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Computer Science Theory Explained
Великобритания
Добавлен 24 июн 2020
Binary vs. Unary Number Encodings and Strong NP-completeness
Textbooks:
Computational Complexity: A Modern Approach by S. Arora and B. Barak.
Algorithm Design by J. Kleinberg and E. Tardos.
Lecture slides by K. Wayne accompanying the latter textbook:
www.cs.princeton.edu/~wayne/kleinberg-tardos/
Computational Complexity: A Modern Approach by S. Arora and B. Barak.
Algorithm Design by J. Kleinberg and E. Tardos.
Lecture slides by K. Wayne accompanying the latter textbook:
www.cs.princeton.edu/~wayne/kleinberg-tardos/
Просмотров: 1 442
Видео
The Lemke-Howson Algorithm - Complementary Pivoting
Просмотров 3,8 тыс.3 года назад
The Lemke-Howson Algorithm - Complementary Pivoting
The Lemke-Howson Algorithm - Best Response Polytopes
Просмотров 3,4 тыс.3 года назад
The Lemke-Howson Algorithm - Best Response Polytopes
The Lemke-Howson Algorithm - Best Response Diagrams
Просмотров 4,8 тыс.3 года назад
The Lemke-Howson Algorithm - Best Response Diagrams
Colorability of Planar Graphs
Просмотров 1,7 тыс.3 года назад
Textbooks: Computational Complexity: A Modern Approach by S. Arora and B. Barak. Algorithm Design by J. Kleinberg and E. Tardos. Lecture slides by K. Wayne accompanying the latter textbook: www.cs.princeton.edu/~wayne/kleinberg-tardos/
Nash's Theorem
Просмотров 2,6 тыс.3 года назад
John Nash's PhD Thesis: library.princeton.edu/special-collections/sites/default/files/Non-Cooperative_Games_Nash.pdf
Two-Player Zero-Sum - a Second Example
Просмотров 1,4 тыс.3 года назад
Two-Player Zero-Sum - a Second Example
Existence and Computation of Nash Equilibria in Two-Player Zero-Sum Games
Просмотров 2 тыс.3 года назад
Existence and Computation of Nash Equilibria in Two-Player Zero-Sum Games
A Brief Linear Programming Refresher
Просмотров 1,2 тыс.3 года назад
A Brief Linear Programming Refresher
The Poisened Drink and the Mixed Nash Equilibrium
Просмотров 1,2 тыс.3 года назад
The Poisened Drink and the Mixed Nash Equilibrium
The Battle of the Sexes and Burning Money
Просмотров 1,5 тыс.3 года назад
The Battle of the Sexes and Burning Money
Pure Nash Equilibrium - a Further Example
Просмотров 8843 года назад
Pure Nash Equilibrium - a Further Example
The Iterated Elimination of Dominated Strategies
Просмотров 2,2 тыс.3 года назад
The Iterated Elimination of Dominated Strategies
Dominating Strategies in the Prisoner's Dilemma
Просмотров 1,4 тыс.3 года назад
Dominating Strategies in the Prisoner's Dilemma
The "Tragedy" in the Tragedy of the Commons
Просмотров 1,8 тыс.3 года назад
The "Tragedy" in the Tragedy of the Commons
Algorithmic Game Theory - Introduction
Просмотров 7 тыс.3 года назад
Algorithmic Game Theory - Introduction
Another Dynamic Program for the Knapsack Problem
Просмотров 7823 года назад
Another Dynamic Program for the Knapsack Problem
Thank you very much.
10:51 Can you please tell why did you take a triangle as the mixed strategy simplex of the first player? Like can't we take a 1x1x1 cube where the strategy probabilities at any point within it would be its coordinates? The triangle approach doesn't seem so obvious
Sum of probabilities must be 1. The triangle is effectively the region in the 1x1x1 cube where the sum of points is 1.(try graphing x1 + x2 + x3 = 1)
Should it not be strict subset at 0:40?
After normalization of V, why didn't the equation y4+y5=1/V exit?
Why does evaluating the formula require "some space" c. Why can't we say c = n?
that means that points (2, 1) and (4, 5) are also Nash Equilibrium because 3 is played with probability 0, right?
Thanks for these great lectures. You videos are very easy to understand and follow. Unfortunately in this video I got lost as to why we need n/3 bits of zeros in middle. We could just work with 1 bit of zero. And also, O(k) bits includes all the k times that the tape head leaves the cell in the entire running of TM for palindromes. Then why are we multiplying it with n/3 in the end?
I definitely prefer proof 1, it's a nice elegant counting argument, love a good bit of combinatorics. While also valid, the construction in proof 2 feels more contrived, the altering of the original graph obscures the argument a little.
