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Determine the location y¯ of the centroid for the cross-sectional area - 9-66
9-66. Determine the location y¯ of the centroid for the cross-sectional area.
Problem from Engineering Mechanics Statics, Fifteenth Edition.
Problem from Engineering Mechanics Statics, Fifteenth Edition.
Просмотров: 5
Видео
Determine the location (x¯,y¯) of the centroid of the area - 9-64
Просмотров 192 часа назад
*9-64. Determine the location (x¯,y¯) of the centroid of the area. Problem from Engineering Mechanics Statics, Fifteenth Edition.
Locate the centroid y¯ of the cross-sectional area of the beam - 9-63
Просмотров 254 часа назад
9-63. Locate the centroid y¯ of the cross-sectional area of the beam. Problem from Engineering Mechanics Statics, Fifteenth Edition.
Locate the centroid y¯ for the beam’s cross-sectional area - 9-60
Просмотров 167 часов назад
*9-60. Locate the centroid y¯ for the beam’s cross-sectional area. Problem from Engineering Mechanics Statics, Fifteenth Edition.
Determine the force in each member of the truss and state if the members are in tension - 6-3
Просмотров 439 часов назад
6-3. Determine the force in each member of the truss and state if the members are in tension or compression. Set P1=200 lb, P2=500 lb. Problem from Engineering Mechanics Statics, Fifteenth Edition.
The pelvis P is connected to the femur F at A using three different muscles - 2-13
Просмотров 7112 часов назад
2-13. The pelvis P is connected to the femur F at A using three different muscles, which exert the forces shown on the femur. Determine the resultant force and specify its orientation θ, measured counterclockwise from the positive x axis. Problem from Engineering Mechanics Statics, Fifteenth Edition.
The three cable forces act on the eyebolt. Determine two possible magnitudes for P - 2-32
Просмотров 6514 часов назад
*2-32. The three cable forces act on the eyebolt. Determine two possible magnitudes for P so that the resultant force has a magnitude of 800 N. Problem from Engineering Mechanics Statics, Fifteenth Edition.
If the cords suspend the two buckets in the equilibrium position, determine the weight - 3-28
Просмотров 13316 часов назад
*3-28. If the cords suspend the two buckets in the equilibrium position, determine the weight of bucket B. Bucket A has a weight of 60 lb. Problem from Engineering Mechanics Statics, Fifteenth Edition.
Knowing the forces in members A and C, determine the forces FB and FD - 3-3
Просмотров 14919 часов назад
3-3. Knowing the forces in members A and C, determine the forces FB and FD acting on members B and D that are required for equilibrium. The force system is concurrent at point O. Problem from Engineering Mechanics Statics, Fifteenth Edition.
Determine the reactions at the supports - 5-10
Просмотров 4221 час назад
5-10. Determine the reactions at the supports. Problem from Engineering Mechanics Statics, Fifteenth Edition.
Determine the force in each cord for equilibrium of the 60-kg bucket - 3-12
Просмотров 298День назад
*3-12. Determine the force in each cord for equilibrium of the 60-kg bucket. Problem from Engineering Mechanics Statics, Fifteenth Edition.
A motor gives gear A an angular acceleration of aA = (2t^3) rad/s^2, where t is in seconds - 16-18
Просмотров 33День назад
16.1 Planar Rigid-Body Motion 16.2 Translation 16.3 Rotation about a Fixed Axis 16-18. A motor gives gear A an angular acceleration of aA = (2t^3) rad/s^2, where t is in seconds. If this gear is initially turning at vA = 15 rad/s, determine the angular velocity of gear B when t = 3 s. All problems from Engineering Mechanics: Dynamics Fourteenth Edition in SI Units by R. C. Hibbeler.
The disk is driven by a motor such that the angular position of the disk is defined - 16-5
Просмотров 29День назад
16.1 Planar Rigid-Body Motion 16.2 Translation 16.3 Rotation about a Fixed Axis 16-5. The disk is driven by a motor such that the angular position of the disk is defined by u = (20t 4t^2) rad, where t is in seconds. Determine the number of revolutions, the angular velocity, and angular acceleration of the disk when t = 90 s. All problems from Engineering Mechanics: Dynamics Fourteenth Edition i...
