![Robols Math](/img/default-banner.jpg)
- Видео 153
- Просмотров 69 578
Robols Math
Филиппины
Добавлен 22 окт 2019
I’m Robols and I like doing Math on my free time. I solve Math problems or do coding stuff as I find interest in recreational/competitive math. I will be uploading lectures for certain topics that I find interesting and the ones the I often see in math competitions.
I intend to upload solution videos for select problems from Math exams and competitions. If you have any suggested content/topics to discuss, leave a comment in any of my videos or email me through robolsmath@gmail.com
Social Media Accounts:
Facebook: robolsmath
RUclips: ruclips.net/user/RobolsMath
Twitter: robolsmath
I intend to upload solution videos for select problems from Math exams and competitions. If you have any suggested content/topics to discuss, leave a comment in any of my videos or email me through robolsmath@gmail.com
Social Media Accounts:
Facebook: robolsmath
RUclips: ruclips.net/user/RobolsMath
Twitter: robolsmath
How to Scrape Facebook Comments Using Python [2024]
In this video, I discussed a method of scraping comments from any Facebook posts using Python. This is a powerful tool that can be used to manage the comments to anyone's post.
Here's the reference material: medium.com/@yassineelboustani666/scraping-facebook-comments-using-python-e8b29b025d73
#howto #tricks #python #automation #pythonprogramming #scraping #webscraping #facebookscraper #pythonforbeginners #manim #aivoiceover
Background Music:
Hopeful Freedom by Asher Fulero
AI Voiceover:
"Will" voice c/o Elevenlabs
Social Media Accounts:
Facebook: robolsmath
RUclips: ruclips.net/user/RobolsMath
Twitter: robolsmath
TikTok: www.tiktok.com/@robolsmathph
Here's the reference material: medium.com/@yassineelboustani666/scraping-facebook-comments-using-python-e8b29b025d73
#howto #tricks #python #automation #pythonprogramming #scraping #webscraping #facebookscraper #pythonforbeginners #manim #aivoiceover
Background Music:
Hopeful Freedom by Asher Fulero
AI Voiceover:
"Will" voice c/o Elevenlabs
Social Media Accounts:
Facebook: robolsmath
RUclips: ruclips.net/user/RobolsMath
Twitter: robolsmath
TikTok: www.tiktok.com/@robolsmathph
Просмотров: 51
Видео
How to Rename Multiple Files Using Python
Просмотров 3116 часов назад
In this video, I discuss a method of renaming a bunch of files inside a folder using Python. The method can be used for any file types and can be extended to not just renaming the files but managing them in general. #howto #tricks #python #automation #pythonprogramming #pythonforbeginners #manim #aivoiceover Background Music: Hopeful Freedom by Asher Fulero AI Voiceover: "Will" voice c/o Eleven...
Integral to Area Trick: Integral of square root of (-1+x)/(2-x)
Просмотров 8421 час назад
In this video, we will discuss a solution for the integral of square root of (-1 x)/(2-x). The solution involves a trick of using the area of a known geometric shape to evaluate the integral. #maths #math #calculus #integral #derivative #integration #integrationbee #mathwizard #mathtrick #manim #aivoiceover Background Music: Hopeful Freedom by Asher Fulero AI Voiceover: "Michael" voice c/o Elev...
U-Substitution Trick You Must Master (Integral of 1/(1-sqrt(x))
Просмотров 184День назад
In this video, we will discuss a solution to evaluate the integral of 1/(1-sqrt(x)) using a simple u-substitution. #math #calculus #integral #derivative #integration #mathwizard #mathtrick #IntegrationBee #manim #aivoiceover Background Music: Hopeful Freedom by Asher Fulero AI Voiceover: "Michael" voice c/o Elevenlabs Social Media Accounts: Facebook: robolsmath RUclips: ruclips.net...