Thank You for the Great videos. I have a doubt in this video. You said that after the construction of φ, we can put value of x and leave out t, and if the SAT gives a satisfying assignment, that means a t exist which satisfies φ. Connecting it to one of your starting videos where you mentioned that when constructing TM for taking sum of two numbers, we can represent each bit of numbers with duplicates and the plus sign with 10. So, what if, the satisfying assignment that t gives doesn't correspond to any useful info of the certificate? like in case of sum of two nos. example, the t turns out to be 100110101.... or something, which the TM won't recognize cuz it was expecting duplicates and a 10 in between for sum. I hope I am clear enough in my question. It would be great if you could clear my doubt soon.
this Problem is truly a fascinating product of the human imagination, i'm obsessed with it, and yes your channel is amazing
"There's a subsequence of such triangles such that the three corners all converge to the same point z" may not be true and you don't need it, right? You only need there's a subsequence of red points converging to z, a subsequence of blue points converging to z and a subsequence of green points converging to z. But these three subsequences may come from different triangles.
Without the triangle things, how would you argue there’s a subsequence of red, green, blue points that converge to the same point z?
If you didn’t consider 324/3244 then it’s all in a mess
It’s hard after simple
Thankyou.
Thankyou. I’ve been desiring information on this. Greatly appreciated
From partial reductions of the napsack problem to combinations of 2 items to sniff out more item variants of the problem with blocks in some parts of the bag as to find clues for your particular napsack problem
Thank you !!!!!
Lf is basically how to define a set, for which the output is "yes".
Sire, any book recommendation to along this playlist ?
Wouldn't a set of non-result altering transformations which result in True be a verifiable certificate for the Tautology problem? Thanks for the well articulated video.
Who is here in August, 2024. I am.
can you pls proved the pdfs of your notes? they would be really helpful for revising the concepts
thank you very much... this was really helpful :) would be great if you could provide the pdfs of your handwritten notes
The first proof seems to be easier to come up with
Hello @compscilessons Great work you are doing on this channel. I have a favour to ask of you. I have a paper on computational complexity, more specifically on SAT solving and would like a peer review. Unfortunately, I am unaffiliated with any institutions. Can you give me an endorsement on the preprint server arXiv so that I can make a submission or provide an email address where I can share my paper with you? Any assistance on this is appreciated. Thanks.
Really helpful thanks!
Thank you
Why is the g in the definition of a reduction taking in both of x and y?
Very clear explanation - Thanks! One Question: What would we do, if we insist, that the numbers given as instance for the SUBST SUM problem are different to each other?
O.K., the solution is given at the end!
No other video explains the pricing method on weighted vertex covers as well as yours, thank you so much, great video
You are genuinely awesome.
you are single handedly saving my ass. may your soul be blessed
Anyway, thank you. This video helped me a lot 🎉
Can you please do the colonel Blotto game
you did good job but my stoopid self could not understand it.
Why is that true? What about a clause of the form: x and ~y? It is not satistied when x and y are true and not satisfied when x and y are false.
you really don't explain things well
🥺
This was a very helpful explanation. The part after 13:00 was especially helpful explaining the purpose of the additional rows
Your channel is the best theoretical CS channel I've seen, fantastic job! thank you!
when you wrote down that proof idea at 2:30 my mouth started watering lets see where this goes
wow. beautiful
this module is so so good
Thank You!!
Thanks!
thank you so so so so much!!! you explain everything so clearly!!!!
i am going to now define the concept of mebeingfkingright. this foundational principle, now called mebeingfkingright, will be proven in the following way. i propose a machine, called the RightMachine that lays out a sequence of adjacent symbols. in each symbol is encoded the final position of the symbol to the left of itself or non at all. the machine beingfkingright at r0 and ends at r-finished. any sequence that this machine can lay down is said to be mebeingfkingright. therefore mebeingfkingright is any seqquence of symbols of mebeingfkingright that the RightMachine can process i.e. can go from r0-r-finish. tada the same level of proof as computability in this turing complete nonsense. the entire field of computer science folks.. like seriously without information theory and linguistics, computer science would just be a joke based on the inane crackpot nonsense of two guys during ww2.
Sir, you are doing God's work
Teacher, time 1:01, you write a f:{0,1}*: What does asterisk (*) mean?
The * is referred to as the Kleene star. {0,1}* is the set of all bitstrings of arbitrary (but finite) length. This includes the empty string, i.e., the string that has length 0.
Yup im bout to fail my exam lol
Was the question "What is Computation?" ever directly answered? Is a computation one run of a Turing machine from q_start to q_end? But even that doesn't answer the question, it only provides an example of a computation which is different than defining it.
Thank you!