BUETian Math
BUETian Math
  • Видео 16
  • Просмотров 1 096
Summing the series with animation
In this video, we dive deep into the derivation of a fascinating summation series formula using mathematical concepts and visualizations. Starting with a basic series, we explore the nth term and simplify it step-by-step to arrive at the final, compact expression. Using Manim, we visually represent the math, making complex ideas more accessible and engaging.
Chapters: 0:00 - Introduction 0:15 - Exploring the Summation Series 1:45 - Deriving the nth Term 3:00 - Simplifying the Expression 4:30 - Substituting Summation Formulas 7:00 - Final Formula and Conclusion
What You'll Learn:
How to break down and simplify a complex series.
Techniques to derive summation formulas.
Visual representations of ...
Просмотров: 222

Видео

Bernoulli's Theorem, the easiest way to sum series with natural number power3:11Bernoulli's Theorem, the easiest way to sum series with natural number power
Bernoulli's Theorem, the easiest way to sum series with natural number power
Просмотров 672 месяца назад
In this video, we'll dive into the easiest way to sum series with integer powers using Bernoulli's Theorem. Whether you're a student tackling series problems or just curious about the beauty of mathematics, this tutorial will guide you through the essential concepts with clear explanations and helpful animations. Learn how to approach complex series in a simplified manner and boost your problem...
Bernoulli's Theorem easiest way to sum series with integer power2:25Bernoulli's Theorem easiest way to sum series with integer power
Bernoulli's Theorem easiest way to sum series with integer power
Просмотров 932 месяца назад
Bernoulli's Theorem easiest way to sum series with integer power #maths #sum #seriesproblems #education #mathematics #series #bernoullisequation #animation #problemsolving x.com/MdAbuba72008822
If (1+z)^n=(1-z)^n then z=? With animation1:00If (1+z)^n=(1-z)^n then z=? With animation
If (1+z)^n=(1-z)^n then z=? With animation
Просмотров 2073 месяца назад
Solving for z in (1 z)^n=(1-z)^n with animation
Summing the series S_r=1^r+2^r+3^r+4^r+5^r+...+n^r with animation3:06Summing the series S_r=1^r+2^r+3^r+4^r+5^r+...+n^r with animation
Summing the series S_r=1^r+2^r+3^r+4^r+5^r+...+n^r with animation
Просмотров 254 месяца назад
S_r=1^r 2^r 3^r 4^r 5^r ... n^r=? where r is natural number
Summing the series 1^r+2^r+3^r+4^r+ ...+ n^r with animation where r is odd1:38Summing the series 1^r+2^r+3^r+4^r+ ...+ n^r with animation where r is odd
Summing the series 1^r+2^r+3^r+4^r+ ...+ n^r with animation where r is odd
Просмотров 284 месяца назад
S_r =1^r 2^r 3^r 4^r ... n^r = ? Where r is odd
Summing the series with animation 1^r+2^r+3^r+4^r+ ...+ n^r where r is even1:30Summing the series with animation 1^r+2^r+3^r+4^r+ ...+ n^r where r is even
Summing the series with animation 1^r+2^r+3^r+4^r+ ...+ n^r where r is even
Просмотров 264 месяца назад
S_r =1^r 2^r 3^r 4^r ... n^r = ? Where r is even
lim x to 0 (sinx)^tanx with animation0:33lim x to 0 (sinx)^tanx with animation
lim x to 0 (sinx)^tanx with animation
Просмотров 1584 месяца назад
lim x to 0 (sinx)^tanx
Summing the series 1^2+2^2x+3^2x^2+...+n^2x^(n-1) with animation0:29Summing the series 1^2+2^2x+3^2x^2+...+n^2x^(n-1) with animation
Summing the series 1^2+2^2x+3^2x^2+...+n^2x^(n-1) with animation
Просмотров 824 месяца назад
1^2 2^2x 3^2x^2 ... n^2x^(n-1)=?
Sum the series to n terms with animation0:46Sum the series to n terms with animation
Sum the series to n terms with animation
Просмотров 235 месяцев назад
Sum the series to n terms with animation
Easy or not easy?2:11Easy or not easy?
Easy or not easy?
Просмотров 135 месяцев назад
Solution of a hard exercise taken from higher algebra by Barnard and Child
Relation between Gamma and Beta function in easiest way5:20Relation between Gamma and Beta function in easiest way
Relation between Gamma and Beta function in easiest way
Просмотров 426 месяцев назад
Relation between Gamma and Beta function Beta(m,n)=Gamma(m)Gamma(n)/Gamma(m n)
A tricky exercise from Higher Algebra by Barnard and Child Solved6:21A tricky exercise from Higher Algebra by Barnard and Child Solved
A tricky exercise from Higher Algebra by Barnard and Child Solved
Просмотров 346 месяцев назад
Show that the roots of (1 z)^n=(1-z)^n are the values of itan(r*pi/n) where r=0,1,2,...n-1, but omitting n/2 if n is even. exercise no (11) page 68 from higher algebra by Barnard and Child
Solution of a hard exercise6:57Solution of a hard exercise
Solution of a hard exercise
Просмотров 356 месяцев назад
Solution of exercise no (v) page 39 of Higher Algebra by Barnard and Child If (1 x x^2)^n=c_0 c_1x c_2x^2 ... c_2n x^(2n) than prove that c_n =1 n(n-1)/1^2 n(n-1)(n-2)(n-3)/(1^2*2^2) ...
int 1/(x^4 sqrt(x^2-1)) dx5:13int 1/(x^4 sqrt(x^2-1)) dx
int 1/(x^4 sqrt(x^2-1)) dx
Просмотров 256 месяцев назад
"Solving a tricky integral easily: ∫(1 / (x^4 √(x^2 - 1))) dx.", int 1/(x^4 sqrt(x^2-1)) dx
int sqrt(tanx) dx5:03int sqrt(tanx) dx
int sqrt(tanx) dx
Просмотров 167 месяцев назад
int sqrt(tanx) dx