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The heights of adult women are normally distributed with a mean of 63 inches and a standard deviation of 3.8 inches. What is the probability that a randomly chosen adult woman will have a height greater than 59.6 inches?

thank you so much! youre a great teacher

goated

I love you

Thank you for such a clear explanation!

Thank you for the video to help with this!!!!!

THANK YOU!

good stuff

thanks bro

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Bro your a life saver 🙌 i have a test tomorrow and this just saved me, thanks

Where did you get the 13?

Thank you SO much!

goated

what if we have a symmetric uniform distribution (i.e. same frequency in all hist. bins). Will it have larger variance than C or lower?

Thank you soo much you have helped me a lot <3333

What a terrible explanation!!After watching this explanation, I'm still confused!!😠😠😠The most annoy thing about algebra is when being given an example problem to learn from, the example problem is usually the easiest problem from that certain algebra topic. After that, I'm usually given the hardest problem of the math topic. Algebra is that one math subject whereto can solve the problem step by step correctly and still get it wrong!!!!!!

Helped me with my assignment, thank you

Thank you. I was getting really frustrated with this part of calculus.

wow very good explanation!

or you can just set the function equal to half of its limiting value, in this case 50, and solve for x. It is much simpler that way.

your video sucks!

Thank you! Very helpful video!!

thank you David! I couldn't figure out this problem on my calc homework 🤗

the worst microphone i have ever heard was too distracting to learn anything. sounds like ur driving 160mph with the windows down.

Great video; there was a small mistake at 3:42, though, when the upper bound was written down, the 4270 was changed to a 4240. As such, the correct answer to that question should be 0.8995861762.

what are you talking about? where is the problem you are working?

thank you so much

Help so much, Thank you sir

I wanna svck your đick bro 😭😭

Thank you for this video

What is the name of that calculator

i also have the question of what comes next if it is a percentage. the percentage was 19.2 and i moved the decimal over 2 places left making is .192 i may have done something wrong ive just got no clue what

thanks this is exactly what I was looking for

thank you! I'm trying to study for pre-calc and couldn't find a good video that explains with a coefficient greater than 1 and wasn't as clear and simple as yours. It helped me understand so much better

THANKYOUUUU very helpfulllllllll

Your videos are incredibly helpful! Wish the professors at my college can teach as well as you do

BRO

i dont know why i got reccomended this video, but I wish you prosperity and happiness.

How do we find median?

thank you.

thank you sooooo much!!!!!!!

thank you for yoru video. is there a function for sorting lists similar to sorta and sortd?

I've noticed something: If we write the derivative of P(t) = M/(1+Ae^(-MKt)) as dP/dt = kP(M-P), where M is the carrying capacity, the inflection point occurs when the P value is half of the carrying capacity. You can see this by taking the second derivative, which is K(MKP(M-P)-2KP^2(M-P)). Set that to zero and we can get MKP(M-P)-2KP^2(M-P) = 0. From this, we get M/2P(M-P)-P^2(M-P) = 0. This means that M/2P(M-P) = P^2(M-P). We can cancel out the M-P term, leaving us with M/2P=P^2, and therefore P=M/2. Then, just plug in the P value into the original equation to solve for t. Do you think that this method is valid?

Thank you David I was going to kms

Thanks! This came really handy

Sir more lessons on probability

THANK YOU SO MUCHHHHHHHHHH

How would I get the answer to find the probability of not spinning blue on either spin. (not blue on the first spin and not blue on the second spin). TIA

i’m typing all this step by step and some how still getting it wrong this unit is really annoying