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1^1^1^1➖ 1^2^3 2^3 (x ➖ 3x+2).

2^16 - 3^8 = 1024 × 64 - 81^2 = 65536 - 6561 = 58975

2^2^2^2-3^2^3 =2^2^4-3^8 =2^16-3^4*3^4 =65536-81*81 =65536-6561 =58975

I did it in my head.

2^2^2^2-3^2^3=58975

2^(n+1)-2^n=2^n et a^2-b^2=(a+b)(a-b) 2^12=2048 S= 2051*2045=4194295

50^4(50^2-1)=50^4(50+1)(50-1)=50^4×51×49 =6250000×51×49

4^9-1234=262144-1234 =260910

50^6 - 50^4 = (100^6 - 4 * 100^4) / 2^6 = (1,000,000,000,000 - 400,000,000) / 2^6 = (250,000,000,000 - 100,000,000) / 2^4 = (62,500,000,000 - 25,000,000) / 2^2 = (15,625,000,000 - 6,250,000) = 15,625,000,000 - 6,250,000 ============== = 15,618,750,000

2^(2a)-2^(2b)•3^(2b)=2^2•7 2^(2b)[2^(2a-2b)-3^(2b)]=2^2•7 2b=2,b=1 2^(2a-2)-3^2=7 2^(2a-2)=16=2^4 2a-2=4,a=3

2^10(2+4+8+16)=1024•30= 30720

(a•b•c)^2=100•200•300=6•10^6 abc=(+-)6^(1/2)•10^3 a=abc/bc=(+-)5•6^(1/2) b=abc/ca=(+-)(10/3)•6^(1/2) c=abc/ab=(+-)10•6^(1/2)

2^24-9=(4100-4)^2-9= 16810000-32800+16-9= 16777207

4^9-1234=(2^9)^2-1234= (500+12)^2-1234= 250000+12000+144-1234= 262000-1100+10=260910

50^4(50^2-1)= 6250000•(2500-1)= 15625000000-6250000= 15618750000

4**3x4**3=4**6

It's not an equation and there's nothing to solve. It should say: calculate the number.

5^6 = 15625 , 5^4 = 625 Ans is 15625000000 - 6250000 = 15618750000

In my head I immediately got 1/15=2/30 =2*{1/30}, i.e. a=b and so a+b=30+30=60. But in fact I forgot about other possible solutions-like you! Not so easy, thanks for sharing!

2856

(0+0 ➖) ^2=1^2 (x ➖ 2x+1).

50^6-50^4=15618750000 It’s in my head.

Id est 4^9= 1234 Or 64 ×64× 64= 1234,or8 ^6= 1234,or 512^3= 1234😅😊😢😂

2^2^1^1^1 ➖ 1^2^3^2^2 1^1 ➖ 1^1^3^1^2 3^2 (x ➖ 3x+2).

I also ansuer like you😊

4^6-3^8 4×4×4....6times_3×3×3×3...8times 64×64-81×81. (64+81)(81-64) 145×17 2465 4+81) 6:20

9^9 - 99 = (10 - 1)^9 - 99 = = 1000000000 - 900000000 + 360000000 - 84000000 + 12600000 - 1260000 + 84000 - 3600 + 90 - 100 = 1372684090 - 985263700 = = 387420390 😁

4^3^2^1-1234=260910 It’s in my head.

2^1=2, so we can ignore the 1 3^2=9 4^9=2^18 Ok, 2^18 is easy for IT guys: 262144 262144-1234=260910

❤❤

37448

1/15=(1•16)/(15•16)=15/(15•16)+1/(15•16)=1/16+1/240 a+b=16+240=256

I think that the solution is incomplete. 1) there are more factors to 225 to consider - 3x75 and 45x5; 2) there should be seven possible cases and we will only know which one is right by substituting the solutions back into the original equation to see which one fits.

1/(7)+1/(8) =1/15 1/(7)+1/(2^3) (1/(3^4)+1/(1^1^1) 1/(3^2^2) 1/(3^1^2) = /(3^2) (x ➖ 3x+2).

Nice

3×75 or 75×3, 5×45 or 45×5??

P=given formula P=A-1/A A=4^8/8^4 =2^16/2^12=2^4=16 P=16-1/16=255/16

(4^8=2^16)/ (8^4=2^12) =2^4=16; => (8^4)/4^8)=1/16; => E=(16-1/16) =255/16

2^2^2^3/2^3^2^2 ➖, 2^3^2^2/2^2^2^3.1^1^1^1^1/1^1^1^1^1 ➖, 1^1^1^1^1/1^1^1^1^2 /1^2 (x ➖ 2x+1).

4^4•(1/2)^4-2^4•(1/4)^4= 2^4-(1/2)^4=16-1/16=15+15/16

4^8=4^4 * 4^4=256*25665536 8^4=8^4 * 8^4=64*64=4096 65536/4096-4096/65536=16-1/16=255/16

(4^8)/(8^4)-(8^4)/(4^8)=255/16=15 15/16=15.9375

3^3^3^3 ➖ 3^3^3^3 1^1^1^1 ➖ 1^1^1^3 1^3 (x ➖ 3x+1).

If you are going to calculate it manually, then there is a much more easier and straight forward way to do it: 9^2 = 81 9^4 = 81^2 = (80 + 1)^2 = 80^2 + 2*80*1 + 1^2 = 6400 + 160 + 1 = 6561 9^8 = 6561^2 = 6561 * 6 * 1000 + 6561 * 5 * 100 + 6561 * 6 * 10 + 6561 * 1 * 1 9^8 = 39366 * 1000 + 32805 * 100 + 39366 * 10 + 6561 9^9 - 99 = 9 * (9^8 - 11) = 9 * (39366 * 1000 + 32805 * 100 + 39366 * 10 + 6561 - 11) = 9 * (39,366,000 + 3,280,500 + 393,660 + 6,550) = 9 * x where x = 39,366,000 + 3,280,500 + 393,660 + 6,550 _________________ = 43,046,710 9^9 - 99 = 9 * 43,046,710 = 387,420,390

71•9^6=71•81•81•81= (70+1)(80+1)•(80+1)(80+1)= (5600+150+1)(6400+160+1)= 35840000+896000+5600+960000+24000+150+6400+160+1= 36800000+920000+12000+311= 37732311

9^6(71)

71 is the ans

= (8^5+ 8^4 + 8^3) + (8^2+ 8 + 1) = (8^3 + 1)(8^2 + 8 +1 ) = (8 +1)(8^2 - 8 + 1)(8^2 + 8 + 1) = 9*57*73 =37449

11

3^11-11=81•81•27-11= 81•(2400-240+30-3)-11= (80+1)(2190-3)-11= 80•2190-240+2190-3-11= 175200+1950-14=177150-14= 177136