- Видео 58
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Let's Learn Mathematics in Tamil
Индия
Добавлен 5 июн 2020
Welcome! This channel aims to lay out a good part of modern mathematics, from the ground up. It provides careful and novel treatments of a wide spectrum of mathematical topics.
A Counting Principle
In this video, we are going to count the members of the subgroup HK
Transcript:
drive.google.com/file/d/17qQzegKosAu_z0KH4CqTXbwjvvYq_ah_/view?usp=sharing
Transcript:
drive.google.com/file/d/17qQzegKosAu_z0KH4CqTXbwjvvYq_ah_/view?usp=sharing
Просмотров: 130
Видео
Product of Two subgroups
Просмотров 81Год назад
In this video, we define product of two subgroup and we prove the characterization of product of two subgroups to be a subgroup. Transcript: drive.google.com/file/d/1cHxmghN-aYtxT-V1qPE4qsIJ7ZF5xh0t/view?usp=sharing
Consequence of Lagrange's Theorem II || Tamil ||
Просмотров 90Год назад
In this video, we define Euler's Phi function, and we prove Euler's Theorem, Fermat's Theorem, every group of prime order is cyclic. Transcript: drive.google.com/file/d/1_bI8KzssguISIolDw3V1vsU5JcF2ab0d/view?usp=drive_link
Converse and Consequence of Lagrange Theorem || Tamil ||
Просмотров 94Год назад
In this video, we define order of an element of a group, and we derive some consequences of Lagrange theorem. Transcript: drive.google.com/file/d/1xNJI0uPG10rEcX4bsKLWX1624b8J_npu/view?usp=sharing
Lagrange Theorem || Tamil ||
Просмотров 160Год назад
In this video, we prove Lagrange theorem using coset and we also prove it directly. Transcript: drive.google.com/file/d/13bWBGYyR1AVP6PR6yEFYq57l-Rk9nlAC/view?usp=drive_link
Banach Fixed Point Theorem || Tamil ||
Просмотров 648Год назад
In this video, we define fixed point, contraction of a metric space and we prove the one of the major theorems of analysis called Banach fixed point theorem. Transcript: drive.google.com/file/d/1xvD8jjmjBnH3WDkUMbJaGVztcWtWGqG1/view?usp=sharing
Right Coset || Tamil ||
Просмотров 184Год назад
In this video, we define congruent relation and Right coset of a subgroup in a group G. We prove that there is a bijection between any two right cosets. Transcript: drive.google.com/file/d/193lINJLPyjMWmqAaNkZY58NOvbQkAdk7/view?usp=share_link
Creating New Subgroups from old one || Tamil ||
Просмотров 2022 года назад
In this video, we prove intersections of two subgroups is a subgroup, union of two subgroups need not be subgroup. If H is a subgroup of G, we proved that aHa^{-1} and N(H) are subgroups of G. Transcript: drive.google.com/file/d/13XJtLumr0sPsZqwpIECPjD51Yztc1iSo/view?usp=sharing
Examples of Subgroup || Tamil ||
Просмотров 2132 года назад
In this video, we give some examples of subgroups, and we also discuss about center of a group, normalizer of an element in a group. Transcript: drive.google.com/file/d/1pAYl0kjhjvU3HqYMK2MnySancKTRX3YZ/view?usp=share_link
Subgroups || Tamil ||
Просмотров 3212 года назад
In this video, we define subgroup, and we prove one characterization of subgroup.
Homomorphism of Rings || Tamil ||
Просмотров 1,2 тыс.3 года назад
In this video, we define homomorphism of Rings. We prove kernel of ring homomorphism form an ideal. We discuss some examples.
Alternative Definitions of Group II || Tamil ||
Просмотров 5843 года назад
In this video, we give some more alternative definitions of group.
Alternative Definitions of Group I || Tamil ||
Просмотров 5413 года назад
In this video, we give some alternative definitions of group
Elementary properties of groups continued || Tamil ||
Просмотров 1,2 тыс.3 года назад
In this video, we prove further properties of group.
