- Видео 40
- Просмотров 96 809
Geoff Cantwell
Добавлен 2 фев 2013
Midpoints of quadrilateral join to form parallelogram - Proof
Midpoints of quadrilateral join to form parallelogram - Proof
Просмотров: 569
Видео
Intersecting chords theorem - proof
Просмотров 1199 месяцев назад
Topic: Circle Geometry. Geometric Proof of the intersecting chord Theorem.
Alternate Segment Theorem - Proof
Просмотров 3619 месяцев назад
A geometric proof of the alternate segment theorem. Circle geometry
12 Apps geometric sequence exam question
Просмотров 426 лет назад
This is practice exam question on geometric growth
12 Apps first order linear recurrence exam question
Просмотров 986 лет назад
12 Apps first order linear recurrence exam question
Minimum and maximum argument for a circle
Просмотров 35 тыс.6 лет назад
Minimum and maximum argument for a circle
Quadratic equation in standard form sketching the graph
Просмотров 447 лет назад
Quadratic equation in standard form sketching the graph
Quadratic equation in turning point form sketching the graph
Просмотров 2,1 тыс.7 лет назад
Quadratic equation in turning point form sketching the graph
least distance of velocity vector from a stationary point
Просмотров 597 лет назад
least distance of velocity vector from a stationary point
simplifying harder index expression by factorising
Просмотров 8969 лет назад
simplifying harder index expression by factorising
simplifying index expression by factorising
Просмотров 4439 лет назад
simplifying index expression by factorising
conditional probability using venn diagram
Просмотров 45410 лет назад
conditional probability using venn diagram
vector eqn of plane convert to cartesian
Просмотров 33 тыс.10 лет назад
vector eqn of plane convert to cartesian
This is the only argument i lose sadly
Thank you.
Thank you sir ❤
Thanks so much.
thank u👍
thanks very helpful
Vikram says thank you geoff
What if arg(z-12)
thanks sir
Thank you!!
「コンテンツを調整する必要があります」、
I have been trying to understand the process behind finding out the least and greatest value of Arg(z) using sin and tan! At least I can see it here! Well explained with funny Australian accent!
I am sooooo grateful to you for this video! It helped me a lot)
Mann, you're a legend! Couldn't find this tutorial anywhere else. God Bless You.
Thank you sir for providing explanation which is straight to the point
I hate physics
well, no, if we were using a calculator we won't be watching this video anyways. misleading title
saving the sanity of students everywhere, even years later ;-;
Holy shit, this video made this shit look so much more easier!
Wish I had watched this earlier, an almost identical question came up in my exams this week, and I had no clue how to answer it
Really helpful
great video!
thnks
Very helpful, thank you
Amazing video thanks
I have an exam today. Damn. This helps
Right!!!
God bless you
thanks you so much, i couldn't find a good explanation anywhere else. you make it sound so simple!
Thank you very much👍👍
😘🙏👳🏿♂️cheers Bub
Easy and clear. Thank you!
Not clear
So useful!!
Love from India ❤
Thankyou! Only video I could find that was simple and explained so well
Thank you very much ;)
this video is clear and to the point. very good thank you
Thank you
It is also a way to use analitic-geometry tool and find the y=mx line that is tangent to this circle. Then tan(alpha)=m
Thanks alot
That's a really good explanation. Thank you!
Very helpful.
Thanks for this, its helped me a bunch
How do you do this manually?
ruclips.net/video/I8Jt-foaIJM/видео.html&ab_channel=PolarPi Everything is in this video
First
Bro how are u it’s been 6 years
First
First again
First
What? You did Cartesian form to vector and not the other way around, hence all the dislikes.
No he didn't.
no he didn't
Asfand no he didn’t
No he didn’t
Thanks