A Textbook Trick to Integrate ln(1+x^2)
Просмотров 21321 день назад
In this video, we will discuss a solution to evaluate the integral of ln(1 x^2) using integration by parts (IBP). There is an interesting sequel for this one that I might do in the future so please stay tuned! 0:00 Intro 0:10 Problem 0:27 Solution #math #calculus #integral #derivative #integration #integrationbyparts #IBP #mathwizard #mathtrick #manim #aivoiceover Background Music: Hopeful Free...
A Clever Trick for This Challenging Integral
Просмотров 1,4 тыс.Месяц назад
In this video, we will discuss a solution to evaluate the integral of (x^4 1)/(x^6 1). This integral is from the 2018 UPMC Nationwide Search for the Math Wizard, and variants of this have appeared in several other collegiate math contests in the past. 0:00 Intro 0:10 Problem 0:47 Solution #math #calculus #integral #derivative #integration #mathwizard #mathtrick #manim #aivoiceover Background Mu...
Integrating a Challenging Integral Using the Reverse Quotient Rule
Просмотров 397Месяц назад
In this video, we will discuss in detail how to use the Reverse Quotient Rule to find the integral of evaluate the integral of (x^4-6x-9)e^(2x 3/x)/x^4 dx. The method used in this video was introduced and discussed in detail in my previous video. I highly recommend that you watch that video first: ruclips.net/video/8pMM_Rm2_QM/видео.html 0:00 Intro 0:10 Problem 0:24 Solution #math #calculus #in...
An Integration Technique You Probably Didn't Know: Reverse Quotient Rule
Просмотров 2,9 тыс.2 месяца назад
In this video, we will discuss in detail how to use the Reverse Quotient Rule to find the integral of (-x^2 1)/(x^2 1)^2. This is a useful technique that can be used to find the antiderivative of a ratio of two functions. Check out more integrals in this playlist: ruclips.net/p/PL6TdfPcYBiviFrEqELyk3WzAOKYtJjzy7 0:00 Intro 0:15 Main Integral 0:30 Quotient Rule for Derivatives 2:40 Reverse Quoti...
UP Math Wizard: Infinite Series
Просмотров 3192 месяца назад
This question is from the Final Round of the UP Mathematics Club Nationwide Search for the Math Wizard 2024 held in March 2024. Problem statement: Find the sum of 200/n - 100/(n 1) - 100/(n-1) from n = 2 to infinity This is a good example of finding the sum using telescoping technique. Although this problem was asked in a Collegiate Math Contest, this type of problem also appears in High School...
Solution to Your Daily Epsilon Math [Jun 4, 2024]
Просмотров 463 месяца назад
Solution to Your Daily Epsilon Math [Jun 4, 2024]
Number of Integer Solutions using Stars and Bars [2024 UPMMC MATHirang MATHibay]
Просмотров 713 месяца назад
Number of Integer Solutions using Stars and Bars [2024 UPMMC MATHirang MATHibay]
Substitution Technique for An Algebra Problem [CAS #44]
Просмотров 553 месяца назад
Substitution Technique for An Algebra Problem [CAS #44]
An Easy Way to Find the Closest Integer Without a Calculator [2024 UPMMC MATHirang MATHibay]
Просмотров 693 месяца назад
An Easy Way to Find the Closest Integer Without a Calculator [2024 UPMMC MATHirang MATHibay]
An Easy Way to Divide: Synthetic Division for Quadratic Divisors [CAS #42]
Просмотров 583 месяца назад
An Easy Way to Divide: Synthetic Division for Quadratic Divisors [CAS #42]
How to Use a Geometric Series for a non-Series Algebra Problem [CAS #41]
Просмотров 493 месяца назад
How to Use a Geometric Series for a non-Series Algebra Problem [CAS #41]
A Complex Solution to Find the Sum of Binomial Coefficients [2024 UPMMC MATHirang MATHibay]
Просмотров 1043 месяца назад