Elementary Properties of Groups || Tamil ||
Просмотров 1,7 тыс.3 года назад
In this video, we prove some elementary properties of group.
Characterization of a Maximal Ideal in a Ring || Tamil ||
Просмотров 2,8 тыс.4 года назад
Characterization of a Maximal Ideal in a Ring || Tamil ||
Maximal ideals in a Ring || Tamil ||
Просмотров 2,7 тыс.4 года назад
Maximal ideals in a Ring || Tamil ||
Properties of compact sets in a metric space || Tamil ||
Просмотров 1,3 тыс.4 года назад
Properties of compact sets in a metric space || Tamil ||
Compact set Definition and Examples || Tamil ||
Просмотров 1,5 тыс.4 года назад
Compact set Definition and Examples || Tamil ||
Connectedness and Continuity || Tamil ||
Просмотров 1,6 тыс.4 года назад
Connectedness and Continuity || Tamil ||
Characteristic of a Ring || Tamil ||
Просмотров 2 тыс.4 года назад
Characteristic of a Ring || Tamil ||
Characterization of Connectedness || Tamil ||
Просмотров 1,2 тыс.4 года назад
Characterization of Connectedness || Tamil ||
Noise is disturbing sir
Sir innum clear ahh explain panna nalla irukkum
sir kindly verify Q is nowhere dense or not in R. in (c) Q is not nowhere in (2) Q in first category . which one is correct? Sir
Both are correct. See 5:19 for the first. For the second one, please read the previous comment.
Super ahh solli thaaringa sir😊
Really very super ..
Why are we proving U is an ideal since M is a maximal ideal?By definition we can say U is an ideal know sir
Yes, you are right, you may skip that portion.
👍👏Anna your videos very useful 🤗
Thank you so much for your teaching ❤️🤝
Nice lecture sir...thank you.. Enaku oru doubt iruku..epdi R\b=A vandichu?
Great sir....but It would be better and clear... If explained with diagram...
Thank you sir
Sir enaku doubt commutative ring with unit element um identiy yum.same ah sir
Yes... Both are same...
Clear explanation thanks
Good explain... Thanks sir
Very very useful this video sir so thank you
thank you so much sir🙏🏻
Tq sir
Sir I request you to pls upload euler's and fermats theorem .pls reply
Anna measure theory ku videos podunga
Please, I need your help in solving this proof. Can I communicate with you? I am from Iraq if M is maximal ideal of S and f is homo and onto then f inverse of M is maximal ideal of R
One can easily prove that f^{-1}(M) is a maximal ideal of R.
@@letslearnmathematicsintami3902 @EmanIbr Please contact me, I really need your help in proving some homologs with the homomorphism function
Hi, could I get your whatsapp number or e-mail? I'm an UG maths student and would like to get tutoring
Thank you sir😁
Sir this transcript notes I want sir
Theorem 3.5 la 2 sum poduga please
ruclips.net/video/_zxEFDQvaXw/видео.html
Sir what is absolute property in topology?
super sir
Super sir clear explanation tq
Bro niga which Book use panragah.
Sir,how you are saying by doing the product of AB it does not belongs to S and product of BA does and how you defining that the product of BA is of the form where ideal hold
A matrix A is in S if its second column is zero. Hence we conclude that AB is not in S and BA is in S.
Sir I like your last exam because that's example clear my all doubts,and then I was watching many videos but you told explanation that's very amazing
Sir module defintion and example pathi solunga
sir please Teach complex analysis
Sure...
Sir pg linear algebra 1 st semester sums podunga sir
Thanks ☺☺☺
Sir Q is of first category then Q can be expressed as a countable union of nowhere dense sets ,is it ?
Yeah I think it is right.
Yes. Q can be written as a countable union of single point sets. Each single point set is nowhere dense.
Vaathiyare super
👌
👌
Very helpful🥺❤
Nice lecture sir
Thank you sir
Tq so much bro
Connectedness about full details in tamil le pls help
Congrats for your efforts
Let (M, row) be a complete metric space. If T is a contradiction on M, then there is one and only one point x in M such that Tx=x. Give me the explanation for this sum sir plsss...