At the instant shown, u = 60°, and rod AB is subjected to a deceleration of 16 m/s^2 - 16-42
Просмотров 40День назад
16.1 Planar Rigid-Body Motion 16.2 Translation 16.3 Rotation about a Fixed Axis 16.4 Absolute Motion Analysis 16-42. At the instant shown, u = 60°, and rod AB is subjected to a deceleration of 16 m/s^2 when the velocity is 10 m/s. Determine the angular velocity and angular acceleration of link CD at this instant. All problems from Engineering Mechanics: Dynamics Fourteenth Edition in SI Units b...
At the instant u = 60°, the slotted guide rod is moving to the left with an acceleration - 16-40
Просмотров 3114 дней назад
16.1 Planar Rigid-Body Motion 16.2 Translation 16.3 Rotation about a Fixed Axis 16.4 Absolute Motion Analysis *16-40. At the instant u = 60°, the slotted guide rod is moving to the left with an acceleration of 2 m/s^2 and a velocity of 5 m/s. Determine the angular acceleration and angular velocity of link AB at this instant. All problems from Engineering Mechanics: Dynamics Fourteenth Edition i...
The two spheres each have a mass of 3 kg and are attached to the rod of negligible mass - 15-102
Просмотров 3614 дней назад
The two spheres each have a mass of 3 kg and are attached to the rod of negligible mass - 15-102
The cord, which is wrapped around the disk, is given an acceleration of a = (10t) m/s^2 - 16-11
Просмотров 2214 дней назад
The cord, which is wrapped around the disk, is given an acceleration of a = (10t) m/s^2 - 16-11
The 2-kg ball of negligible size is fired from point A with an initial velocity of 10 m/s - 14-75
Просмотров 7214 дней назад
The 2-kg ball of negligible size is fired from point A with an initial velocity of 10 m/s - 14-75
The force F, acting in a constant direction on the 20-kg block, has a magnitude which varies - 14-11
Просмотров 8614 дней назад
The force F, acting in a constant direction on the 20-kg block, has a magnitude which varies - 14-11
The 30-kg block is supported by two springs having the stiffness shown - 3-9
Просмотров 34414 дней назад
The 30-kg block is supported by two springs having the stiffness shown - 3-9
The force of F = 50 N is applied to the cord when s = 2 m - 14-6
Просмотров 6814 дней назад
The force of F = 50 N is applied to the cord when s = 2 m - 14-6
Determine the maximum weight W that can be supported in the position shown - 3-4
Просмотров 71021 день назад
Determine the maximum weight W that can be supported in the position shown - 3-4
Determine the magnitude of the resultant force FR=F1+F3 and its orientation θ - 2-10
Просмотров 22121 день назад
Determine the magnitude of the resultant force FR=F1 F3 and its orientation θ - 2-10
Determine the magnitude of the resultant force FR=F1+F2 and its orientation θ - 2-9
Просмотров 17621 день назад
Determine the magnitude of the resultant force FR=F1 F2 and its orientation θ - 2-9
Draw the shear and moment diagrams for the cantilevered beam - 7-48
Просмотров 9921 день назад
Draw the shear and moment diagrams for the cantilevered beam - 7-48
Determine the magnitude of the resultant force and its direction - 2-35
Просмотров 7921 день назад
Determine the magnitude of the resultant force and its direction - 2-35
Draw the shear and moment diagrams for the beam (a) in terms of the parameters shown - 7-47
Просмотров 4821 день назад
Draw the shear and moment diagrams for the beam (a) in terms of the parameters shown - 7-47
Express F1 and F2 as Cartesian vectors - 2-34
Просмотров 6021 день назад
Express F1 and F2 as Cartesian vectors - 2-34
Initially the 5-kg block is moving with a constant speed of 2 m/s around the circular path - F15-21
Просмотров 4821 день назад
Initially the 5-kg block is moving with a constant speed of 2 m/s around the circular path - F15-21
The 2-kg particle A has the velocity shown. Determine its angular momentum HO about point O - F15-19
Просмотров 2121 день назад
The 2-kg particle A has the velocity shown. Determine its angular momentum HO about point O - F15-19
I was stuck on this problem for ages because I never went over the actual process for this question in my class. Thank you!
bros majestic
Thanks lol
this is mad helpful, you explain things very clearly
Thanks bro
Bless your soul. You are a saint and a scholar!
