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Rash Quanty Maths
Добавлен 8 июн 2024
Simplification of Radical Nested Exponential Expression and Application of Difference of 2 Squares
How to Simplification Radical Nested Exponential Expression Using Difference of 2 Squares Rule to finalize
Просмотров: 298
Видео
Math Olympiad A tricky Exponential equation Solution 1÷k^5 k^4÷3^k = 0
Просмотров 236День назад
Math Olympiad A tricky Exponential equation Solution 1÷k^5 k^4÷3^k = 0
GH Tricky Exponential Equation Solution 256 ^x - X^(-1) = 0
Просмотров 128День назад
GH Tricky Exponential Equation Solution 256 ^x - X^(-1) = 0
Math Olympiad Solving Radical Equation Using Algebraic Identities
Просмотров 166День назад
Solve a challenging Math Olympiad radical equation using algebraic identities! Watch as I break it down step by step and share tips for tackling similar problems. Don’t forget to like, comment, and subscribe for more exciting math content!
Solving the Nested Radical Equation: √X√X√X√X = 125^5⁄8
Просмотров 4182 дня назад
In this video, we tackle an exciting and challenging nested radical equation involving powers and roots: √X√X√X√X = 125^(5/8). Step by step, I’ll show you how to simplify and solve this equation using algebraic techniques and properties of exponents. If you love solving math puzzles or preparing for competitions, this video is perfect for you!
Math Olympiad: Advanced Exponential Equation
Просмотров 40614 дней назад
An Intriguing Math Olympiad: Advanced Exponential Equation Step-by-Step Solution
Math Olympiad: A Simple Tricky Exponential Equation
Просмотров 46614 дней назад
Math Olympiad: A Simple Tricky Exponential Equation
TaTU GH Simplifying Radical Expression
Просмотров 19521 день назад
Simplifying Radical expression step by steop
Simple Exponential Equation SQR5^(x+5) = 5^3÷x p
Просмотров 49021 день назад
Simple Exponential Equation SQR5^(x 5) = 5^3÷x p
Simplification of Radical Nested Exponential Expression
Просмотров 2,7 тыс.Месяц назад
Stepby step procedure of simoplifying teteration expression
EXPONENTIAL EQUATION WITH COMPLEX NUMBERS
Просмотров 307Месяц назад
Learn how to solve exponential equations with complex numbers.
TaTU Math Olympiad Radical Equation 2x + 2y = 5(xy)^0.5
Просмотров 343Месяц назад
How to Solve Radical Equations Using Indices and Algebraic Identities
Math Olympiad Exponential Equation 8^y^2 2y+2 4^y^2 2y+2=48 P
Просмотров 162Месяц назад
How to solve math Olympiad Exponential Equation 8^y^2 2y 2 4^y^2 2y 2=48. The Application of Algebraic Identity.
Simplify without Calculator (39^3 +19^3)/(20^3 +39^3)
Просмотров 1912 месяца назад
we tackle a unique algebra problem that involves simplifying a complex fraction: (39^3 19^3)/(20^3 39^3) without using a calculator! Follow along to see the steps and logic required to break down this expression using algebraic identities and clever problem-solving techniques. This method will strengthen your skills in simplifying large expressions efficiently and is perfect for those intereste...