A Complex Solution to Find the Sum of Binomial Coefficients [2024 UPMMC MATHirang MATHibay]
Algebraic Manipulation and Power Reduction Method [CAS #40]
Просмотров 553 месяца назад
Algebraic Manipulation and Power Reduction Method [CAS #40]
Algebra | Easy Trick for This Sum of Cubes [CAS #39]
Просмотров 333 месяца назад
Algebra | Easy Trick for This Sum of Cubes [CAS #39]
An Incredibly Hard Sum of Cubes Algebra Problem [CAS #38]
Просмотров 503 месяца назад
An Incredibly Hard Sum of Cubes Algebra Problem [CAS #38]
Algebra | Dealing with A Ratio [CAS #37]
Просмотров 453 месяца назад
Algebra | Dealing with A Ratio [CAS #37]
Algebra | Finding abc given a + 3/b = 3 and b + 1/c = 1 [CAS #36]
Просмотров 1253 месяца назад
Algebra | Finding abc given a 3/b = 3 and b 1/c = 1 [CAS #36]
Algebra | A Slightly Hard Literal Equation [CAS #35]
Просмотров 703 месяца назад
Algebra | A Slightly Hard Literal Equation [CAS #35]
Can you evaluate this ceiling function in 30 seconds? [2024 UPMMC MATHirang MATHibay]
Просмотров 2033 месяца назад
Can you evaluate this ceiling function in 30 seconds? [2024 UPMMC MATHirang MATHibay]
Algebra Problem Involving Two Radicals [CAS #34]
Просмотров 633 месяца назад
Algebra Problem Involving Two Radicals [CAS #34]
How to deal with this Algebra problem? [CAS #33]
Просмотров 833 месяца назад
How to deal with this Algebra problem? [CAS #33]
A Likely Easy Algebra Problem [CAS # 32]
Просмотров 823 месяца назад
A Likely Easy Algebra Problem [CAS # 32]
A Simple Geometric Probability Problem
Просмотров 493 месяца назад
A Simple Geometric Probability Problem
Very Tedious Algebra Problem, or is it? [CAS #31]
Просмотров 884 месяца назад
Very Tedious Algebra Problem, or is it? [CAS #31]
Another Slightly Challenging Algebra Problem [CAS #30]
Просмотров 254 месяца назад
Another Slightly Challenging Algebra Problem [CAS #30]
Hello! Thanks for sharing. I'm doing it but in most of the cases the code print that there are no comments or just extract a low percentage of total :(
Hi! As I’ve mentioned in the video, we can only scrape up to 3000-4000 comments. If the post has much more than that, this code will not be able to scrape them all 🥹 But regardless if it’s that much, the code should be able to return a portion. If the post has comments, the code should be able to scrape them. May I see the post you are testing?
Woww i think is so difficult but it turns out it's very simple😮
Yes, it can look quite hard when you see it for the first time 🥹
2:01 What if po Sir ay hindi na-switch ang limits and stayed with a negative 2 multiplier, absolute value lang po ba ang pagkuha ng area?
Or pwede po bang gawing positive 2 multiplier and magiging quarter circle sa 4th quadrant
If hindi mo iswitch yung order the limits, magiging negative yung value ng integral. So negative times negative will still result sa positive. I suggest wag gawing habit na iforce lang na absolute value yung sagot. The sign matters 🥹
Yup, itong second suggestion mo is okay 😍
@@RobolsMath Yown. Thank you po!
Or x = tanθ
I don’t think this will help since you won’t be able to integrate the result as it is. You’ll have to use IBP for that as well. Unless I’m mistaken?
Nicely illustrated. Your work is top notch 😊
Thank you! Cheers!🍻
this trick is so impressive
Thanks!
Need more critical problems
Will do :)
Thanks
Great work.❤ Howdo you do voiceovers sir? Using TTS service or recorder service?
Thanks for the kind words. For the voiceover, I’m using Eleveabs. I tried the GTTS but it doesn’t sound human-like for the most part.
