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this is so under rated wth

But mark scheme for q2 i said 0 is an answer

how did you get k < 0 and not k > 0 in 1:03:56

i just want o say thank you so much. Learning with you has been a real pleasure.

Great explaination but you could talk a bit faster

i do not undestad why in question 8 it is ax. Shouldnt it just be x since we know x=o

AAA chemical engineering at university of bath

thank you so much for this video you legend, your soft spoken voice is very soothing for maths. keep it up!! 🙏🙏🔥🔥

I got 2 A* and 1 A, which was in maths. I am planning on doing a degree apprenticeship for electro-mechanic engineering in Warwick uni and a company called GE. Thanks for all the videos, it helped me alot!

48:45 just a head up instead of -488/3 the right value is -448/3 so the final answer is 1736/3. I found your video very helpful thanks.

How to type : when jacoobi and gaus siddle methods in 991cw

also, how do you know where the shape starts from? q7

lol me thinking 6/.5 =3...

What is this

Anyone got the 2024 paper/answers yet? I want to check my answers

29:12 using the sine rule here would be easier.

Couldn't have dropped this video at a better time thank you! Where did you find this paper?

44:04 - you got -448/3 on your calculator but you wrote -488/3

I somewhat agrees these guys but you’re doing a good job. These kinds of videos always help just not some people. Like sometimes you don’t get the mark scheme and just easier when someone explains.Also when your cramming the night before like 100 paper this help ALOT

31:37 why is it bigger than on the left hand side not bigger than and equal to?

For question 3, why don’t we consider 3, 3 twice?

2:33 can anyone explain why its negative g becuase isnt it going up and then down so how can it be negative?

Your answer for k in question in 8B still lies outside the range of acceptable k values according to the mark scheme. However, I think the mark scheme is wrong; the upper limit of 0.167 is ridiculously large.

U speak in slow motion 😭😭😭, appreciate vid though

34:53 Hi, sorry. Small correction, but 23/100 x 600 is actually 13.8 minutes (14 minutes rounded by the nearest minute). So the correct answer is actually 13:14 pm.

for question 5 I tried doing it another way but it did not work, could you tell me where I am going wrong. work out time for horizontal to reach 50m (100/square root 2 U). then substituite that T value in V= U + at with v=0 (as at greatest height the vertical velocity=0) U= Usin45. a= -9.8 I don't understand why I get a different value of 31 instead of 28

for question 4d, i used CR method instead, which meant my answer for part e was slightly differen,t is this ok?

thanks for this!

1:35:19 how come for the Dijkstra you are starting from Node A? I thought we were meant to find F to G?

Thank you so much

ty

this was such a helpful video! thank you

Thanks dude very helpful

bros handwriting is the cleanest in all the land

hi, please could you make of these for the 2023 paper? thank you!!

Explain more

atleast explain what your talking about and how to do it

Hey man, wasn't sure about the last question and came to this vid in which you clearly explained it, appreciate the help

Can you explain as well like every answer you go through you don’t even explain how you answer them what kind of teaching is that?

This video is extremely confusing

For Q10 you put '9.852...' into your calculator when it should be '9.8052...'. The answer should be 2.53 instead of 2.52. Apart from that, thank you so much for this video. It's very helpful and making me feel confident for my GCSE next week :)

How do you know what suvat formula to use? For example in q1 c we have all the values to use s=(v+u/2)t but when I substitute the same values that you used I get something different. Thanks so much for the video btw!!

For question 1bi) why can't you have n=0 as the smallest value?

At 36:21, I don’t understand why we divide through by a? I thought that equating coefficients here shows a is 1

Yes, at last someone who does these papers. Thank you

horrific watch

Hello do you have a link to this paper please?

for 3c why do we calculatre the probabilty of 10 at the start?