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Manikandan Institute of Physics
Индия
Добавлен 26 авг 2022
Tutorial series on Physics for class 11 and 12 for CBSE Syllabus (Theory and Practical’s)
Dr. P. Manikandan M.Sc., PhD.
Manikandan Institute of Physics
Chennai.
Dr. P. Manikandan M.Sc., PhD.
Manikandan Institute of Physics
Chennai.
Figure of Merit and Resistance of a Galvanometer by Half Deflection Method | 12 Physics Practicals
#galvanometer #figureofmerit #physics #cbse #physicspractical #cbsephysics #cbseclass12 #neet #neetphysics
12 CBSE / Electric Charges and Fields -
ruclips.net/p/PLf9qCaMDHk4-Dgwx7V4Vey2oWpaM3a72Z&si=3Kseb-aKfB47TSd5
12 CBSE / ELECTRIC POTENTIAL AND CAPACITANCE: ruclips.net/p/PLf9qCaMDHk48uJy7H_X2KU2uUQCZn1oqW
Ray Optics ruclips.net/p/PLf9qCaMDHk49xDa0mLCyQYdW2DCMfzgI2
12 CBSE / Semiconductors -
ruclips.net/p/PLf9qCaMDHk48jQn2-jervpqwJV6mUa-fs&si=zus1esVq_fH1Wp5N
12 CBSE Physics Practicals: ruclips.net/p/PLf9qCaMDHk4-POWmovAflghKZ70X48Dvt&si=KqUJKMYz2w1euvs7
Tutorial series on physics for class 11 and class 12 for CBSE syllabus.
Dr. P. Manikandan M.Sc., PhD
Manikandan Institute of Physics
Chenna...
12 CBSE / Electric Charges and Fields -
ruclips.net/p/PLf9qCaMDHk4-Dgwx7V4Vey2oWpaM3a72Z&si=3Kseb-aKfB47TSd5
12 CBSE / ELECTRIC POTENTIAL AND CAPACITANCE: ruclips.net/p/PLf9qCaMDHk48uJy7H_X2KU2uUQCZn1oqW
Ray Optics ruclips.net/p/PLf9qCaMDHk49xDa0mLCyQYdW2DCMfzgI2
12 CBSE / Semiconductors -
ruclips.net/p/PLf9qCaMDHk48jQn2-jervpqwJV6mUa-fs&si=zus1esVq_fH1Wp5N
12 CBSE Physics Practicals: ruclips.net/p/PLf9qCaMDHk4-POWmovAflghKZ70X48Dvt&si=KqUJKMYz2w1euvs7
Tutorial series on physics for class 11 and class 12 for CBSE syllabus.
Dr. P. Manikandan M.Sc., PhD
Manikandan Institute of Physics
Chenna...
Просмотров: 2 063
Видео
What is Torque ? | Singapore Science Park
Просмотров 1874 месяца назад
#torque #physics #mechanics #cbse #cbsephysics #cbsephysicspracticals
Kirchhoff's Law Numericals - NCERT Example 3.8| Current Electricity | Class 12 | CBSE, NEET & IITJEE
Просмотров 27510 месяцев назад
#kirchhoffslaw #currentelectricity #cbsephysics #physics #ncert #neet #iitjee #iitjeephysics #kirchhoff #kirchhoffslaw #currentelectricityclass12 #cbsephysics #numericals #12physics #cbseclass12 #class12physicschapter3 #class12physics 12 CBSE / Electric Charges and Fields - ruclips.net/p/PLf9qCaMDHk4-Dgwx7V4Vey2oWpaM3a72Z&si=3Kseb-aKfB47TSd5 12 CBSE / ELECTRIC POTENTIAL AND CAPACITANCE: ruclips...