The source code please
I’m sorry, I did this months ago when I was just starting and I somehow lost it when I bought a new computer
Clear and concise. Thanks! Human voice is preferred though.
Thanks for the feedback. I currently prefer the AI voice as it’s easier for me to record this way but maybe I’ll reconsider in the future :)
@@RobolsMathUSING GTTS or Azure service?
"That's crazy" Quote by me
It is!
Excellent work. Easy to follow. Thank you 🙏
Thanks for the kind words, Chris! :)
Nice music, and very helpful. Thank you for making this video
Glad you enjoyed it!
No violent reactions, just admiration. Thank you for your videos. Keep up the good work
Thank you for the kind words. ☺️
Bangis
🔥
Excellent technique. Thank you for sharing. 😊
How to solve f(x) using differential equations method? I lost it in the deductive reasoning part 😅
Write it as y' + (-2x/(x^2+1)) y = (-x^2+1)/(x^2+1) which is a first order linear differential equation (FOLDE). Then you can proceed using standard FOLDE methods. See discussion here: tutorial.math.lamar.edu/Classes/DE/Linear.aspx I think it's gonna be a longer process though.
@@RobolsMathI got y/(x²+1) or f(x)/(x²+1), I think I'm still missing some steps haha. Linear in y multiplied by the integrating factor 1/(x²+1). The right side of the general solution is the problem itself which is pretty interesting
Ohh I rewatched and the solution makes sense to me now
Great! I fully explained my solution in the video. I thought you just wanted to know the differential equation way as an extra :)
Excellent job!
Thanks! I’ve come a long way since I did this video. I learned a lot since, but I still have a lot to learn. :)
Sir!!! AI voice reveal hehehe I wanna do this too.
AI Voiceover c/o elevenlabs. They offer free services for 10k characters per month :) You can use my referral link to sign up: elevenlabs.io/?from=partnerdaniels387
0:56
I am in so much awe…the problems you select are just 🤌! Thank you for making such good videos!
Please consider doing a Probability series, your explanations and problems that you select are too good. Thank you.
Thank you for your kind words. I’ll try to make that when I find the time :)
g(x)^2 = x^2 implies g(x) = x is a choice of g(x) xf' - f = xe^x - e^x So as f' = f then f = e^x So a solution to the integral is g(x) = e^x + C where C is the arbitrary constant of integration. I suppose that begs the question, is there something clever which uses the product rule on f(1/g)?
I'll try to explore that perspective, but I think that it's a harder path to take because there are plenty other forms that are not as easy to express in the form f'/g - f/g^2.
Thank you Robols 😊
Lakas mo idol
🥳
625
Correct! :)
I want more of these competitions. Nakaka-excite mag-aral kapag nawi-witness mo kung gaano kabilis mga math wizards.
Yes! Exciting yung mga ganitong contests. I still host similar online contests from time to time to keep the spirit alive 🔥
Good stuff
Ain’t no way I’m doing 1012 x 2025 without a calculator
That's 1012 multiplied by 3 four times, then by 5 twice.
Can’t blame you for that. The digiits are small tho so this is not really hard to do by hand 🫡
very good.i undertstanded it very well.keep up the good workkk!!!!!🎉🎉🎉🎉❤
Thank you! :)
I didn't realize that complex numbers can be a useful tool for this problem. The solution is very neatly presented!
🙏
❤
Let s=y+z-x. The given condition implies that s is nonzero. (x-y)/z = (z-s)/z = 1 - s/z (y+z)/x = (x+s)/x = 1 + s/x (z-x)/y = (s-y)/y = s/y - 1 (1-s/z) + (1+s/x) + (s/y-1) = 1 s/z = s/x + s/y Since s is nonzero, then 1/z = 1/x + 1/y Consequently, z = xy/(x+y).
Just simplify this 1/(2+a) + 1/(2+b) + 1/(2+c) and then plug in the value of abc = 4(4+a+b+c) and further simplify giving us 1/2 as the final answer.
