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greate job............well done

Thank you so much!!!! I've looking everywhere and only your video helped me to actually do the exercise. Your video is very much practical. Thanks!

Pls on the number line X>3 should be 1 not 0

wonderful great explanation thank you mam

Thanks ❤❤❤❤

😲😲🙀🙀😃😃😯😯

Next video upload please

I love you great ever!

A thumbs up for the amazing explanation.

numb digger

Wheres the continuation of this lecture?

Wheres the continuation of this lecture?

Where's the continuation of this video?

Thanks

Given: .5x, x E [0, 1] .5, x E [1, 2] .5(3-x), x E [2, 3] 0 otherwise We calculate the indefinite integrals of each, which I will mark with "I#", where # is the number, and I stands for integral: I1 = .25x^2 I2 = .5x I3 = 1.5x - .25x^2 Now evaluate each one within each interval. "E" stands for evaluated, "#" for number E1 = I1[0 to 1] (.25 - 0) = .25 E2 = I2[1 to 2] = (1 - .5) = .5 E3 = I3[2 to 3] = (2.25 - 2) = .25 In this process, we also found what it was evaluated at for each lower bound. Let's mark these as LI#: LI1 = 0, LI2 = .5, LI3 = 2 Resulting CDF is: 0, x < 0 I1, x E [0, 1] I2 - LI2 + E1, x E [1, 2] I3 - LI3 + (E1 + E2), x E [2, 3] 1, x > 3 Evaluated: 0 .25x^2 = x^2/4 .5x - .25 = x/2 - 1/4 1.5x - .25x^2 - 1.25 = 3/2x - x^2/4 - 5/4 1 SUMMARIZED: Current Integral (CI) - CI Lower Bound + Previous Integrals Evaluated

Awesome explanation 😊❤😊

Superb explanation 😊 thanks ma'am 🙌🏻💗

she is just a wonderful lady

clear

following your lecturs for past 5 years maam , you were truly a life saviour for me . Thankyou

Mam could you please check the answer for 9th question. Thank you

Nice teachings method 🥰

Normal distribution activity starts at 2.10 min. Before that, I discussed how to install data analysis add-ins required in Excel.

I was soo confused between those limits 😞 and thanks alot...for helping us thank you ma'am ❤

Mam u just killed it

Thank you!

Very well explained. Thank you so much

why in the cdf 4th integration the limit is 2 to x and not 2 to 3?

There is a correction:- @ 4.30 , while explaining CDF on a number line, F(x)=1 for x >=3. Kindly rectify it

Can you explain how the inequalities can be inclusive on both ends for the cdf? Shouldn't some of them be just < instead of < or equal to? Thank you.

much appreciated

On question 2, I don't see the range

I was very confesed why we are taking 1 at the last though it has 0 for x>3 but now i understood thank u mam

Great Explanation ma'am👍🏼

Hare Krishna 🙏🏻🌸 Bestest❤

Thank you

Thank you

13:36 Integral of 0 is 0 + constant.

Mam can you tell me from which textbook this example was taken from ?

Most underrated channel on youtube , you're teaching is more expensive than the he teacher whom I pay thousands monthly

Thank u so much! Good explanation :D

Thank you👌, you have explained heat equations in 12 minutes that my lecturer couldn’t explain in 2 hours 👌

Thanks madam for digesting the concept for me

nice

thank you, a lot of teachers ignored to mention the fact that when u have a 2nd order eqn you gotta check the k=0, k+ and k-, i saw them do it and i was really confused, your videos are short and brief but it answered most of my questions!

F(x) = 1 hoga na greater then 3

thanks a lot

Best explnation

Thank you so much for a clear explanation🤌🤌🤌