Kirchhoff's Law Numericals - NCERT Example 3.6| Current Electricity | Class 12 | CBSE, NEET & IITJEE
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Kirchhoff's Law Numericals - NCERT Example 3.6| Current Electricity | Class 12 | CBSE, NEET & IITJEE
NCERT Example 3.7 - Class 12 Kirchhoff's Law Numericals - Current Electricity | CBSE, NEET & IITJEE
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NCERT Example 3.7 - Class 12 Kirchhoff's Law Numericals - Current Electricity | CBSE, NEET & IITJEE
Current Electricity - Kirchhoff's Law - Numericals - Part 1| 12 Physics | CBSE, NEET & IITJEE
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Current Electricity - Kirchhoff's Law - Numericals - Part 1| 12 Physics | CBSE, NEET & IITJEE
Ray Optics - Important Problems - Part 2 in English | 12 Physics | CBSE, NEET & IITJEE
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Ray Optics - Important Problems - Part 2 in English | 12 Physics | CBSE, NEET & IITJEE
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Parallel Plate Capacitor with Dielectrics and Capacitors in Series and Parallel | 12 Physics | CBSE
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Parallel Plate Capacitor with Dielectrics and Capacitors in Series and Parallel | 12 Physics | CBSE
Ray Optics - Important Problems - Part 1 in English | 12 Physics - CBSE, NEET & IITJEE
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Ray Optics - Important Problems - Part 1 in English | 12 Physics - CBSE, NEET & IITJEE
Capacitance and Parallel Plate Capacitor | Electrostatics |12 Physics | CBSE, NEET & IIT
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Capacitance and Parallel Plate Capacitor | Electrostatics |12 Physics | CBSE, NEET & IIT
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Dielectrics and Polarisation | Electrostatic Potential and Capacitance |12 Physics | CBSE,NEET& IIT
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Dielectrics and Polarisation | Electrostatic Potential and Capacitance |12 Physics | CBSE,NEET& IIT
Electrostatic Potential Energy of System of Charges in an External Field | 12 Physics-CBSE NEET IIT
Просмотров 108Год назад
Electrostatic Potential Energy of System of Charges in an External Field | 12 Physics-CBSE NEET IIT
Meter Bridge - Series Combination of Resistance | 12 Physics Practicals
Просмотров 8 тыс.Год назад
Meter Bridge - Series Combination of Resistance | 12 Physics Practicals
Equipotential Surface and Relation between Electric Field and Potential | 12 Physics for CBSE & NEET
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Equipotential Surface and Relation between Electric Field and Potential | 12 Physics for CBSE & NEET
Torque and Potential Energy of Electric Dipole in an External Field | 12 Physics for CBSE NEET & IIT
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Torque and Potential Energy of Electric Dipole in an External Field | 12 Physics for CBSE NEET & IIT
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Electric Potential due to Dipole | Electrostatic Potential | 12 Physics for CBSE NEET & IIT JEE
Electric Potential due to a Point Charge | Electrostatics | 12 Physics for CBSE NEET & IIT JEE
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Electric Potential due to a Point Charge | Electrostatics | 12 Physics for CBSE NEET & IIT JEE
Half and Full wave Rectifier | PN Junction Diode | Semiconductor | 12 Physics for CBSE NEET & IITJEE
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PN Junction - Forward and Reverse Bias | Semiconductor | 12 Physics | CBSE, NEET and IIT-JEE
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Electric Field due to Uniformly Charged Thin Spherical Shell | 12 Physics | Electrostatics
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Electric Field | Field due to the system of Charges - Electric Charges and Fields - Part 3
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Electric Field | Field due to the system of Charges - Electric Charges and Fields - Part 3
Very nice❤❤❤❤
@@General-z2l All the best
@@General-z2l all the best
The video was very helpful sir but can you kindly explain why we are dividing OA+OB by 4.Is there any specific reason or is it just the formula
The values of v and u are the same for point O. The coordinates of point O should be (2f, 2f), as for a convex lens, when v=2f, u=2f. (since position of object and image at centre of curvature) Therefore, OB = OA = 2f This implies that f = OB/2 and f = OA/2 Mean value of f = (OA +OB) / 4 cm
THANK YOU SIR
@@yokeshs8709 All the best
Sir you are really great now i can understand it and work it out so thank you sir
@@narutopiece9810 All the best
Very nice video sir Outstanding sir 😊❤🎉 Thank you so much 😊
@@RajeshMahato-ws9sx All the best
Pls what values of the extension (length)did u use to plot the graph.. Like on the table after finding the mean how do u get the extension pls
Extension length is nothing but (x+y)/2
Thank u so much 😊
@ all the best
thank you sir
All the best
@@manikandaninstituteofphysics i am still watching ur other videos i hav exam tmr
@ super
Thank you sir
@@SreeyaP-s6w All the best
Super sir thank you
@@Barath.M-o8h All the best
Why can't we directly measure the distance between mirror and screen??
