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He asked the output, not what the function will return.

@lifematch the output of the program is what is returned by its main function. Its input is whatever is provided to it via command line arguments

@@TheFrankvHoof no no, the output of the program is not what function returns. You treat a program like a black box. The output is what the user sees. If you write a program that sets a LED to green, then the output is what LED shows you regardless what the function returns. The input of the program is what the user inputs, not what argument you are passing in a function. Likewise, the output of the program is what the user sees. The return of main, user can see that but the objective of this program is the print output, so any user would know that’s the output.

​@@lifematch "The output is what the user sees" As a professional software developer, I have to STRONGLY disagree. The output is what is returned by the program. That can be directly (in the terminal) or indirectly (i.e. via a HTTP or websocket-message). What the user sees is a side-effect of the program. (or technically it's the output of what's being piped into cout. On Unix this would be the output of /dev/tty0, not your program)

@TheFrankvHoof absolutely not. We are talking about a “Program” meaning the code is black box. This program spews prints output. When you talk with Verifications/validation engineer, the output is what they see without looking at the code. The output is what executable spews out that the user sees. I don’t know what you being a professional software engineer has to do with this discussion, since this is very elementary (as far as theories goes). I have been embedded software engineer for 11 years but that doesn’t mean anything since this is theoretical discussion that even grad students can chip in. Maybe ask your colleagues, from different fields, what they think. Should be interesting to hear everyone opinions.

3 right? I am not good in c++

X power 0 Not times

​@@Omarfikry2005it is still wrong , anything raised to power of 0 is 1

I’m assuming you know how an AND gate works here. & is the bitwise AND operator. In binary, 0 is 00000000 and 100 is 001100100. The & operator puts these two values into an AND gate, giving the result 00000000, which is 0.

They all say return 0 So it returns 0 If they put a variable it would return that variable

I think it's because it return 0 no matter what. Though I'm not sure I am not familiar with this language so maybe return 0 means something else

The Symbol Operator(^) is a Bitwise Exclusive or, Such that it Goes through every Bit in the Number (in this case (10) and (10) and Applies the XOR operation (1 if One or the other is Set, 0 if both or none are set) Since it is Applying over identical Bits, Then the Second case is always true Thus (10)^(10)=00 The XOR operator comes in Useful during Low Level bit manipulation or Embedded Registers and stuff like that

​@@alexandre.Monge_ this is C++ (Extension Cpp, c++ or cxx depending on your system) The return in this case is a Finished State The return is there to Explicitly give back control to the Operating system, or the last Caller of this program The Value that the Return Gives is Called an Exit Code, and they are well defined, such that 0 is a Success and anything else is not C++ uses a Different way to print to the Standard Output, Which uses the std::cout member, and the insertion operator(<<) Thus, It inserts "Z= " to the output, and then it inserts the value z into the output, givin the Output of the Program to be: Z= {value Of z} Which in this case is Z= 0

@@ahuma6952 ho, i didn't know, thank you very much

@@ahuma6952 ho, i didn't know, thank you very much

That's a bitwise XOR operator.