GH TaTU Beautiful Olympiad Maths Problem Solved (6+√35)^x+ (6 - √35 )^x=142
Просмотров 1772 месяца назад
GH TaTU Beautiful Olympiad Maths Problem Solved (6 √35)^x (6 - √35 )^x=142
MATH 101 Math Olympiad: Solve √71 + 12√35
Просмотров 2312 месяца назад
MATH 101 Math Olympiad: Solve √71 12√35
TaTU Math Olympiad: Solving nonlinear equations for entrance exams. Find (x, y) values step-by-step
Просмотров 3882 месяца назад
TaTU Math Olympiad: Solving nonlinear equations for entrance exams. Find (x, y) values step-by-step
Solving an Advanced Square Root Equation | Technical University BSc Math Entrance Exam
Просмотров 7952 месяца назад
Solving an Advanced Square Root Equation | Technical University BSc Math Entrance Exam
A tricky Maths Olympiad Exponential Equation: x^8 4^x=0
Просмотров 3792 месяца назад
A tricky Maths Olympiad Exponential Equation: x^8 4^x=0
A Special Maths Olympiad Equation |x +1| = |x|
Просмотров 3982 месяца назад
A Special Maths Olympiad Equation |x 1| = |x|
Simplifying fractional expressions involving numbers in tetration form
Просмотров 502 месяца назад
Simplifying fractional expressions involving numbers in tetration form
How to solve Simultaneous Equations xy =50, xz = 100, zx = 200
Просмотров 1042 месяца назад
How to solve Simultaneous Equations xy =50, xz = 100, zx = 200
GH Simplification of exponential fraction without calculator
Просмотров 432 месяца назад
GH Simplification of exponential fraction without calculator
Solving the Tetration Equation ^32^x + 4^x = 6 Step by Step Explanation
Просмотров 1262 месяца назад
Solving the Tetration Equation ^32^x 4^x = 6 Step by Step Explanation
Interesting Maths Olympiad Equation x^2 9÷2016 + x^2 6÷2019 + x^2 3÷2022 = 3
Просмотров 1913 месяца назад
Interesting Maths Olympiad Equation x^2 9÷2016 x^2 6÷2019 x^2 3÷2022 = 3
A Tricky Exponential Equation 1÷8^x +1÷4^x = 80 Solved
Просмотров 4453 месяца назад
A Tricky Exponential Equation 1÷8^x 1÷4^x = 80 Solved
6 + √35
Неправильное решение, основание степени не 1,а число 5,нужно 5 возводить в степень, грубая ошибка, будет 5^[4*2*1*2*1*4*(1/4)]=5^16 Не удаляйте мой комментарий, лучше удалите свое видео, ведь вашу ошибку увидят другие, если уверены в своем решении, оставьте мой комментарий и увидите реакцию
Спасибо за ваш комментарий. В задаче 4 является показателем степени основания (5), 2 - это показатель степени для 4, 1 - это показатель степени для 2 и так далее. Таким образом, верхняя степень (2^4) упрощается, и ответ становится показателем степени 1; упрощение (2^4) дает 16, что становится показателем степени 1 (то есть 1^16), и так далее, как показано в решении.Я уверен, что решение верное.
Nice
Thanks🙏
😅
Wonderful
0 & 5
1. Indeterminate form: In calculus, 0^0 is considered an indeterminate form, meaning it cannot be assigned a definite value without more context. 2. Limit approach: Using limits, we can examine the behavior of f(x) = x^x as x approaches 0. In this case, the limit is 1, suggesting that 0^0 could be defined as 1. 3. Combinatorial interpretation*: In combinatorics, 0^0 can be seen as the number of ways to choose 0 items from a set of 0 items, which is 1. The answer 5 is correct but 0 as suggested mybe debatable. Thank you.
Well represented
Thanks
IT IS Reilly tricky
Lovely. I have llearnt something
Is this a common problem we would encounter?😢
Sometimes
❤
That's Interesting
Interesting
Thanks
At some point, I was expecting a quadratic equation, but you used the identities to avoid that. Thank you
Nice one there
Thank you
A nice approach. very educative.
squaring both sides 4xx+8xy+4yy=25xy 4xx-17xy+4yy=0 a=x/y 4aa-17a+4=0 (4a-1)(a-4)=0 a=x/y= 4 or 1/4
Nice one
🙏
=>5^(×+5)/2=5^3/× =>×+5=6/× =>×^2+5×-6=0 ×=-5+_ _/{5^2+4(6)}]/2 =(-5+_7)/2=1 or-6
Nicely displayed.
Great. Thank you.
x^15/16=125^5/8 x^15/16=5^15/8 x=5^(15/8×16/15) x=5^2 x=25
You miss the x=3, y=-1 solution arising from the fact that (-3)^4 is also 81, from which you get x/y=-3, x-y=4.
Yes Sir. I agree with you. Thank you.
That's fantastic
Thank you.
Very Educative
Very impressive bro
Tuanks
Educative
Fine one
I love this.
I love this.
I love this.
Great one
Nice ome
Thanks
So interesting
Great
Thanks
Fantastic
Thank you.
A very helpful simplification...thank you sir!
Nice equation
Thanks and welcome
Wow!
Interesting
Waaw great one
Thank you brother.
Good one there
Thank you.
Thank you.
Nice one there.
trickish
Good tutorials
Good
Interesting Maths
V good
Nice one
Fantastic
(5^4^2^1^2^4)^1/4=(5^4^2^1)^1/4 =(5^4^2)^1/4=(5^16)^1/4 =5^16/4=5^4=625
Nice
So nice
A=（19X+49）^（1/3），B=（19X-49）^（1/3）， A/B-2/B=1，A^3-B^3=98，A-2=B， A-B=2， A^2-2AB+B^2=4， A^2+AB+B^2=49， AB=15，A（- B）=-15， A，- B are root of T^2-2T-15=0，（T-5）（T+3）=0，T=5，-3， （A，B）=（5，3），（-3，-5）