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Mr Engineer
Добавлен 31 мар 2020
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Видео
ENGINE ASSMPLY AND DRAWING ON SOLIDWORKS
Просмотров 182 часа назад
ENGINE ASSMPLY AND DRAWING ON SOLIDWORKS
6-If the resultant force acting on the bracket is required to be a minimum,
Просмотров 92 часа назад
6-If the resultant force acting on the bracket is required to be a minimum, determine the magnitudes of F1 and the resultant force. Set Φ=30°.
5-The component of force F acting along line aa is required to be 30 N.
Просмотров 134 часа назад
5-The component of force F acting along line aa is required to be 30 N. Determine the magnitude of F and its component along line bb.
4-The force F has a magnitude of 80 N and acts within the octant shown.
Просмотров 239 часов назад
4-The force F has a magnitude of 80 N and acts within the octant shown. Determine the magnitudes of the x, y, z components of F.
3-Two forces act on the hook as shown in the opposite figure. Determine the magnitude of F2 and its
Просмотров 529 часов назад
3-Two forces act on the hook as shown in the opposite figure. Determine the magnitude of F2 and its coordinate direction angles so that the resultant force FR acts along the positive y axis and has a magnitude of 800 N.
2-The link in the opposite figure is subjected to two forces F1 and F2.
Просмотров 209 часов назад
2-The link in the opposite figure is subjected to two forces F1 and F2. Determine the magnitude and direction of the resultant force.
1-It is required that the resultant force acting on the eyebolt be directed along the positive x
Просмотров 519 часов назад
1-It is required that the resultant force acting on the eyebolt be directed along the positive x axis as shown in the opposite figure and that F2 has a minimum magnitude. Determine F2 magnitude, the angle θ, and the corresponding resultant force.
WRIST PIN , BUSH UPPER LOWER BEARINGSDRAWING ON SOLIDWORKS TUTORIAL FOR BIGGENERS
Просмотров 1816 часов назад
WRIST PIN , BUSH UPPER LOWER BEARINGSDRAWING ON SOLIDWORKS TUTORIAL FOR BIGGENERS
5-The chipping machine ejects wood chips at v0=30 m/s. If the tube is oriented at 30° from
Просмотров 1521 час назад
5-The chipping machine ejects wood chips at v0=30 m/s. If the tube is oriented at 30° from the horizontal,determine how high, h, the chips strike the pile if they land on the pile 20 m from the tube.
4.For a short time, the path of the plane is described by y = (0.001x2) m. If the plane is rising
Просмотров 13День назад
4.For a short time, the path of the plane is described by y = (0.001x2) m. If the plane is rising with a constant upward velocity of 20m/s.determine the magnitudes of the velocity and acceleration of the plane when it reaches an altitude of y=100 m.
3-A particle moves along a horizontal path with a velocity of v = (3t2-6 t) m/s, where t is the time
Просмотров 68День назад
3-A particle moves along a horizontal path with a velocity of v = (3t2-6 t) m/s, where t is the time in seconds. If it is initially located at the origin , determine the distance traveled in 3.5sthe particle’s average velocity average speed during the time interval.
2 A small projectile is fired vertically downward into a fluid medium with an initial velocity of 60
Просмотров 60День назад
2-A small projectile is fired vertically downward into a fluid medium with an initial velocity of 60m/s. Due to the drag resistance of the fluid the projectile experiences a deceleration of a = (-0.4v3) m/s2, where v is in m/s. Determine the projectile’s velocity and position 5 s after it is fired.
1-The car on the opposite photo moves in a straight line such that for a short time its velocity
Просмотров 120День назад
1-The car on the opposite photo moves in a straight line such that for a short time its velocity is defined by v=(3t2 2t) m/s, where t is in seconds. Determine its position and acceleration when t = 3s. When t =0, s = 0.