Thanks!
Tension change in problem b since another cat lies on the block A.
Coop
Great video jeff hanson 2.0
I love that guy
There is no other explanation, save for your mother being a zoophile, for you, sir, are truly a GOAT.
Crazy compliment damn
My dumb ass forgot I could divide off the the cos while solving for the first tension force. Thank you so much for reminding me
lol nice job
Insightful solution strategy. Rapid delivery keeps attention. So helpful to students learning by themselves. Much appreciated, Grant.
Appreciate it! Glad I could help.
Thank you jit
Any time
I’ve always wanted to know where the centroid of y was
Yay now you do
@@calcgang Not the solution you were looking for, but I modelled the part in SolidWorks and used the Mass Properties tool to get an answer of y_bar = 11.93
All I did was sum the forces in the x direction and solve for Tac, sum the forces in the y direction and solve for W. Plug in Tac into my y direction sum. Put 600 in for Tab and solve for W
Ok cool 😎
yooo i just searched up this problem for a homework assignment and this was the first result, small world. Thanks for the help
Is this heavy civil Joshua?
💯
🐿️
thank you friend🤝
Welcome 👍
Pro delivery, Grant. Always clear and economical. Many thanks.
Why did you use sine as your Fx and cos as your Fy?
It has to do with sin being opposite over hypotenuse
i think i love you
Thanks lol
goated
Thank you
Thanks bro. Keep up the good work
You bet
Thanks bro. Keep up the good work
Thanks, will do!
Thanks bro. Keep up the good work
Thanks g
The king has returned!
Let’s go
Thank you mechanical engineering Jesus
Civil engineering*
@calcgang Thank you civil engineering Jesus
thats a great problem man! thanks
Glad to help
@calcgang if u wish to try jee advanced problems, they get a lot of attention online
Thank youuu so much king!
You're welcome! 🙏
Thank you kind sir for doing this, you clearly expressed how to do everything right and how to approach problems like this, keep up the good work.
You're welcome! Thanks for the support.
V=222m\s
Ok
t=1. 85
Cool
gyat
Thanks :)
Superb, Grant. Thanks.
My pleasure!
hello sir I have a question that I wish to explain to me, do you have a telegram to send on telegram
Telegram App
No
Great method, clear explanation. Many thanks!
Glad it was helpful!
Can you explain the units on this it seems you get M^2 over mm^2 when you solve for P/AE
Mega is (10)^6 and mm is (10)^-3, so when you do the calculations with those prefixes the magnitudes cancel out, try it yourself with converting to standard units
oh my goodness are you single
Yes
hey man, just wanted to leave a quick comment about how much your videos have helped me with dynamics, i really appreciate it and keep up the good content 💪
Appreciate that! Glad I could help.
can this question be done using conservation of energy ?
Probably, try it out
Why do you multiply again Cos (45+90) to find i^?
With three dimensional vectors you have to do two trig functions to lay it on to one axis
Thanks for this
No problem
10/10 thanks man
Glad it helped
thx man
Of course
thx man!
No problem!
Yo i dont even usually leave comments but your vids are actually so helpful, you the reason im passing physics rn. Gonna recommend your vids to all of my friends!!
Thank you! That helps me a lot
since a and b accelerates at the same time, we can combine the mass of a and b -> (15 + b)(36/25) = T - T + 60 then solve for b to get that mass.
thank you very much 😭
the part at 0.441, why i get -0.441?
Yup same as me but there are another positive answer, thus we need to take the positive one right
@@ahmadtarmidzie6884 ye, i only can understand like this if the object fall like the question, we should assume the equation is positive g.
how to get the acceleration and the normal force of this problem
thank you daddy
🦾
thanks