolecular.

Your teaching is excellent in all videos but this video you draw the wrong urotropin structure this one change

My favourite serie of videos on youtube! Keep it up !

Hi, cool video, but the structure of Urotropin that you draw in blue is wrong. The lower nitrogen only has two bonds to cabons while it should have three.

How did you do? I'd love to hear your proposals for next week's mechanism so drop them down below! Subscribe for more chemistry content, and hit the notification bell to stay updated! #ScienceCommunity #MechanismMonday #OrganicChemistry

How did you do? I'd love to hear your proposals for next week's mechanism so drop them down below! Subscribe for more chemistry content, and hit the notification bell to stay updated! #ScienceCommunity #MechanismMonday #OrganicChemistry

5:53 why does another EtOH have to deprotonate it? oxygen can only have 2 bonds so i figure it deprotonates itself & could just bubble out as H2.

It is mCPBA

That was really cool! Is there a particular name for this specific transformation?

This is great, thanks. Is it *possible* that instead of Michael addition we might get imine formation at the carbonyl carbon with the same result?

Hi Dr. Rojas another fantastic video! Just curious, I might be mistaken, but should there be an extra alkyl carbon in the reductive amination practice problem solution? Thank you so much again!

Like this, thank you 😄

❤

Love this! I'll see you every Monday until I finish my 2nd year in Chemistry.

What is it called, is it possible to eat it?

Great Video! Very informative for the MCAT!

Good video, well understood,, Do more topics❤.

Hey broo ur a nice teacher Really loving ur teaching skills ❤

If you enjoyed this video, don't forget to give it a thumbs up, subscribe for more chemistry content, and hit the notification bell to stay updated! Have questions or specific topics you'd like me to cover? Drop them below, and let's keep the chemistry conversation going! #ScienceCommunity #LearningTogether #OrganicChemistry

I like your very clear videos, mechanisms are well explained, thanks !

Michael addition of amine, proton transfer enol tautomerization, intramolecular imine condensation, then an elimination reaction to form the olefin.

Hmm next week's vaguely reminds me of a robinson annulation analog- Michael addition, intramolecular ring forming reaction... not sure how I'd go about it to form a nitrogen heterocycle though

Now do a retrosynthesis of the molecule 😅

Oh, next week’s looks cool! I see the Michael addition but what comes next?

I'm not a chemist, but I find your lessons very educational, and chemistry is something I've had an interest in for a while. Maybe I'll go to school for it at some point

How did you do? I'd love to hear your proposals for next week's mechanism so drop them down below! Subscribe for more chemistry content, and hit the notification bell to stay updated! #ScienceCommunity #MechanismMonday #OrganicChemistry

Bro you were close to demonetization with the 1-phenyl-2-aminopropane 😂

Hey, I loved the video! I do have a few question, though. At around 8:20, wouldn't the but-Li also attack the electrophilic carbon on the Carbonil group? I heard that ButylLithium, unlike an organocuprate (Gilman Reagent), is a hard nucleophile, meaning that it is less likely to attack a soft electrophile like a double bond and more likely to attack a harder electrophile like the electrophilic carbon of the Carbonil group. Also, at any point the nucleophilic intermediate could attack the electrophilic carbon on the Carbonil group, ending the polymerization reaction right there(unless the negatively charged oxygen could act as a nucleophile and attack another double bond or electrophilic carbon, which would lead to the formation of a completely different polymer). For those reasons I thought that a cationic polarization would be better suited for this particular polymer as it didn't encounter such problems. Having said that, the main problem that the cationic polarization would encounter is the fact that the intermediate would not be as stable as the one from the anionic polymerization, as the aldehyde group is an EWG, this would probably slow down the rate at which the reaction proceeds significantly, maybe even making the whole process unviable. Do You think that it could be done with a cationic one as opposed to the one shown in the video? I'd love to hear your thoughts on this as I'm not that knowledgeable about this topic just yet. But either way, thanks for this amazing content!

Hey, this video is really cool. At 9:30 I would have added that the sulfo group is withdrawing electron density in the orto and para positions due to its resonance structures.