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ncert class 10 ex 8.1 q 5 | trikonmiti prashnavali 8.1 q 5 | ncert class 10 ex 8.1 q 5
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ex 8.1 | ex 8.1 class 10 | class 10 maths | trigonometry class 10 | ex 8.1 q 4 class 10 maths |
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संजीव सर ने पढ़ाया ऐसा सवाल जो जिंदगी भर नहीं भूलोगें | ex 5.1 class10 maths
Просмотров 52Месяц назад
संजीव सर ने पढ़ाया ऐसा सवाल जो जिंदगी भर नहीं भूलोगें | ex 5.1 class10 maths
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Thankyou sir
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❤❤❤❤👍👍👍👍👍
❤❤❤❤❤❤❤❤❤
Padha rhi ho ki dara rhi ho😂😂😂😂
Right bro🤣🤣
Sir mujhe समझ आ गया
Ok beta
<AOB=360-260=100deg. and<APB=100/2=50deg.ans
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Prabhakar Gautam school
Om Kumar
Sir thoda noice sahi Karo background noice bahut aa rha h 😅
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Kya kar rahe ji?
Harmi
very good😊
चक्रीय चतुर्भुज nahi है
<APB=100/2=50deg.as<AOB=100Deg.
Good sir 0:42 0:44 ji❤❤❤
80
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P 50 q 100
महोदय, चतुर्भुज AQBO के चारों कोण का योग = 360° कोण OAQ = 90° ,कोण OBQ = 90° और कोण AQB =80° . इस तरह , कोण OAQ+ कोणAQB+ कोणOBQ+ कोण AOB = 360° => 90°+80°+90°+कोण AOB =360° =>260° + कोण AOB = 360° =>कोण AOB = 360° - 260° = 100° अब, कोण APB =1/2 कोण AOB अतः कोण APB = 1/2 × 100°. = 50°. विषय की पूरी जानकारी न हो तो पढ़ाने का प्रयास नहीं करना चाहिए ।
<A and <B r complimentary.
Sir 8 th or 10 th same hi hota hai naa Matalb thoda hi different hota hai naa Sir please reply me😢
अपना कम्पास को सही करो
Kindergarten class को पढ़ा रहे हो क्या?
C
Prem, &&&&@@%€¥^
200 degree
Ap mehnat to kafi kr rahe hain pr cahnnel me kuchh gadbad hai sir
Ho sakta hai
Jankari ho to please bata dijiye
,<AOB =100⁰ <APB = 50⁰
SR parallel PQ and sp transversal.<P=180-85=95 deg. and <Q=180-80=100 deg
trgleBAO and CAO R congruent by RHS rule.thua<BAO=<CAO/2.
<BAO=90-55=35deg.
34
पहले पढ़ लो फिर पढ़ाना।
ANGLE AOB = 2(180-40-90) = 100 ANGLE APB = 100/2 = 50
Super sir ji❤❤❤❤
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ये चतुर्भुज चक्रिया नहीं है
राइट।
Sir 1.2 Kai savaal likhea❤❤❤
Hi
Sir First Answer ka methed wrong hai
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