At 4:01, it is clear that 2m=1+x-1/x = 1+m^2 > (m-1)^2 = 0 > m =1 > x-1/x = 1 > x^2-x-1=0. Also, since the RHS of the original equation is positive, x is positive. Thus, x = 1/2[sqrt(5) + 1].
Why can't for instance (a +1) = -11/3, b + 1 = 3/2 and c + 1 = 6. Ie a combination of negatives and positives?
Good question. We can’t have a positive and negative scenario at the same time because that won’t fit the given equations. For example, if a+1 is positive and b+1 is negative, then their product would be negative. However, we know from the first part that their product should be positive.
instinctively, x - (1/x) = 1 1 - (1/x) = 1/x^2 by this, 1+ (1/x) = x therefore x= phi or golden ratio
This type of solution comes with a lot of solving experience. Would you like to share how you came up with this intuition? :)
1:19 Sir, how did the b^(3a) become 1, or the (1)^3a become 1, i'm confused, please enlighten me
1 raised to any power is equal to 1. So knowing b = 1, b^(3a) means 1 raised to 3a which is equal to 1. Let me know if it’s clear. Cheers 🍻
@@RobolsMath I get it now, thanks!
Very nice video, Robols Math. Thanks for sharing. 🤴
Thank you for your kind words. 🫡
Correction: At 6:20, the number there should be -4 instead of -12. I’m not sure why I said that 😆
Təşəkkürlər gözəl həll üçün.Bakıdan salamlar.
I hope I can contribute more. Thank you for your support.
Nice job on the video, sir. You’ve clearly demonstrated a trick that everyone should know, especially if you’re planning to participate in an integral competition. I’ve seen MIT integrals and Putnam integrals based on these principles.
Thank you for the kind words :)
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Good day sir! May I ask for book recommendations for these type of competitions? Even naming just a few books is a great help. Di po ako taga luzon, interested lng po talaga ako sa mga gantong questions na diko talaga masolve kahit di rin naman ako makakasali.
I'm not familiar with books (if there are any) na dedicated para sa mga ganitong competitions. Best advice I can give you is to search online for compilations from previous Math competitions. I am not affiliated with or training any contestants so wala rin akong maayos na compilation na maiishare. If you're not a member yet, I suggest you join these Facebook groups. May mga compilations dito from other competitions which might help you. Good luck! :) Math Enthusiast Quiz Group: web.facebook.com/groups/1738335653070622 Elite Math Circle: web.facebook.com/groups/184167192600
Just to add (and self-promote), my goal for this year is to upload solutions for contest-type problems. So I hope you get to watch and learn from my videos. See you!
@@RobolsMath Thank you so much po sir! Naubos ko na po yung latest vids nyo about UPMC MathWiz andami ko pa po talagang di alam. Waiting for more vids from you sir. Sana makaupload din po kayo ng vids about Casio SpeedWhizz and MathWizz. Thank you po talaga.
I’ll be uploading 3-4 UPMC Math Wiz videos this week :)
Nice one! Liked the swinging out of the pieces that get cut in half.
Thank you for the kind words. I hope I can do content at least half as good as yours. Cheers to Manim! 🎉
Hi! Where to get past questions po ? Ty for making vid !
UPMC was not as open in distributing questions during previous Math Wizard competitions so we can only get questions from notes of participants and audience. Unfortunately, I only have limited number of questions from the past and I’m not sure if I can share them.
Hi idol! where to find copy of questions po? I can't understand the video. hindi makita ang questions at ang hirap intindihin ng audio thanks po!
For 2024 Math Wiz, the audience was allowed to take pics of the questions. Di ko sure tho kung sino ang may complete compilation nung questions if meron man. I only have pics of the questions I like and I will be posting them from time to time
I got stuck in this question because I only knew the max value of the expression. I forgot what the equality case was. pain
I understand. For different inequalities, the conditions for equality vary. That’s the advantage of the second method- the approach is the same regardless :)