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MathWithMrC
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Добавлен 25 мар 2020
Видео
Applications of Taylor Polynomials and Approximate Integration
Просмотров 92 месяца назад
Applications of Taylor Polynomials and Approximate Integration
Representing Functions as Power Series
Просмотров 122 месяца назад
Representing Functions as Power Series
Applications to Physics and Engineering
Просмотров 602 месяца назад
Applications to Physics and Engineering
Trigonometric Integrals and Substitution
Просмотров 1262 месяца назад
Trigonometric Integrals and Substitution
Absolute Value and Inequalities Review
Просмотров 1233 месяца назад
Absolute Value and Inequalities Review
Linear Approximations and Differentials
Просмотров 1095 месяцев назад
Linear Approximations and Differentials
Areas and the Definite Integral Part 2
Просмотров 525 месяцев назад
Areas and the Definite Integral Part 2
Areas and the Definite Integral Part 1
Просмотров 535 месяцев назад
Areas and the Definite Integral Part 1
hey i think for example 4 when you went to plug your Z value from the plane equation into the distance formula, you forgot to subtract 1. you kept it as z^2 instead of (z-1)^2. by the way thanks for keeping these videos public, you're the only reason I'm passing calc 3 right now !
Looks like I had a silly mistake at about 13:26, I should have written x^2=4y instead of "2y". Oops! I only used that as a general reference for the shape of the graph though, so it didn't end up affecting the integral set up.
great video! I am confused about f in example 4 you say it is 1, however, I got -1. Could you explain this please?
hii i think there might b a mistake when graphing the vectors for x=1 when the gradient is <-3,1> @18:55. Seems the slope is slightly incorrect, but I might b wrong. Anyway, thank u so much for ur vids! these have been so helpful w my studying.
Can u provide us with the pdf notes for this video???
Pog
13:57 Although this doesn't change the final answer, I believe that taking y=-3a and x=4a would be more appropriate because tanθ = y/x is a ratio in its simplest form and the exact values of x and y might not be equal 4 and -3 when they could be canceled out using common divisible factors.
While it is valid to approach it in that way, it adds unnecessary complication to the problem. As we discussed in the previous section, the ratios of similar triangles are equal so when solving these kinds of problems we can just work with the simplest case rather than trying to generalize to all possible triangles.
38:57 y=ln(-x) when is y=ln(-x+3) or y=ln(3-x), so the graph should've moved towards left (since we're adding a number inside f(x)). But as you've explained x-3=0->x=3, the graph shifts towards right. It seems like there's two different answers to this, did I do something wrong?
Hello, sorry for the slow reply! I am not totally sure if I am understanding your question correctly, but hopefully this will help: Adding a number inside the function doesn't tell you anything meaningful, because what we are trying to track is where the function moved relative to it's starting point. So, if you imagine a point on the graph at x=0 and ask where does it go after the transformation, you would find that by taking the entire new input and setting it to 0 to see where x moved. I think that you are thinking about an algebra shortcut for determining shifts that often causes confusion for students, which is why I don't teach the topic that way. In order to apply that trick, you would have needed to rewrite the function first as y=ln(-1(x-3)), which using the algebra shortcut would tell you that shift was 'right by 3'. Taking your input and setting it equal to 0 bypasses the need to rewrite the function first, and generally helps students avoid the most common mistakes on these problems. I hope that helps!
hey just curious because when I was watching the video at 28:46 you miswrote the denominator and thus when you used the conjugate to solve for the limit it was wrong and the limit you got was 0, but I think that it should have been 3.
Hi! That's a good catch, looks like I just miscopied and forgot to write the x. Thankfully, the work stays almost identical, but you are correct, the answer should have worked out to 3. Thanks!
tysm for this
Adios Calculus 2 ! Thanks for the wonderful explanations throughout the course Mr. C
yooo Mr C with the new mic
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❤❤❤
hi
We did it!
Example 2 skipped stuff probably won't be able to skip with some other questions as a reminder Also first :)))))))))))
first
First
first!
9:30 I think hyperbola should be written on the top instead of ellipse
Absolutely saddened that this is the last video for the Calculus 2 course. An absolute emotional and mental journey that I won't forget!
0:02 Discordo
hi