CRANK SHAFT DRAWING SOLIDWOKS TUTORIAL BIGGENERS (رسم عمود الكرنك باستخدام السوليدوركس بالعربى)
Просмотров 40День назад
CRANK SHAFT DRAWING SOLIDWOKS TUTORIAL BIGGENERS (رسم عمود الكرنك باستخدام السوليدوركس بالعربى)
END CAP DRAWING SOLIDWOKS TUTORIAL BIGGENERS (رسم الغطاء السفلى باستخدام السوليدوركس بالعربى)
Просмотров 5414 дней назад
END CAP DRAWING SOLIDWOKS TUTORIAL BIGGENERS (رسم الغطاء السفلى باستخدام السوليدوركس بالعربى)
CONNECTING ROD DRAWING SOLIDWOKS TUTORIAL BIGGENER(رسم زراع التوصيل باستخدام السوليدوركس بالعربى)
Просмотров 21314 дней назад
CONNECTING ROD DRAWING SOLIDWOKS TUTORIAL BIGGENER(رسم زراع التوصيل باستخدام السوليدوركس بالعربى)
PISTON DRAWING ON SOLIDWOKS TUTORIAL FOR BIGGENERS (رسم مكبس باستخدام السوليدوركس بالعربى )
Просмотров 16914 дней назад
PISTON DRAWING ON SOLIDWOKS TUTORIAL FOR BIGGENERS (رسم مكبس باستخدام السوليدوركس بالعربى )
Drawing Templates from Scratch in SOLIDWORKS ( Assuit Template ) الرسم باستخدام برنامج سوليدوركس
Просмотров 8214 дней назад
Drawing Templates from Scratch in SOLIDWORKS ( Assuit Template ) الرسم باستخدام برنامج سوليدوركس
solidworks tutorial for beginners sketch , revolved boss CUP
Просмотров 5121 день назад
solidworks tutorial for beginners sketch , revolved boss CUP
solidworks tutorial for beginners sketch , lofted boss HOOK
Просмотров 30121 день назад
solidworks tutorial for beginners sketch , lofted boss HOOK
solidworks sketch tutorial for beginners sketch #3
Просмотров 3821 день назад
solidworks sketch tutorial for beginners sketch #3
solidworks sketch tutorial for beginners sketch #2
Просмотров 7228 дней назад
solidworks sketch tutorial for beginners sketch #2
solidworks sketch tutorial for beginners sketch #1
Просмотров 9028 дней назад
solidworks sketch tutorial for beginners sketch #1
solidworks sketch tutorial for beginners sketch #20
Просмотров 27Месяц назад
solidworks sketch tutorial for beginners sketch #20
solidworks sketch tutorial for beginners sketch #19
Просмотров 30Месяц назад
solidworks sketch tutorial for beginners sketch #19
solidworks sketch tutorial for beginners sketch #18
Просмотров 50Месяц назад
solidworks sketch tutorial for beginners sketch #18
solidworks sketch tutorial for beginners sketch #17
Просмотров 42Месяц назад
solidworks sketch tutorial for beginners sketch #17
SolidWorks Drawing Tutorial for beginners Exercise 107 part 2
Просмотров 713 месяца назад
SolidWorks Drawing Tutorial for beginners Exercise 107 part 2
SolidWorks Tutorial for beginners Exercise 107 (اعدادى هندسة)
Просмотров 623 месяца назад
SolidWorks Tutorial for beginners Exercise 107 (اعدادى هندسة)
looks like a great presentation, pity i don't understand a word you are saying?
@@malcolmlourens8404 unfortunately , it is in Arabic language for arabic student in my university, hope you contact me if you need further information about turbines.
Thank you very much!
Tendrás el archivo con el dibujo echo de casualidad?😅
Can someone explain me by which formula does the value 2.18 came from?
|'TZNTENGINEERING.
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W MyW
I am from Vietnam. Thank you so much, the lesson so great. have a good day pro.
what is m?
M means module
عفيه بسبع
Que libro es estos ejercicios ? What is the name of the author of this book?
Mansun fluid mechanics
what exactly does the 9800 in the last step become when using imperial units?
60° Shaft Angle
Thank you for this tutorial, it is very informative. Please, if you can make a tutorial for BEVEL GEAR 60 degrees M1.5, T40, with M1.5, T20, not for 90 degrees. I will be very grateful to you. Thank you in advance!
If only it was in English.
So sorry, if you need any explanation, send me ,tnx
Can I contact you ... I am struggling with this for my research
Contact me in what'sup +201126063245
How long of a 3 inch pipe would it take to create a downdraft to make a Helmholtz resonator placed underneath the pipe to make sound for free from the downdraft?
جامد!
Thank you very much! Plus, I’m wondering why v2 equals to zero? Thanks for the helpful instructions again!
for point 2 , we take the point on the lake surface . And for very wide surfaces like that , the surface moves really slowly when you add or take water so we consider it to be almost zero.
Thank you very much !🤩🤩🤩
من أفضل الدكاتره شرح مبسط وجميل ربنا يجازيك خير يا دكتور علي .... انا من تلاميذ حضرتك خريج أسيوط دفعه ٢٠٢١ ❤❤❤❤
جزاك الله خيرا يا بشمهندس مؤمن ربنا يبارك فيكم اجمعين يارب و يجعل الخير على يدكم فى كل مكان ان شاء الله
اريد اسم الكتاب بلازحمة
Fluid mechanics for mansun
@@mrengineer1000 شكرا
@@user-yl4zg4cm3p العفو بالتوفيق يارب
ingilizce konuşmuyosan neden ingilizce başlık atıyon olm
çözüm ingilizce belki birileri faydalanabilir
neatly presented habibi
Is the bevel gear that you've designed appropriate the ISO standart ?
No , it is just a close way to draw the bevels in solidworks
جزاك الله كل خير .... ممكن لو في فيديوهات حل تانيه تبعت لينكها
Thank you for solving these questions and organizing them.
thanks you really much
اسم الكتاب ارجوك الذي اخدت منه المسألة
Cengel heat transfer
english please!
