Computer Science Theory Explained
Computer Science Theory Explained
  • Видео 116
  • Просмотров 391 627
Binary vs. Unary Number Encodings and Strong NP-completeness
Textbooks:
Computational Complexity: A Modern Approach by S. Arora and B. Barak.
Algorithm Design by J. Kleinberg and E. Tardos.
Lecture slides by K. Wayne accompanying the latter textbook:
www.cs.princeton.edu/~wayne/kleinberg-tardos/
Просмотров: 1 442

Видео

The Lemke-Howson Algorithm - Complementary Pivoting
Просмотров 3,8 тыс.3 года назад
The Lemke-Howson Algorithm - Complementary Pivoting
The Lemke-Howson Algorithm - Best Response Polytopes
Просмотров 3,4 тыс.3 года назад
The Lemke-Howson Algorithm - Best Response Polytopes
The Lemke-Howson Algorithm - Best Response Diagrams
Просмотров 4,8 тыс.3 года назад
The Lemke-Howson Algorithm - Best Response Diagrams
Colorability of Planar Graphs
Просмотров 1,7 тыс.3 года назад
Textbooks: Computational Complexity: A Modern Approach by S. Arora and B. Barak. Algorithm Design by J. Kleinberg and E. Tardos. Lecture slides by K. Wayne accompanying the latter textbook: www.cs.princeton.edu/~wayne/kleinberg-tardos/
The Complexity Class PPAD
Просмотров 1,5 тыс.3 года назад
The Complexity Class PPAD
Scarf's Theorem
Просмотров 6593 года назад
Scarf's Theorem
Computing a Nash Equilibrium
Просмотров 1,3 тыс.3 года назад
Computing a Nash Equilibrium
Nash's Theorem
Просмотров 2,6 тыс.3 года назад
John Nash's PhD Thesis: library.princeton.edu/special-collections/sites/default/files/Non-Cooperative_Games_Nash.pdf
Brouwer's Fixed Point Theorem
Просмотров 5 тыс.3 года назад
Brouwer's Fixed Point Theorem
Sperner's Lemma
Просмотров 4,9 тыс.3 года назад
Sperner's Lemma
Two-Player Zero-Sum - a Second Example
Просмотров 1,4 тыс.3 года назад
Two-Player Zero-Sum - a Second Example
Solving Rock-Paper-Scissors
Просмотров 6 тыс.3 года назад
Solving Rock-Paper-Scissors
Existence and Computation of Nash Equilibria in Two-Player Zero-Sum Games
Просмотров 2 тыс.3 года назад
Existence and Computation of Nash Equilibria in Two-Player Zero-Sum Games
A Brief Linear Programming Refresher
Просмотров 1,2 тыс.3 года назад
A Brief Linear Programming Refresher
Two-Player Zero-Sum Games
Просмотров 3,6 тыс.3 года назад
Two-Player Zero-Sum Games
The Poisened Drink and the Mixed Nash Equilibrium
Просмотров 1,2 тыс.3 года назад
The Poisened Drink and the Mixed Nash Equilibrium
The Battle of the Sexes and Burning Money
Просмотров 1,5 тыс.3 года назад
The Battle of the Sexes and Burning Money
Pure Nash Equilibrium - a Further Example
Просмотров 8843 года назад
Pure Nash Equilibrium - a Further Example
The Battle of the Sexes
Просмотров 1,4 тыс.3 года назад
The Battle of the Sexes
Weak Dominance
Просмотров 8513 года назад
Weak Dominance
The Iterated Elimination of Dominated Strategies
Просмотров 2,2 тыс.3 года назад
The Iterated Elimination of Dominated Strategies
Dominating Strategies in the Prisoner's Dilemma
Просмотров 1,4 тыс.3 года назад
Dominating Strategies in the Prisoner's Dilemma
The Prisoner's Dilemma
Просмотров 9183 года назад
The Prisoner's Dilemma
Games in Strategic Form
Просмотров 1,1 тыс.3 года назад
Games in Strategic Form
The "Tragedy" in the Tragedy of the Commons
Просмотров 1,8 тыс.3 года назад
The "Tragedy" in the Tragedy of the Commons
The Tragedy of the Commons
Просмотров 2,2 тыс.3 года назад
The Tragedy of the Commons
Algorithmic Game Theory - Introduction
Просмотров 7 тыс.3 года назад
Algorithmic Game Theory - Introduction
An FPTAS for the Knapsack Problem
Просмотров 6 тыс.3 года назад
An FPTAS for the Knapsack Problem
Another Dynamic Program for the Knapsack Problem
Просмотров 7823 года назад
Another Dynamic Program for the Knapsack Problem

Комментарии

  • @seeblu
    @seeblu День назад

    Thank you very much.