We can measure. But to get more accurate value I am using this method R = Y-X (The image produced by the Convex lens acts as an object for the mirror)
@@manikandaninstituteofphysics Ok sir👍
Thanks sir
All the best
Sir what is the curvature of your booty
Thanks sir
@Zzzzzzzzzzzzzzzzz. All the best
Bro's intro😭🙏🏻🤣💀💀💀
thanks sir ... helped a lot for my practicals
All the best
Sir Meesai Mass sir
crystal clear sir❤
@@muthukumaresanparimalam3824 All the best
i quiet understand it well
All the best
How to take 52(x)
Thanks
@@gururajank8188 All the best
Thank you sir Very helpful at this moment ☺
All the best
romba nandri sir
@@dhyanishah-d3k All the best
Nice 👍🙂
@@pnalonegaming2329 All the best
Sir how to do for unequal weights in both sides
Same procedure
Thank you very much 🎉
@jagannathjagan3977 All the best
@manikandaninstituteofphysics Thank you sir 🧡
7:38 sir u get same side deflection (left side A ,deflection on left side )?
First i am getting right side deflection when jockey is placed near point B and then i am getting left side deflection when jockey is placed near point A. It is correct only watch the video again.
This video helped me alot... thanks for saving my practicals sir ❤
@@whitedevelgaming5495 All the best
Helpful 🤌
Thank you. All the best
Thank you sir and it is very kind of you sir 🙏
@@SiddlingappaJangannavar All the best
Thank you so much 👏🏻👏🏻👏🏻👏🏻
All the best
Awesome sir🎉
Thank you
sir why in the graphical method we divide oa+ob/4 i can't understand
That's the formula to calculate the focal length using the graph.
The values of v and u are the same for point O. The coordinates of point A should be (2f, 2f), as for a convex lens, when v=2f, u=2f. Therefore, OB = OA = 2f This implies that f = OB/2 and f = OA/2 Mean value of f = (OA +OB) / 4 cm
@@manikandaninstituteofphysics thanks sir got it now🙏
LOVE YOU SIR , I GOT 30/30 LAST MINUTE REVISION. THANK YOU SO MUCH
@@naveenraja4452 All the best
Thanks sirrrrr
Resistance is equal to slope or 1/slope?
It depends which axis you are choosing voltage and current. If you are choosing Y axis voltage and X axis current, then R = slope of the curve. ( R=V/I )
Super sir 🎉
@@arunaballa5360 Thank you
🔥🔥
Useful information 😊
❤❤❤
Sir lens formula 1/v-1/u =1/f .. but you used mirror formula sir uv/u+v. Kindly explain sir
Watch the explanation at 1.35 min of this video
Ooi
14:46 sir from where did this 4 come from
For 50g of weight we taking scale as 1cm. So, 200g take 4cm
Which place bro from which area you took the video
Royapettah Chennai
Which place bro from which area you took the video
Which place sir
@@tamilgamingdheena Singapore
Super sir❤❤
❤❤❤👍👍
Thalaiva tomorrow practicals, you saved me 🫡🙏
Thank you
Practical in 30 mins me watching now😂
@@shyamkumar.y.c do well all the best
@@manikandaninstituteofphysics sure bro Thanks
@@manikandaninstituteofphysics Bro one doubt how to find standard focal length
Explained very well sir
@@mohammedadil4372 Thanks