Видео

My plan is to start from first week of September.

Any current source (dependent or independent) in parallel with an impedance (resistor, capacitor or inductor) can be transformed to a voltage source in series with this impedance.

@@electrical4everyone Dear Sir, so the equivalent voltage source would be j16Vo ? if i'm not wrong? Will we take impedance angle into account? or is it gonna be just 16Vo?

You are welcome

You are welcome

In the current equation, it will always converge but if we change the formula from 0.7sin(x) to 1.5sin(x), the partial derivative will be higher than 1 and hence it will not converge.

@@electrical4everyone Thank you Professor. Allah bless you

Sure you can do that, but we are trying to apply numerical method techniques because the RTD can have higher order polynomial, and hence it will be harder to solve it using simple mathematical formula. Also, it is important to compare numerical solutions with closed form ones to check the correctness of the numerical approach.

You are welcome

Vgs is the voltage between the gate and the source and the source is not grounded and hence there is a voltage drop between the source and the ground which is equal the current source (gm*Vgs) and the resistance Rs. This is why we need to do this modification.

It will depend on the elasticity of the spring, and not just the applied force and this is the example I used to describe why if you apply the same voltage to two different materials with different dielectric constants will have different stored energy.

Secondly, for the part (e) it is kinda tricky to apply assumption on two BJTs and solve using KCL could you help with the answer for this.

For part (e), my calculations show Q2 to be in active mode and Q1 to be in cutoff mode, my question here is if we have cuttoff mode that means Ic is zero if Ic is zero then I think we have Vc1 as 5V. When you have time can you confirm.

@@HaiderAli-rm6rd Hi, I will try to solve these two questions in couple of weeks as currently I'm on vacation.

You are welcome

Hi Kindly send to me an email with your request and I will respond to you.

@@electrical4everyone I just. sent you an email, thank you!

For the generator we do not specify if the generator is over or under excited. We just specify the load power factor.

@@electrical4everyone Hi professor, so is it the opposite if we talk about the synchronous machines instead of the synchronous generator?

You mean synchronous motors and yes the motor is opposite to the generator.

Q6 is about Laplace application. As an advice it will be better to concentrate on the other 5 questions as they belong to fundamentsl of circuits. Laplace is considered an advance topic. Nevertheless, I will try to solve this question.

@@electrical4everyone Thank you professor. Understood and really thank you so much for your advice. A1 and A6 seems still easy to pick up......But B7 is much more difficult, especially we do not know the question type after 2019......Seems the PEO has made the exam much more difficult than the undergraduate exam ~

You are welcome, if you have any feedback to improve the content, please let me know.

Secondly, is the newtow raphson method sufficient to solve all type of questions of this nature.

The plan is to start B7 early September. I will provide videos to describe the theory for each question and then solve questions about this topic.

Yes NR can solve any load flow question

Thank you for your feedback, you are right, I added the correction in the video description

Thank you for your feedback, you are right, I added the correction in the video description

At t=0 the inductor will maintain the same current just before the switch move. So it will be modeled as a current source

Yes I can, what is your email?

cos(x) = cos(-x), so both equations are correct.

To select a loop for a kvl you need to avoid any current source in that loop. So for loop 2 I took the most outer loop. I could take the loop without the last branch

Thanks for the correction, you are correct. I wrote a correction in the video description.

@@electrical4everyone Salam alaykom Dr, Thank you so much for perfect teaching. is Voc 80.94<67.49 ?

Hi Professor, I believe Zth=8.544-j0.04, can you double check please?

Hi, I1 is already given to you, so, you only have two unknowns, I2 and I3, You need only to apply 2 KVL equations in loop 2 and loop 3

If you use rms as input sources then all voltages and current you calculate is rms and if the input is peak then every thing is peak. We usually use the rms for power calculation questions.

I have noticed the samething in the second example as well. I think I have not ignored the -ve sign with Vin for the negative waveform that is why the difference in the output wave form

Done, here is the link: ruclips.net/video/KD2lYM-9Rrs/видео.html

@@electrical4everyone Thank you very much!!

@@isandipp You are welcome

You are welcome

You may use nodal analysis, you will have 3 nodes with unknown voltages and you need to create 3 equations to solve for these 3 node voltages

You are welcome

Hi Thanks for your nice words. I have playlists in my channel for: A5: electronics A6: power system and machines B7: power system analysis. Unfortunately, I do not have background for A4.

Jazak Allah khair for your nice words.

You are welcome

This is in my plan hopefully this week.

@@electrical4everyone Thanks. I also wanted to know if you have any plans in the future to cover topics related A5 (Electronics) or a guide on what topics need to covered for A5.

@HaiderAli-rm6rd I already have one playlist about A5 ruclips.net/p/PLDkq31epwdjx_ALhPPYEv4E6RdYSbIDYq&si=823FqGX55bH_xa0l

@@electrical4everyone Thanks Professor. I will go through it first. I just found it in the playlists as well.

I will do that soon in cha Allah

Hi I just solved one question about transient analysis containing both a capacitor and an inductor. Here is the link: ruclips.net/video/smw5N8GS8fM/видео.html

@@electrical4everyone Thank you so much. This is really helpful.

You are welcome. Any other question you want me to solve? I will solve first order transient but with inductor

I think you have already solved such an example in this video ruclips.net/video/ULX07oCptL0/видео.htmlsi=kPFKQYVGlnwqBT4C but if you find any different or slightly tricky example, please add a video for it when you are able find sometime. I think your playlist for A1 covers essentially all different types of questions

@@HaiderAli-rm6rd but it was not a peo question

JAK for your nice words

هذا من فضل الله وحده

Thanks for your feedback, I added the correction to the video description.

100hp is the motor name plate value. Pout is the actual output power at the given conditions that may or may not match with the name plate values.

The losses we have in the short circuit test is done on a different side of the transformer, so there is a^2 = 4 factor different between the two losses.

Correct, this will be the phase current in the supply.