  • @akshatgupta7471
    @akshatgupta7471 13 дней назад

    10:51 Can you please tell why did you take a triangle as the mixed strategy simplex of the first player? Like can't we take a 1x1x1 cube where the strategy probabilities at any point within it would be its coordinates? The triangle approach doesn't seem so obvious

    • @akhilkammila6910
      @akhilkammila6910 2 дня назад

      Sum of probabilities must be 1. The triangle is effectively the region in the 1x1x1 cube where the sum of points is 1.(try graphing x1 + x2 + x3 = 1)

  • @acliooeye2881
    @acliooeye2881 19 дней назад

    Should it not be strict subset at 0:40?

  • @蒲昊-s6z
    @蒲昊-s6z 20 дней назад

    After normalization of V, why didn't the equation y4+y5=1/V exit?

  • @mahirrahman3363
    @mahirrahman3363 Месяц назад

    Why does evaluating the formula require "some space" c. Why can't we say c = n?

  • @MegaSávioMiranda
    @MegaSávioMiranda Месяц назад

    that means that points (2, 1) and (4, 5) are also Nash Equilibrium because 3 is played with probability 0, right?

  • @A-_AkramahFaizi
    @A-_AkramahFaizi 2 месяца назад

    Thanks for these great lectures. You videos are very easy to understand and follow. Unfortunately in this video I got lost as to why we need n/3 bits of zeros in middle. We could just work with 1 bit of zero. And also, O(k) bits includes all the k times that the tape head leaves the cell in the entire running of TM for palindromes. Then why are we multiplying it with n/3 in the end?

  • @jibbmng
    @jibbmng 2 месяца назад

    I definitely prefer proof 1, it's a nice elegant counting argument, love a good bit of combinatorics. While also valid, the construction in proof 2 feels more contrived, the altering of the original graph obscures the argument a little.

  • @A-_AkramahFaizi
    @A-_AkramahFaizi 2 месяца назад

    Thank You for the Great videos. I have a doubt in this video. You said that after the construction of φ, we can put value of x and leave out t, and if the SAT gives a satisfying assignment, that means a t exist which satisfies φ. Connecting it to one of your starting videos where you mentioned that when constructing TM for taking sum of two numbers, we can represent each bit of numbers with duplicates and the plus sign with 10. So, what if, the satisfying assignment that t gives doesn't correspond to any useful info of the certificate? like in case of sum of two nos. example, the t turns out to be 100110101.... or something, which the TM won't recognize cuz it was expecting duplicates and a 10 in between for sum. I hope I am clear enough in my question. It would be great if you could clear my doubt soon.

  • @mohamedamineaydoun6364
    @mohamedamineaydoun6364 2 месяца назад

    this Problem is truly a fascinating product of the human imagination, i'm obsessed with it, and yes your channel is amazing

  • @ZhengyuanZhou-l4q
    @ZhengyuanZhou-l4q 2 месяца назад

    "There's a subsequence of such triangles such that the three corners all converge to the same point z" may not be true and you don't need it, right? You only need there's a subsequence of red points converging to z, a subsequence of blue points converging to z and a subsequence of green points converging to z. But these three subsequences may come from different triangles.

    • @沈骁瑜
      @沈骁瑜 Месяц назад

      Without the triangle things, how would you argue there’s a subsequence of red, green, blue points that converge to the same point z?

  • @brendawilliams8062
    @brendawilliams8062 3 месяца назад

    If you didn’t consider 324/3244 then it’s all in a mess

  • @brendawilliams8062
    @brendawilliams8062 3 месяца назад

    It’s hard after simple

  • @brendawilliams8062
    @brendawilliams8062 3 месяца назад

    Thankyou.

  • @brendawilliams8062
    @brendawilliams8062 3 месяца назад

    Thankyou. I’ve been desiring information on this. Greatly appreciated

  • @JikeWimblik
    @JikeWimblik 3 месяца назад

    From partial reductions of the napsack problem to combinations of 2 items to sniff out more item variants of the problem with blocks in some parts of the bag as to find clues for your particular napsack problem

  • @taha7shaikh
    @taha7shaikh 3 месяца назад

    Thank you !!!!!

  • @shantanukaushikmathoholic
    @shantanukaushikmathoholic 4 месяца назад

    Lf is basically how to define a set, for which the output is "yes".

  • @shantanukaushikmathoholic
    @shantanukaushikmathoholic 4 месяца назад

    Sire, any book recommendation to along this playlist ?

  • @jasoncotton9804
    @jasoncotton9804 4 месяца назад

    Wouldn't a set of non-result altering transformations which result in True be a verifiable certificate for the Tautology problem? Thanks for the well articulated video.

  • @cikechukwujohn
    @cikechukwujohn 4 месяца назад

    Who is here in August, 2024. I am.

