Видео

Thanks for the breakdown! A bit off-topic, but I wanted to ask: I have a SafePal wallet with USDT, and I have the seed phrase. (alarm fetch churn bridge exercise tape speak race clerk couch crater letter). Could you explain how to move them to Binance?

How would you use l'hopital's rule if the function is not a fraction like xe^(1/x) as x approaches 0

Excellent

really helpful. thanks

Thnx it is so much helpful 😁❤

k(m)k(n) = k^2(mn) = k(mn)

81

Excellent video! Merry Christmas ; )

Thank you sumchief

Great video, but as you said in your other video the sum of columns and rows of non principal characters must be zero, but sum of your 13 and 7 column don't add to zero, couldn't we distribute the minus signs in column 17 in a different order to get sums add to zeros everywhere?

If you already know that the derivative of sin(x) is equal to cos(x), why do you calculate the limit of sin(x)/x approaching 0 ?

Thanks!

Thanks. At 11:20 some people might recognize ((x squared) - 1) = (x+1)(x-1). A substitution would produce (x to the fourth power) . Long division might not be necessary.

why you didn't divide by 2 immidiately after 2x^2 - 12x + 4 = 0 (mod 19) --> x^2 - 6x + 2 = 0 (mod 19) --> x^2 - 6x + 9 = 7 (mod 19) --> (x - 3)^2 = 7 (mod 19)?

thank you for this video, it is clear but you must replace B by Bn and you find y(x)=sum (i between 0 and n) of Bn sin[(n Pi ln(x)/ln(2)]/x

thank you for this video, it is clear but you must replace B by Bn and you fon y(x)=sum (i between 0 and n) of Bn sin[(n Pi ln(x)/ln(2)]/x

tanz = sinz/cosz then from cosz cames others singularities I think.

Thank you

Mangoldt, not Margoldt and this is NOT a proof, just a demonstration for n=18.

Well explained and very clear. Thank you!

You read out 26962 backwards!

That was a clear explanation! I needed it for my homework in theory on statistical inference.

This is easy to understand and very helpful, thank you.

Thank you for another excellent video. I love complex analysis, and have always found your complex analysis videos to be the best.

👍

Shouldn’t x = 0, 1?

Your Chi's look more like X's. Yuck.

i thought it was a finite expansion lol. i was also thinking of pi as an exponent, i guess it'll have inifinite terms like these.

Hi, Can you explain the error function `log(n)/10` please.

goddamn math is so fucking boring it should basically be done by machines at this point, why do we humans even bother at this point it's just a series of subtle and pedantic rules applied over and over again? we should do it all via computers except for maybe 1000 humans who dedicate their lives to actually advancing the field. just kill me already.

What if you get a case where you cannot easily find a square number for the square root? Eg: x^2+5x+1 = 0 (mod 13)

First!

why not 2x^2+16x+34=t^2

Hey, I'm not sure what the purpose of the video is. I teach math at university, and I gotta tell you that substituting 2x^2+16x+34 gives you an immediate answer to the problem. No logarithm no sec function. Did you just wanna try to make things extra complicated? Seems a little disingenuous and leads people to believe that math is difficult. This video does math a disservice.

If you divide that final equation by 2 on both sides, don't you get a different radius?

Great job as always. Thank you!

To nie jest szereg, dziecko, a jego kawalek, czyli wielomian Taylora ) Dislajk.

Thank you! Especially for explaining this with an actual example. I've been going nuts trying to figure out residues and everything I look in always seems to hide the ball.

Very useful, but I don't think I quite get why (A = -5/4) instead of (A = 4/-5).

These are great! But I have a question/problem arising from 8:05 in video. If we expect pointwise convergeance then result holds and is good and wholeseome. If I say, well look - I need an error bound on this. If it approaches a fixed point with error bound plus or minus one ± 1 say inclusive on [-1, 1] then a finite number of ambiguities arise. Can I say it does converge to zero with error ε in [-1, 1] or equivalently it converges to 1 within error ranging [-1, 1] or converges to -1 within error ranging [-1, 1] AS far as I am concerned, say, an error bound of ±2 on the limit value is perfectly acceptable 0 ±1 or 1±2 or -1±2 is acceptable on ± infinity ?

Amazing 🤩

Not clear video

Thank you so much

2025 who'se watchign

hell yeah man, thanks for the help

I echo the previous three comments and ponder: Hey! Where is Prime Number Theorem? I can't find it - googled it and results speaks in a language I have yet to understand. I am sure your version will make more sense to me (please?)

This is going to make me kill mysefl

In 15:37 -3 is congurent to 5 mod 8 and not 5 mod 4 right?

Thank you! So helpful!

Of cosh you went on a tangent, and it was complex, but it was also great!