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Rashel's Classroom
Добавлен 18 июн 2021
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Maths Olympiad | Simply Radical maths problems | Square root maths problems |
A tricky radical maths problems. #maths #mathematics #squareroot
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Видео
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Hello everyone ,Welcome to Rashel's classroom. In this video i solve a beautiful math problem. Algebra problem. A tricky maths for competitive exams. Find the value value of X & Y? #maths #mathematics #olympaidalgebra #highermathematics
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Maths Olympiad | A Tricky Maths Olympiad Question | An Algebraic Expression |
Просмотров 1,6 тыс.21 день назад
Maths Olympiad | A Tricky Maths Olympiad Question | An Algebraic Expression |
c:26
400
(Sqrt(5))^(X+1)=125, 5^((X+1)/2)=5^3, (X+1)/2=3, X=5
-1-1-1-1🎉🎉🎉🎉
What is going on😢 I don't get it
K=5
very ugly number handwriting
Simple 150
A long way to solve a simple equation!
2^(x)*5^(x)=10^(3) log(10^(x))=log(10^(3)) log(10)=1 log10^(3)=3 x*log(10)=3 x*1=3
Solution 1-) the solution of k^3 −k^2 =100 if we assume the dots means faktor of K. Solution 2-) if in "K.K.K" and "K.K" the dots are decimal points one solution could be given an interpretation of this equation as: 1. K.K.K as a number in the format K.KK, where K is some digit, and 2. K.K as a number with just one decimal place. Wich it result in (K+K/100+K/1000)−(K+K/10)=100
台灣 國中二年級數學
Thought 2^x • 5^x=100 lel
3.
pontosabban ennyi a végeredmény: 2^100-2^99=633825300114114700748351602688
I think thé answer IS --6
2^100-2^99=6,7^29
k^3 - k^2 => k^2(k-1) => k=5
15 x 16^4 es igual, pero queda más bonito y rápido
I use logic
Whether you like it or not, your answer is incomplete without the complex roots. So you can all stop congratulating yourself in the comments about how you figured out immediately that the answer was 5, because it’s not the whole answer.
5^x-1 = 5 × 2^x-2 5^x × 5^-1 = 5 × 2^x × 2^-2 5^x × 1/5 = 5 × 2^x × 1/2² 1/5 × 5^x = 5 × 2^x × 1/4 5^x/5 = (5 × 2^x)/4 4 × 5^x = 25 × 2^x 4 × (5/2)^x = 25 (5/2)^x = 25/4 (5/2)^x = (5/2)^2 X = 2
(ab*ca)/bc=(100*300)/200,a*a=150, a=√150=5(√6) the same, b*b=200/3,b=√(200/3)=10√(2/3)=10/3(√6) c*c=600, c=√600=10√6 then you can get a+b+c=55/3(√6)
a+2ab+b=8 -> {a+b)^2=8^2 -> a+b=+-sqrt(8)
It should be a^2+2ab+b^2 to do so
You are blocked for not mentioning that the numbers were integers and wasted my time!
You can do that.
O K.
5
How about 4^x+4^x=16 2(4^x)=16 4^x=8 xlog4=log8 x=log8/log4 x=log2^3/log2^2 x=3log2/2log2 x=2/3
26
I did it in 3 seconds
😊
7/3
❤❤❤🎉 thank you 👍
Are you stupid?
C=26
worst, is the person dumb or he thinks viewers are all dumb
😮awesome 👌 ❤🎉
this guy would not have made it imtui Harvard, he couldn't do 16^4 * 15? really?
X=3
1+25=26
Did you make this quetion by yourself?, If yes, you made math less intetestimg.
I solved it in my mind. k=5
It so easy for me. It s your easy exercise. 😂. I like complex exercise
16^4 (16-1) = 256x256 x15
I solved it suddently thinkig which square could be added to 100 to have a cube
2 in R.
lg7/lg2.
The bases are different so 3x-7=0😊
superb