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Okay thanks for letting me know. I'll put that right.

Well done!

I'm glad you've found this video helpful. Thanks for watching!

Thanks for pointing that out. I'll put that right!

Thanks! Glad you enjoyed it!

You're welcome. Thanks for watching!

Okay thanks for pointing that out. I'll put that right!

Okay thanks for letting me know. I'll get that put right!

Thanks very much. Much appreciated! I'll get some OCR papers published. I'll try and go for the most recent. Any questions give me a shout.

No problem. I'll get a link put in the description.

You're welcome. I'm glad the video helped you out!

You're welcome. I'm glad the video was helpful!

You're welcome 😊

NAHH RAYAAN

Thanks a lot. I'm glad the video was helpful!

Okay thanks. That's all been put right.

Thank you. I'm glad the video really helped!

Don't be sorry! That's all done. Thanks again.

for question 2

@@earthcrafter3240 Yes that should be 1.248 x 10^-2. I'll put that right. Thanks for pointing that put.

Thanks for pointing that out. I'll put that right!

In Q12 part a since matches come in whole numbers, the next value up would be 205. But if you notice because it's a less than or equal to sign, if we were to put 205, it would be rounded up to 210. If it was strictly less than 205, we would have got away with putting 205. For part b, by definition upper bounds don't necessarily mean the highest possible values, it just means strictly less than 7.5 and 5.5 which therefore means these values would still be rounded down to 7 and 5. Hope that makes sense. I'll put question 20 right, that should say 3/4, thanks for pointing that out.

It's just a predicted past paper. As soon as the real 2024 paper becomes available, I get it posted. Hope that helps.

Thanks RonAdie!

It's just the predicted past paper. As soon as the real 2024 paper becomes available I get it posted. Hope that helps.

This would just be the predicted paper. As soon as the actual paper becomes available I'll get it uploaded. Hope that helps.

You're welcome 😊

Thank you!

No problem at all. Any questions give me a shout!

I've just checked question 25. It's all correct. f=4 and n=21. If you substitute those values back into the table and work out the mean you should get a mean value of 5.5.

This paper is a prediction of the actual paper. As soon as the official June 2024 paper becomes available I'll get it posted. Hope this helps.

Thanks for pointing that out. I'll get that put right.

@@matt-tutorialsno problem

If you look at the center (3, -5) the vertical distance from the center of the circle and the x-axis is 5. Hence if the radius was exactly 5 the circle would be just touching the x-axis and if it was greater than 5 then the circle would be overlapping the x-axis. Hope that helps.

Thank you! Glad it was helpful!

This is just a predicted past paper. The actual paper this year isn't yet available.

Yes this is the official paper 3.

I've just got this corrected. Thank you.

It should actually just say 34-k. Thanks for pointing that out! We are not required to work out r but since r^2 > 0 (because all square numbers are positive), and r^2 = 34 - k, that means 34-k must also be positive, hence 34-k > 0 and 34 > k which is the same as k < 34. Hope that helps!

You're welcome. Thanks for watching!

I'm glad you've found the video helpful. Drop me a comment if there's anything you're not sure about. I'll try and reduce the music volume :)

Hi Ken. I think it's only the June 2024 papers that are restricted. There's other youtube channels who have posted the same content from months ago. The papers are available online. As far as I'm aware all is in order.

If the radius is equal to or greater than 5, the circle will then be touching the x-axis. But in the question, it says that the circle cannot touch the x-axis. Hope that helps.

@@matt-tutorials Ahh i get it thank you!!

I've actually skipped a couple of important steps. The best thing to do is put the quartic in the form (x^2 + ax + b)(x^2 + cx + d). After you've multiplied out the brackets, you can then equate coefficients of x^3, x^2, x and the constant term and use simultaneous equations to work out the coefficients in terms of p. Hope that will be of help.

You're welcome. Glad you've found this video helpful. Thanks for watching!

Is it just by inspection?

@@Endy0620 Sorry for the delay. A couple of important steps have actually been missed. You need to put the quartic in the form (x^2 + ax + b)(x^2 + cx + d). After you've multiplied out the brackets, you can then equate coefficients of x^3, x^2, x and the constant term and use simultaneous equations to work out the coefficients in terms of p. That should do the job.

@@matt-tutorials thanks!

You're welcome. If you have any questions please let me know.

You're welcome. If you have any questions please let me know