  • @akshatgupta7471
    @akshatgupta7471 4 месяца назад

    can you pls proved the pdfs of your notes? they would be really helpful for revising the concepts

  • @akshatgupta7471
    @akshatgupta7471 4 месяца назад

    thank you very much... this was really helpful :) would be great if you could provide the pdfs of your handwritten notes

  • @adrianho7165
    @adrianho7165 4 месяца назад

    The first proof seems to be easier to come up with

  • @ProfJigsaw
    @ProfJigsaw 5 месяцев назад

    Hello @compscilessons Great work you are doing on this channel. I have a favour to ask of you. I have a paper on computational complexity, more specifically on SAT solving and would like a peer review. Unfortunately, I am unaffiliated with any institutions. Can you give me an endorsement on the preprint server arXiv so that I can make a submission or provide an email address where I can share my paper with you? Any assistance on this is appreciated. Thanks.

  • @dan7nm
    @dan7nm 5 месяцев назад

    Really helpful thanks!

  • @MohdYaseenmas
    @MohdYaseenmas 5 месяцев назад

    Thank you

  • @michaelperry886
    @michaelperry886 6 месяцев назад

    Why is the g in the definition of a reduction taking in both of x and y?

  • @queenpost
    @queenpost 6 месяцев назад

    Very clear explanation - Thanks! One Question: What would we do, if we insist, that the numbers given as instance for the SUBST SUM problem are different to each other?

    • @queenpost
      @queenpost 6 месяцев назад

      O.K., the solution is given at the end!

  • @nicolasgioanni606
    @nicolasgioanni606 7 месяцев назад

    No other video explains the pricing method on weighted vertex covers as well as yours, thank you so much, great video

  • @FabiolaMariaVillatoroGarcia
    @FabiolaMariaVillatoroGarcia 7 месяцев назад

    You are genuinely awesome.

  • @halchen1439
    @halchen1439 7 месяцев назад

    you are single handedly saving my ass. may your soul be blessed

  • @olxxa4967
    @olxxa4967 7 месяцев назад

    Anyway, thank you. This video helped me a lot 🎉

  • @olxxa4967
    @olxxa4967 7 месяцев назад

    Can you please do the colonel Blotto game

  • @nothingspecial2018
    @nothingspecial2018 8 месяцев назад

    you did good job but my stoopid self could not understand it.

  • @ElIrracional
    @ElIrracional 8 месяцев назад

    Why is that true? What about a clause of the form: x and ~y? It is not satistied when x and y are true and not satisfied when x and y are false.

  • @liamtolkkinen5025
    @liamtolkkinen5025 8 месяцев назад

    you really don't explain things well

  • @welfarewagonrepairs
    @welfarewagonrepairs 8 месяцев назад

    This was a very helpful explanation. The part after 13:00 was especially helpful explaining the purpose of the additional rows

  • @laautaro11
    @laautaro11 8 месяцев назад

    Your channel is the best theoretical CS channel I've seen, fantastic job! thank you!

  • @lucasarif4387
    @lucasarif4387 8 месяцев назад

    when you wrote down that proof idea at 2:30 my mouth started watering lets see where this goes

  • @lucasarif4387
    @lucasarif4387 8 месяцев назад

    this module is so so good

  • @gate_dose
    @gate_dose 8 месяцев назад

    Thank You!!

  • @ShakrinJahanMozumder
    @ShakrinJahanMozumder 8 месяцев назад

    Thanks!

  • @AamirMohamedThahirAli-x5z
    @AamirMohamedThahirAli-x5z 9 месяцев назад

    thank you so so so so much!!! you explain everything so clearly!!!!

  • @manawa3832
    @manawa3832 9 месяцев назад

    i am going to now define the concept of mebeingfkingright. this foundational principle, now called mebeingfkingright, will be proven in the following way. i propose a machine, called the RightMachine that lays out a sequence of adjacent symbols. in each symbol is encoded the final position of the symbol to the left of itself or non at all. the machine beingfkingright at r0 and ends at r-finished. any sequence that this machine can lay down is said to be mebeingfkingright. therefore mebeingfkingright is any seqquence of symbols of mebeingfkingright that the RightMachine can process i.e. can go from r0-r-finish. tada the same level of proof as computability in this turing complete nonsense. the entire field of computer science folks.. like seriously without information theory and linguistics, computer science would just be a joke based on the inane crackpot nonsense of two guys during ww2.

  • @alieser7770
    @alieser7770 10 месяцев назад

    Sir, you are doing God's work

  • @abdurrahmanyakar3040
    @abdurrahmanyakar3040 10 месяцев назад

    Teacher, time 1:01, you write a f:{0,1}*: What does asterisk (*) mean?

    • @compscilessons
      @compscilessons 10 месяцев назад

      The * is referred to as the Kleene star. {0,1}* is the set of all bitstrings of arbitrary (but finite) length. This includes the empty string, i.e., the string that has length 0.

  • @alexdolan9373
    @alexdolan9373 10 месяцев назад

    Yup im bout to fail my exam lol

  • @EntertainmentUnit
    @EntertainmentUnit 10 месяцев назад

    Was the question "What is Computation?" ever directly answered? Is a computation one run of a Turing machine from q_start to q_end? But even that doesn't answer the question, it only provides an example of a computation which is different than defining it.

  • @alexvisan7622
    @alexvisan7622 10 месяцев назад

    Thank you!