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great explanation of the topic. you earned my subscription sir

Thanks so much for the great instruction!! I was looking for a way to find the turning points without using derivatives. But why does that method work? How does writing the function as a quadratic, setting its discriminant to be at least zero, and solving for y give you the y-coordinates of the turning points?

Cool am learning plz more

anyone has the full set of paper?

how can i do it without a graphing calculator

thank you good video👍

Nice video. Thanks!!

Best explanation 😊

The key cocept is not working

11:07 I think the answer should be -4<x<4

BEST TEACHER. TYSM

😊

You have been really helping me out !!!!!!!🎉🎉🎉🎉🎉

Thank you for this video

thanks

We should work together to grow quicker on YT. Up for a collaborative approach?

Thank you

V gud sir

Nice

Thnku so much sir

Hello sir. Just wanted to say thank you for these videos; they are very helpful.

Thanks

I have finals on Monday. This was super helpful! Please post more of such useful content for us AA hl students.

YOU ARE A GOD THAANK YOU

you're underated. keep up the good work!

Thank you so much!!! Super clear and helpful 😄

is this in 0607 math igcse syllabus

sir ive doubts in transformations a bit so if u have made a video on it, can u please share the link :DD

thank you so much sir, this is extremely helpful :D

Good luck Yogendra!

Commendable job Yogi

awesome

I love these videos sir you desreve more viewss

Thanks alot 🙌🙌

Hi, I'm a little confused. Shouldn't it be 1 - 4a >0? Why is it 1 + 4a > 0?

Very nice!

great thanks u

very cool concept

PrO tEaCheR

ez

thanks a lot

OMG thank you

wow bhai

problem akta hoicilo oita solve hoye gece video ta dekhar por thank u very much tnx a lot 😇😇😇😇😇😇 tnx tnx tnx😊😊

Just amazing, you deserve more likes and subscribers

NICE VIDEO Helped me understand the concept :)

wow, thank you so much!!!