Видео

Here is an example of a 8x8 self orthogonal Latin square: 0 4 6 2 7 3 1 5 5 1 3 7 2 6 4 0 4 0 2 6 3 7 5 1 1 5 7 3 6 2 0 4 3 7 5 1 4 0 2 6 6 2 0 4 1 5 7 3 7 3 1 5 0 4 6 2 2 6 4 0 5 1 3 7

Sorry. Poor presentation 😢

First! Also love your course notes, animations are cool!

THE RHOMBIC DODECAHEDRON NESTS THE CUBE, THE RHOBIC DODECAHEDRON FITS INSIDE A HEXAGON & HEXAGRAM STAR, I LEARNED THIS FROM 4 SHASHIBO CUBES. THE REGULAR DODECAHEDRON DOESN’T FIT IN A NATURAL HEXAGON SHAPE.

Very good video !

Now do size 8!

Uh, where do we start on the playlist?

Thank you🙌

Very nice!

2 frizbees. Floats , looks like a boat .

equation 3 ? i really cant understand how n! ended having k's in it !!!!

I cant seem to find the pylance extension unfortunately

hei, nice video. i love ur explanation ❤❤

Thank you from Jordan for this wonderful explanation, especially with its translation into Arabic 🌹

what program are you using

Hi Prof StrickLand. Nice to see you on RUclips.

Still have same though to ask. Thank you for your video. Please let me know your thinking

Thank you!! May I ask, is there any more sophisticate method for subdivision the tetrahedron into more of regular or irregular tetrahedrons? Or could there be only 24 maximum tetrahedrons from having 6 such dividing planes?

THANK YOU!!

Thank you, very informative video!

damped pendulum?

Explicitly writing out t in that way might be a bit tedious. I think the following might work and save us from having to do that computation: Let r(x) = x + t(x-f(x)) with t > 0 such that ||r(x)||^2 = 1 (Note that this constraint fixes t). It follows that 1 = ||x||^2 + t^2||x-f(x)||^2, implying t = \sqrt{1-||x||}/|| x - f(x)||. Clearly r(x) is well defined continuous etc. If x is on the boundary of B^n then ||x|| = 1 and so t = 0 yielding r(x) = x. Therefore $r$ defines a retraction onto the boundary.

I understood nothing 😂

Nice!

for me, the best algebric topology lecture for bring the formal explanation about the inclusion maps.

ruclips.net/video/tz3QWrfPQj4/видео.html

Thanks for this video! :)

good stuff

Very simple and elegant way of solving rooks polynomial. Thanks a lot.

thanku

Thank you that was helpful.

thank you sir

you should get your throat checked out, this was sooo hard to listen to with you coughing so often

This proof is wrong! the last equality isn't correct because you have 1/(n-k-1)! wich it's equal to (n-k)/(n-k)! not only to 1/(n-k)! so please be careful with the role as a teacher mr.

And your point is / was, as not being in the text books ?! - My point being: I do not like textbook to video copiers, be original : I had to set play back speed to 1.75! and I still got bored. - Be so kind and stop making RUclips videos and go play with your dodecahedron-zillion-quadrilion models, make some new posters, or rewatch some of your British SciFi, like Blake's Seven. - Bye!

Source code for the graphics*

Source code for the visualizer?

You were too fast on the last part would love for you to slow down and explain how you getting the combinations

Thank you, professor!

what software did you use? can you please tell me and where can I find the documents that you describe here?

Hi, Places, Could you tell me any software did you used to plot these phases portraited? Can I get the code?

Hi, I'm sorry but can I send an exercise of topology.? I couldn't solved it in exam but he will ask me to solve it on Monday

Are you writing backwards from your pov

Thank you for this video!

Awesome video ! Great intro explaining all of the equalities very clearly.

Sir there is one example in collin adam book chapter 4 example 4.13 sir please explain at

Where do we get the application being used?

What is z ??

Boring and mindless. Thanks for nothing.

insufficient explanation, rushed!