Equations all in English. But explaination in arabic unfortunately
Could you share de biography about the formulas to design the profile of tooth, for example, you use pitch diameter/5 to Flank radius, why /4 in helical gears?...... Casillas" book use /8, which is your biography??
iam using what solidwrks library use , the correct shape is envaulted shape
Write the lessons in order...
Write the lessons in order
Write the lessons in order
Cause acoustic wave length is long at low frequency so we do not need dense mesh like CFD mesh to solve acoustics study
Gentile Mr Engineer per ottimizzare : Valutare -Rilevamento Interferenze e non intaccare la bellezza formale delle sue equazioni ho diminuito lo spessore del dente sul Diametro Primitivo nel seguente modo : "D6@Shizzo1"=(3.14*"D1@Schizzo1"/n/4) - 0.22 . Praticamente è lo spessore di rettifica dopo i trattamenti termici
Thankyou
وين التكمله
فى فيديوهات بعدها
Emkan dare emailetuno dashte basham, mikhastm chanta soal beporsam azatun?
Dear Engineer in Gear Geometry I modified the equation "D8@Sketch1" with the following values: = ("M"*1.25 - "M" ) / 2 that from Value 0.75 mm this value is recommended by the Manual. "c" = Clearance where ( M*1.25 - M ) I used a tangent circle instead of a tangent arc then adjusted with Trim Entities. All perfect
Thats incredible sir , thanks for adding a new information 🌹🌹
"I used a tangent circle instead of a tangent arc then adjusted with Trim Entities. All perfect" - what is the difference? Isn't the same? And the equation ("M"*1.25 - "M" ) / 2 == ("M"*0.25) / 2 == "M"* 0.125 It's the same but the last one is the most simple expression. Isn't there any mistake? You know, nobody would write M"*1.25 - "M" in any Manual, because it's M"*1.25 - "M"*1 and that is "M"*(1.25-1) and that is "M" * 0.25
Dear Engineer, I use solidworks 2023 SP03 as a hobby, I am fascinated by its helical gear geometry. I ran the path down to Convert Entities to be able to insert Helix and Spiral. But with SW 2023 it is impossible for me. I have tried many times. I would be very happy to receive advice Thank you very much
+201126063245 this is my whatsapp send me screen shot for the problem, i hope that i can help
Dear Engineer, I can vary M10. Impossible to vary N150. Thanks for a correct solution. Grazie
Thanks senior 😊😊
اخي الطريقة التي انت استخدامها ليست بالمستوى المطلوب بالنسبة لعمق السن هناك خطا ثم بالنسبة لرسم المودول فان طريقة INVOLUTE افضل بكثير انا مصمم مسننات منذ اكثر من 10اعوام
ممكن اخي تساعدني اريد قاعدة رسم مسنن مخروطي حلزوني
المسن PINION راس السن رفيع لديك بينما ال GEAR ذات الأسنان 30 سن راس السن أغلظ هل تستطيع أن تفسر لماذا اتمنى أن تجيب علي شكرا
اخي الطريقة التي انت استخدامها ليست بالمستوى المطلوب بالنسبة لعمق السن هناك خطا ثم بالنسبة لرسم المودول فان طريقة INVOLUTE افضل بكثير انا مصمم مسننات منذ اكثر من 10اعوام
شكرا على جهودك لدي سوال من أين حصلت على 0.46 ولماذا استخدمت 0.64 وليس 0.46 ثم أن ADDENDUN دائما يساوي المودول فكيف حصلت على هذه العلاقة
Hi bro I need help for spiral bevel gear n pinion
x2 me too, have you found information about that?
Um die Ecke gedacht funktioniert das wie ein abgewandelter/ umgekehrter SCHRAUBENKOMPRESSOR!!! Diesen gibt es auch schon sehr lange!
Es handelt sich doch um einen Schraubenkompressor?
@@paulrichter7014 Entschuldigung - habe diesen meinen Beitrag hier irrrtümlich plaziert! Bin doch ein 'Schussel so was von aber auch... Habe DIESEN Beitrag mit dieser meinigen Message gemeint: ruclips.net/video/7jymEvf66EQ/видео.html
Alles gut kann ja passieren, hatte mich nur verwirrt :).
von MAN gestohlen?
P R O M O S M 🙃
ملحوظه فى خطا فى نصف قطر ترس الhelical gear وهو يساوى 2.715 inch بدلا من 5.431 inch الملفات الخاصه بالشرح على لينك الدرايف بالارقام المعدلة : docs.google.com/presentation/d/1br0Bxvn8TslnYxqVw87dJqcjPcs3cUby/edit?usp=sharing&ouid=111386358874653419997&rtpof=true&sd=true
For the calculation of the transverse pressure angle, the fraction inside the atan function should be flipped. φ ₜ = tan⁻¹(tan(γ) / cos(φ)).
I think this is the correct expression: φt = tan⁻¹(tan(φ) / cos(γ)).
أفضل شرح احد هلء ، بس المشكلة إنتا مش مستعمل قاعدة ال involute curv
هى دى طريقه رسم الترس داخل السوليدوركس وهو لا يستعمل invelute لانه معقد فى تمثيل ال gear